Paper has been added to Favourites!
Mathematics (Core)
Paper 1 | Objectives | 48 Questions
WASSCE/WAEC MAY/JUNE
Year: 1993
Level: SHS
Time:
Type: Question Paper
Answers provided
FREE
No description provided
Feedbacks
This paper is yet to be rated
Paper has been added to Favourites!
Paper 1 | Objectives | 48 Questions
WASSCE/WAEC MAY/JUNE
Year: 1993
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Tips to make the best study space and quality time for studies are essential.
Scholarship in Norway universities are open for application in 2022 also for developing countries.
A guide to passing your exams without studying hard, how to pass any test and top your class
| # | Question | Ans |
|---|---|---|
| 1. |
S = {1, 2, 3, 4, 5, 6}, T = {2,4,5,7} and R = {1,4, 5}, and (S∩T) ∪ R A. {1, 4, 5} B. {2, 4, 5} C. {1, 2, 4, 5} D. {2, 3, 4, 5} E. {1, 2, 3, 4, 5}
Show Content
Detailed SolutionS = {1, 2, 3, 4, 5, 6}; T = {2, 4, 5, 7}; R = {1, 4, 5}(S∩T) ∪ R = {2, 4, 5} ∪ {1, 4, 5} = {1, 2, 4, 5} |
|
| 2. |
Simplify: \(\frac{3}{4} \div 1\frac{1}{4} \times (1\frac{1}{2} - \frac{2}{3})\) A. 7/30 B. 7/24 C. 9/25 D. 1/2 E. 18/25
Show Content
Detailed Solution\(\frac{3}{4} \div 1\frac{1}{4} \times (1\frac{1}{2} - \frac{2}{3})\)\(\frac{3}{4} \div \frac{5}{4} \times (\frac{9 - 4}{6})\) = \(\frac{3}{4} \times \frac{4}{5} \times \frac{5}{6}\) = \(\frac{1}{2}\) |
|
| 3. |
Solve the inequality: 3m + 3 > 9 A. m > 2 B. m > 3 C. m>4 D. m>6 E. m>12
Show Content
Detailed Solution3m + 3 > 93m > 9 - 3 3m > 6 m > 2 |
|
| 4. |
Convert 89\(_{10}\) to a number in base two. A. 1101001 B. 1011001 C. 1001101 D. 101101 E. 11001
Show Content
Detailed Solution\(89_{10}\)\(89_{10} = 1011001_{2}\) |
|
| 5. |
A stick of length 1.75m was measured by a boy as 1.80m. Find the percentage error in his measurement A. 27/9% B. 26/7% C. 5% D. 277/9% E. 284/7%.
Show Content
Detailed Solution% Error = Error /Actual measurement x 100/1 =
0.05/1.80
|
|
| 6. |
The nth term of a sequence is given by (-1)\(^{n-2}\) x 2\(^{n-1}\). Find the sum of the second and third terms. A. -2 B. 1 C. 2 D. 6 E. 12
Show Content
Detailed Solutionwhen n = 2(-1)\(^{n-2}\) 2\(^{n+1}\) = 2 When n = 3 (-1)\(^{n-2}\) 2\(^{n+1}\) = -4 Sum = 2 - 4 = -2 |
|
| 7. |
Simplify: \(\frac{4^{-\frac{1}{2}} \times 16^{\frac{3}{4}}}{4^{\frac{1}{2}}}\) A. 1/4 B. 0 C. 1 D. 2 E. 4
Show Content
Detailed Solution\(\frac{4^{-\frac{1}{2}} \times 16^{\frac{3}{4}}}{4^{\frac{1}{2}}}\)= \(\frac{16^{\frac{3}{4}}}{4^{\frac{1}{2}} \times 4^{\frac{1}{2}}}\) = \(\frac{(2^4)^{\frac{3}{4}}}{4^{\frac{1}{2}} \times 4^{\frac{1}{2}}}\) = \(\frac{2^3}{4}\) = 2 |
|
| 8. |
Simplify: \(\frac{\log \sqrt{27}}{\log \sqrt{81}}\) A. 1/6 B. 3/8 C. 1/2 D. 3/4 E. 6
Show Content
Detailed Solution\(\frac{\log \sqrt{27}}{\log 81}\)= \(\frac{\log \sqrt{3^3}}{\log 3^4}\) = \(\frac{\log 3^{\frac{3}{2}}}{\log 3^4}\) = \(\frac{\frac{3}{2} \log 3}{4 \log 3}\) = \(\frac{\frac{3}{2}}{4}\) = \(\frac{3}{8}\) |
|
| 9. |
Factorize the expression 2s\(^2\) - 3st - 2t\(^2\). A. (2s - t)(s + 2t) B. (2s + t)(s - 2t) C. (s + t)(2s - 1) D. (2s + t)(s -t) E. (2s + t)(s + 2t)
Show Content
Detailed Solution2s\(^2\) - 3st - 2t\(^2\)= 2s\(^2\) - 4st + st - 2t\(^2\) = 2s(s - 2t) + t(s - 2t) = (2s + t)(s - 2t) |
|
| 10. |
Solve the equation x\(^2\) - 2x - 3 = 0 A. (-3, 1) B. (-1, -3) C. (3,1) D. (43, 0) E. (-1, 3).
Show Content
Detailed Solutionx\(^2\) - 2x - 3 = 0x\(^2\) - 3x + x - 3 = 0 x(x - 3) + 1(x - 3) = 0 (x + 1)(x - 3) = 0 x = (-1, 3) |
Preview displays only 10 out of the 48 Questions