Paper 1  Objectives  49 Questions
WASSCE/WAEC MAY/JUNE
Year: 1996
Level: SHS
Time:
Type: Question Paper
Source: Nigeria
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#  Question  Ans 

1. 
The 6th term of a G.P is \(\frac{2}{27}\) and its first term is 18. What is the common ratio? A. ^{1}/_{2} B. 1/3 C. 1/4 D. 2 E. 3
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Detailed Solutiona, ar, ar\(^2\), ar\(^3\), ar\(^4\), ar\(^5\)6th term = ar\(^5\) = \(\frac{2}{27}\) 1st term = a = 18 => ar\(^5\) = 18r\(^5\) =\(\frac{2}{27}\) r\(^5\) = \(\frac{2}{27 * 18}\) → \(\frac{1}{27 * 9}\) r\(^5\) = \(\frac{1}{243}\) r = \(^5\)√[\(\frac{1}{243}\)] r = \(\frac{1}{3}\) 

2. 
Convert the decimal number 89 to a binary number A. 101101 B. 111001 C. 1001001 D. 1001101 E. 1011001
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Detailed Solution89\(_{10}\) = 1011001\(_{2}\) 

3. 
Simplify: \((2\frac{1}{6}  1\frac{2}{3}) \div 2\frac{2}{3}\). A. 3/16 B. 7/16 C. 1 13/24 D. 2 11/24 E. 10 2/5
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Detailed Solution\((2\frac{1}{6}  1\frac{2}{3}) \div 2\frac{2}{3}\)= \((\frac{13}{6}  \frac{5}{3}) \div \frac{8}{3}\) = \(\frac{3}{6} \times \frac{3}{8}\) = \(\frac{3}{16}\) 

4. 
Simplify 56x\(^{4}\) \(\div\) 14x\(^{8}\) A. 2x^{12} B. 3x^{3} C. 4x^{4} D. 4x^{3} E. 4x^{4}
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Detailed Solution\(56x^{4} \div 14x^{8}\)= \(4x^{ 4  (8)}\) = \(4x^{4}\) 

5. 
Simplufy Log_{10}4 + Log_{10}25 A. 1 B. 2 C. 3 D. 4 E. 5
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Detailed SolutionLog_{10}4 + Log_{10}25 = Log_{10}(4 + 25)= Log_{10}100 = Log_{10}10^{2} = 2Log_{10}10 = 2 x 1 = 2 

6. 
A boy measured the length and breath of a rectangular lawn as 59.6m and 40.3m respectively instead of 60m and 40m. What is the percentage error in his calculation of the perimeter of the lawn? A. 10% B. 1.4% C. 7% D. 0.2% E. 0.1%
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Detailed SolutionLength = 59.6mBreath = 40.3m Perimeter = (59.6m + 40.3m) x 2 = 99.9 x 2 = 199.8m Actual measurement Perimeter = (60 + 40) x 2 = 100 x 2 = 200m Error = 200m  199.8m = 0.2 Error =0.2/200 x 100/1 = 0.1% 

7. 
Find the 9th term of the arithmetic progression 18, 12, 6, 0, 6 ......... A. 54 B. 30 C. 30 D. 42 E. 66
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Detailed Solution18, 12, 6, 0, 6, 12, 18, 24, 309th term = 30 

8. 
Expand (2x  5)(x  3) A. x^{2}  1x 15 B. 2x^{2}  11x + 15 C. 2^{2}  5x  8 D. x^{2}  5x  15 E. 2x^{2}  6x + 15
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Detailed Solution(2x  5)(x  3)2x\(^2\)  5x  6x + 15 2x\(^2\)  11x + 15 

9. 
Simplify: \(\frac{5}{x  y}  \frac{4}{y  x}\) A. 9/x  y B. 9/y  x C. 1/x  y D. 1/y  x E. y  9x/x  y
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Detailed Solution\(\frac{5}{x  y}  \frac{4}{y  x}\)= \(\frac{5(y  x)  4(x  y)}{(x  y)(y  x)}\) = \(\frac{5y  5x  4x + 4y}{(x  y)(y  x)}\) = \(\frac{9y  9x}{(x  y)(y  x)}\) = \(\frac{9(y  x)}{(x  y)(y  x)}\) = \(\frac{9}{x  y}\) 

10. 
If 3p  q = 6 and 2p + 3q = 4, find q A. o B. ^{1}/_{2} C. 2/3 D. 1 E. 3^{3}/_{7}
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Detailed Solution3p  q = 6 ........ 12p + 3q = 4 ....... 2 Multiply eqn 1 by 3 9p  3q = 18 ........ 3 2p  3q = 4 ......... 2 Add eqn3 and eqn2 11p = 22 => p = ^{22}/_{11} = 2 Substitute for p =2 in eqn1 3p  q = 6 3x2  q = 6 => 6  q = 6 => q = 6  6 q = 0 
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