Paper 1  Objectives  40 Questions
JAMB Exam
Year: 2020
Level: SHS
Time:
Type: Question Paper
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#  Question  Ans 

1. 
Evaluate (212)\(_3\)  (121)\(_3\) + (222)\(_3\) A. (313)\(_3\) B. (1000)\(_3\) C. (1020)\(_3\) D. (1222)\(_3\)
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Detailed SolutionEvaluate (212)\(_3\)  (121)\(_3\) + (222)\(_3\)(212)\(_3\) + (222)\(_3\) = 1211\(_3\) → 1211\(_3\)  121\(_3\) = 1020\(_3\) There is an explanation video available below. 

2. 
Factorise (4a + 3) \(^2\)  (3a  2)\(^2\) A. (a + 1)(a + 5) B. (a  5)(7a  1) C. (a + 5)(7a + 1) D. a(7a + 1)
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Detailed Solution[(4a + 3) \(^2\)  (3a  2)\(^2\) = a\(^2\)  b\(^2\) = (a + b) (a  b)= [(4a + 3) + (3a  2)] [(4a + 3)  (3a  2)] = [4a + 3 + 3a  2] [4a + 3  3a + 2] = (7a + 1)(a + 5) (a + 5) (7a + 1) There is an explanation video available below. 

3. 
Find all median of the numbers 89, 141, 130, 161, 120, 131, 131, 100, 108 and 119 A. 131 B. 125 C. 123 D. 120
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Detailed SolutionArrange in ascending order89, 100, 108, 119, 120,130, 131, 131, 141, 161 Median = \(\frac{120 + 130}{2}\) = 125 There is an explanation video available below. 

4. 
Find all real number x which satisfy the inequality \(\frac{1}{3}\) (x + 1)  1 > \(\frac{1}{5}\)(x + 4) A. x < 11 B. x < 1 C. x > 6 D. x > 11
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Detailed Solution\(\frac{1}{3}\) (x + 1)  1 > \(\frac{1}{5}\)(x + 4) = \(\frac{x + 1}{3}  1\) > \(\frac{x + 4}{5}\)\(\frac{x + 1}{3}  \frac{x + 4}{5} 1\) > 0 = \(\frac{5x + 5  3x  12}{15}\) 2x  7 > 15 2x > 22 = x > 11 There is an explanation video available below. 

5. 
Reach each number to two significant figures and then evaluate \(\frac{0.02174 \times 1.2047}{0.023789}\) A. 0 B. 0.9 C. 1.1 D. 1.2
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Detailed Solution\(\frac{0.021741 \times 1.2047}{0.023789}\) = \(\frac{0.0255 \times 1.2}{0.024}\) (to 216)= \(\frac{0.0264}{0.024}\) = 1.1 There is an explanation video available below. 

6. 
Four boys and ten girls can cut a field first in 5 hours. If the boys work at \(\frac{5}{4}\) the rate at which the girls work, how many boys will be needed to cut the field in 3 hours? A. 180 B. 60 C. 25 D. 20
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Detailed SolutionLet x rep. numbers of boys that can work at \(\frac{5}{4}\) the rate atwhich the 10 girls work For 1 hrs, x boys will work for \(\frac{\frac{1}{5} \times 10}{4}\) x = \(\frac{5}{4}\) x 10 = 8 boys 8 boys will do the work of ten girls at the same rate 4 + 8 = 12 bous cut the field in 5 hrs for 3 hrs, \(\frac{12 \times 5}{3}\) boys will be needed = 20 boys. There is an explanation video available below. 

7. 
What is the circumference of latitude 0\(^o\)S if R is the radius of the earth? A. cos \(\theta\) B. 2\(\pi\)R cos \(\theta\) C. R sin \(\theta\) D. 2 \(\pi\) r sin \(\theta\)
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Detailed SolutionCircumstances of latitude 0\(^o\)s where R is the radius of the earth 2\(\pi\)r cos \(\theta\)There is an explanation video available below. 

8. 
A room is 12m long, 9m wide and 8m high. Find the cosine of the angle which a diagonal of the room makes with the floor of the room A. \(\frac{15}{17}\) B. \(\frac{8}{17}\) C. \(\frac{8}{15}\) D. \(\frac{12}{17}\)
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Detailed SolutionABCD is the floor. By pathagorasAC\(^2\) = 144 + 81 = \(\sqrt{225}\) AC = 15cm Height of room 8m, diagonal of floor is 15m Therefore, the cosine of the angle which a diagonal of the room makes with the floor is EC\(^2\) = 15\(^2\) + 8\(^2\) cosine \(\frac{adj}{Hyp} = \frac{15}{17}\) EC\(^2\) = \(\sqrt{225 + 64}\) EC = \(\sqrt{289}\) = 17 There is an explanation video available below. 
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