Paper 1  Objectives  41 Questions
WASSCE/WAEC MAY/JUNE
Year: 1988
Level: SHS
Time:
Type: Question Paper
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#  Question  Ans 

1. 
Evaluate (101.5)^{2}  (100.5)^{2} A. 1 B. 2.02 C. 20.02 D. 202 E. 2020
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Detailed Solution(101.5)^{2}  (100.5)^{2};(101.5 + 100.5)202 x 1 = 202 

2. 
Express the product of 0.06 and 0.09 in standard form A. 5.4 * 10^{1} B. 5.4*10^{2} C. 5.4*10^{3} D. 5.4*10^{2} E. 5.4*10^{3}
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Detailed Solution0.06 x 0.09 = 0.0054= 5.4 x 10^{3} 

3. 
Simplify 36\(^\frac{1}{2}\) x 64\(^\frac{1}{3}\) x 5\(^0\) A. 0 B. 1\24 C. 2/3 D. 1^{1}/_{2} E. 7^{1}/_{2}
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Detailed Solution36\(^\frac{1}{2}\) x 64\(^\frac{1}{3}\) x 5\(^0\)= \(6 \times \frac{1}{4} \times 1\) = \(1\frac{1}{2}\) 

4. 
Find the 8th term of the A.P 3, 1, 1 ...... A. 13 B. 11 C. 8 D. 11 E. 17
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Detailed SolutionU_{n} = a + (n1)d= 3 + (8  1)2 = 11 

5. 
A group of students took a test and the following frequency table shows the scores above A. 2 B. 3 C. 4 D. 5 E. 7
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Detailed SolutionThe mode=4. It has the highest frequency of 7 

6. 
A group of students took a test and the following frequency table shows the scores above A. 1.75 B. 2 C. 2.5 D. 2.75 E. 3
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Detailed Solution\(\bar{x} = \frac{\sum fx}{\sum f}\)= \(\frac{55}{20}\) = \(2.75\) 

7. 
A group of students took a test and the following frequency table shows the scores above A. 0 B. 2.5 C. 3 D. 5 E. 7
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Detailed SolutionThere are 20 students. Hence, the median is found by the average of the 10th and 11th score.= \(\frac{3 + 3}{2}\) = 3 

8. 
If cos 60° = 1/2, which of the following angle has cosine of 1/2? A. 30^{o} B. 120^{o} C. 150^{o} D. 210^{o} E. 300^{o}
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Detailed Solutioncos 60° = 1/2, cos(180°  60°) = 1/2cos120° = 1/2 

9. 
In the diagram above, find the ratio PQ/PR A. 2 : 5 B. 3 : 5 C. 2 : 3 D. 3 : 2 E. 5 : 3 
B 
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