Paper 1  Objectives  48 Questions
WASSCE/WAEC MAY/JUNE
Year: 1995
Level: SHS
Time:
Type: Question Paper
Source: Nigeria
Answers provided
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#  Question  Ans 

1. 
Find (101\(_2\))\(^2\), expressing the answer in base 2. A. 10101 B. 11001 C. 10010 D. 11101 E. 10110
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Detailed SolutionYou can convert it to base 10 and square, then reconvert it after the operation.OR You can multiply it straight applying the rules of binary multiplication. 

2. 
If three children shares N10.50 among themselves in ratio 6:7:8, how much is the largest share? A. N3.00 B. N3.50 C. N4.00 D. N4.50 E. N5.00
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Detailed SolutionRatio = 6 + 7 + 8 = 2121 = N10.50 1 = 1050K/21 = 50K 6 = 6 x 50K = N3.00 7 = 7 x 50K = N3.50 8 = 8 x 50K = N4.00 the Largest share = N4.00 

3. 
Express 0.000834 in standard form A. 8.34 x 10^{4} B. 8.34 x 10^{3} C. 8.34 x 10^{3} D. 8.34 x 10^{4} E. 8.34 x 10^{6} 
A 
4. 
Given that log_{2}a = log_{8}4, find a A. 2^{1/3} B. 4^{2/3} C. 4^{2/3} D. 2^{2/3} E. 2^{3}
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Detailed SolutionLog_{2}a = Log_{8}4Log_{2}a = Log_{8}8^{2/3} → 2/3Log_{8}8 → 2/3 x 1 Log_{2}a = 2/3 Recall; If Log_{a}x = y ∴ ay = x Log_{2}a = 2/3 2^{2/3} = a 

5. 
By selling some crates of soft drinks for N600.00, a dealer makes a profit of 50%. How much did the dealer pay for the drinks? A. N1,200.00 B. N900.00 C. N450.00 D. N400.00 E. N200.00
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Detailed SolutionS.P = N600.00(100 + 50)% = N600 150% = N600 1% = \(\frac{600}{150}\) 100% = \(\frac{600}{150} \times 100%\) = N400 

6. 
Find the nth term Un of the A.P., 11, 4, 3,....... . A. Un=19+7n B. Un=197n C. Un=18+7n D. Un= 187n E. Un= 177n
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Detailed SolutionA.P 11, 4, 31st term = 11 A.P = a, a + d, a + 2d ...... a + (n  1)d If a = 11 a + d = 4 d = 4  11 = 7 nth term = a + (n1)d = 11 + (n1)(7) = 11  7n + 7 = 18  7n 

7. 
lf 16/9 , x, 1, y are in Geometric Progression (GP), find the product of x and y. A. 9/16 B. 3/4 C. 1 D. 4/3 E. 16/6
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Detailed Solution16/9, x, 1, y => a, ar, ar^{2}, ar^{3}ar^{2} = 1 => 16r^{2}/9 = 1 => 16r^{2} 9 => r^{2} = 9/16 => r = 3/4 ar^{2} = y = ar^{2} x r = 1 x 3/4 = 3/4 x xy = 4/3 x 3/4 = 1 

8. 
If R = [2, 4, 6, 7] and S = [1, 2, 4, 8], then R∪S equal A. [1,2,4,6,7,8] B. [1,2,4,7,8] C. [1,4.7,8] D. [2.6.7] E. [2.4]
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Detailed SolutionR = {2, 4, 6, 7}; S = {1, 2, 4, 8}R \(\cup\) S = {1, 2, 4, 6, 7, 8} 

9. 
Find the value(s) of x for which the expression is undefined: \(\frac{6x  1}{x^2 + 4x  5}\) A. +4 or+1 B. 5 or +1 C. 5 or 1 D. +5 or 1 E. \(\frac{1}{6}\)
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Detailed Solution\(\frac{6x  1}{x^2 + 4x  5}\)The expression is undefined when \(x^2 + 4x  5 = 0\) \(x^2 + 5x  x  5 = 0\) \(x(x + 5)  1(x + 5) = 0\) \((x  1)(x + 5) = 0\) The expression is undefined when x = 1 or 5. 

10. 
Which of the following could be the inequality illustrated in the sketch graph above? A. y≥2x+3 B. y≤3x+3 C. y < 3x+2 D. y≤x +3 E. y≥3x+2.
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Detailed SolutionGradient of the line = \(\frac{3  0}{0  1}\)= 3 y = 3x + b. Using (1,0), we have 0 = 3(1) + b 0 = 3 + b b = 3 y = 3x + 3 \(\therefore\) The graph illustrates y \(\leq\) 3x + 3. 
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