Paper 1 | Objectives | 45 Questions
WASSCE/WAEC MAY/JUNE
Year: 1997
Level: SHS
Time:
Type: Question Paper
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Make sure you study hard but not into the late-night hours to give your body the enough rest you need.
These are the three things to do in test preparation for higher grades and excellent performance.
Apply tips for stress-free eating before and during exams and what to avoid for good grades.
# | Question | Ans |
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1. |
Express (0.0425 / 2.5) as a fraction A. 17/10,000 B. 17/1,000 C. 17/250 D. 17,100 E. 17/10
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Detailed Solution0.0425/2.5 = 425/25000 = 17/1000 |
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2. |
If P = {3, 5, 6} and Q = {4, 5, 6} then P∩Q equals A. {3, 4} B. {4, 5} C. {4, 6} D. {5, 6} E. {3, 5}
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Detailed SolutionP ∩ Q = {5, 6} |
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3. |
A and B are two sets. The number of elements in A∪B is 49, the number in A is 22 and number in B is 34. How many elements are in A ∩ E? A. 105 B. 27 C. 15 D. 12 E. 7
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Detailed SolutionLet x represent the intersection34 - x + 22 - x + x = 49   - x = 49 - 56; x = 7 |
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4. |
A student found the approximate value of 0.02548 correct to two places of decimal instead of two significant figures. Find the percentage error. A. 0% B. 131/3% C. 15 5/13% D. 2/3% E. 20%
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Detailed Solution0.02548 \(\approxeq\) 0.03 (to 2 decimal places)0.02548 \(\approxeq\) 0.025 (2 sig. figs) Error = 0.03 - 0.025 = 0.005 % error = \(\frac{0.005}{0.025} \times 100%\) = 20% |
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5. |
Simplify log39 + log315 - log35 A. log319 B. log3 C. 3 D. 1 E. o
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Detailed Solutionlog3 (9 x 15)/5 = log327 = 3 |
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6. |
Solve me equation: 2/3 (x + 5) = 1/4(5x - 3) A. 11/7 B. 18/23 C. 3 D. 43/7 E. 7
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Detailed Solution2/3 (x + 5) = 1/4(5x - 3)8x + 40 = 15x - 9 -7x = -49 x = 7 |
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7. |
Which of the following equations has its roots as 4 and -5? A. x2 + 4x - 20 = 0 B. x2 + x + 20 = 0 C. x2 - x + 20 = 0 D. x2 + x - 20 = 0 E. x2 - x - 20 = 0
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Detailed Solution(x - 4)(x + 5) = 0x\(^2\) + 5x - 4x - 20 = 0 x\(^2\) + x - 20 = 0 |
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8. |
Solve the equations: 4x -y = 11; 5x + 2y = 4. A. x = 6, y = 13 B. x = -2, y = -3 C. x = -2, y = 3 D. x = 2, y = -3 E. x = 2, y = 3.
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Detailed Solution4x - y = 11....(1) x 2 8x - 2y = 22....(3)5x + 12y = 4....(2) x 1 5x + 2y = 4....(4) add eqn (3) and (4) 13x = 26 x = 2 4(2) - y = 11 \(\implies\) y = 8 - 11 y = -3. |
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9. |
Make q the subject of the relation t = √pq/r - r2 A. q = rt2/p - r3 B. q = t2/p - r2 C. q = rt/p - r3 D. q = p - r3/rt2 E. q = rt2(p - r3) |
A |
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