Year :
1988
Title :
Mathematics (Core)
Exam :
WASSCE/WAEC MAY/JUNE
Paper 1 | Objectives
1 - 10 of 41 Questions
| # | Question | Ans |
|---|---|---|
| 1. |
Evaluate (101.5)2 - (100.5)2 A. 1 B. 2.02 C. 20.02 D. 202 E. 2020 Detailed Solution(101.5)2 - (100.5)2;(101.5 + 100.5)202 x 1 = 202 |
|
| 2. |
Express the product of 0.06 and 0.09 in standard form A. 5.4 * 10-1 B. 5.4*10-2 C. 5.4*10-3 D. 5.4*102 E. 5.4*103 Detailed Solution0.06 x 0.09 = 0.0054= 5.4 x 10-3 |
|
| 3. |
Simplify 36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\) A. 0 B. 1\24 C. 2/3 D. 11/2 E. 71/2 Detailed Solution36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)= \(6 \times \frac{1}{4} \times 1\) = \(1\frac{1}{2}\) |
|
| 4. |
Find the 8th term of the A.P -3, -1, 1 ...... A. 13 B. 11 C. -8 D. -11 E. -17 Detailed SolutionUn = a + (n-1)d= -3 + (8 - 1)2 = 11 |
|
| 5. |
 A group of students took a test and the following frequency table shows the scores above A. 2 B. 3 C. 4 D. 5 E. 7 Detailed SolutionThe mode=4. It has the highest frequency of 7 |
|
| 6. |
 A group of students took a test and the following frequency table shows the scores above A. 1.75 B. 2 C. 2.5 D. 2.75 E. 3 Detailed Solution\(\bar{x} = \frac{\sum fx}{\sum f}\)= \(\frac{55}{20}\) = \(2.75\) |
|
| 7. |
 A group of students took a test and the following frequency table shows the scores above A. 0 B. 2.5 C. 3 D. 5 E. 7 Detailed SolutionThere are 20 students. Hence, the median is found by the average of the 10th and 11th score.= \(\frac{3 + 3}{2}\) = 3 |
|
| 8. |
If cos 60° = 1/2, which of the following angle has cosine of -1/2? A. 30o B. 120o C. 150o D. 210o E. 300o Detailed Solutioncos 60° = 1/2, cos(180° - 60°) = -1/2cos120° = -1/2 |
|
| 9. |
 In the diagram above, find the ratio |PQ|/|PR| A. 2 : 5 B. 3 : 5 C. 2 : 3 D. 3 : 2 E. 5 : 3 |
B |
| 10. |
A ladder 9m long leans against a vertical wall, making an angle of 64° with the horizontal ground. calculate correct to one decimal place, how far the foot of the ladder is from the wall. A. 4.0m B. 5.8m C. 7.1m D. 8.1m E. 18.5m Detailed Solution
x = 9 cos 64° =3.94 ≅ 4.0m |
| 1. |
Evaluate (101.5)2 - (100.5)2 A. 1 B. 2.02 C. 20.02 D. 202 E. 2020 Detailed Solution(101.5)2 - (100.5)2;(101.5 + 100.5)202 x 1 = 202 |
|
| 2. |
Express the product of 0.06 and 0.09 in standard form A. 5.4 * 10-1 B. 5.4*10-2 C. 5.4*10-3 D. 5.4*102 E. 5.4*103 Detailed Solution0.06 x 0.09 = 0.0054= 5.4 x 10-3 |
|
| 3. |
Simplify 36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\) A. 0 B. 1\24 C. 2/3 D. 11/2 E. 71/2 Detailed Solution36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)= \(6 \times \frac{1}{4} \times 1\) = \(1\frac{1}{2}\) |
|
| 4. |
Find the 8th term of the A.P -3, -1, 1 ...... A. 13 B. 11 C. -8 D. -11 E. -17 Detailed SolutionUn = a + (n-1)d= -3 + (8 - 1)2 = 11 |
|
| 5. |
A group of students took a test and the following frequency table shows the scores above A. 2 B. 3 C. 4 D. 5 E. 7 Detailed SolutionThe mode=4. It has the highest frequency of 7 |
| 6. |
A group of students took a test and the following frequency table shows the scores above A. 1.75 B. 2 C. 2.5 D. 2.75 E. 3 Detailed Solution\(\bar{x} = \frac{\sum fx}{\sum f}\)= \(\frac{55}{20}\) = \(2.75\) |
|
| 7. |
A group of students took a test and the following frequency table shows the scores above A. 0 B. 2.5 C. 3 D. 5 E. 7 Detailed SolutionThere are 20 students. Hence, the median is found by the average of the 10th and 11th score.= \(\frac{3 + 3}{2}\) = 3 |
|
| 8. |
If cos 60° = 1/2, which of the following angle has cosine of -1/2? A. 30o B. 120o C. 150o D. 210o E. 300o Detailed Solutioncos 60° = 1/2, cos(180° - 60°) = -1/2cos120° = -1/2 |
|
| 9. |
In the diagram above, find the ratio |PQ|/|PR| A. 2 : 5 B. 3 : 5 C. 2 : 3 D. 3 : 2 E. 5 : 3 |
B |
| 10. |
A ladder 9m long leans against a vertical wall, making an angle of 64° with the horizontal ground. calculate correct to one decimal place, how far the foot of the ladder is from the wall. A. 4.0m B. 5.8m C. 7.1m D. 8.1m E. 18.5m Detailed Solution
x = 9 cos 64° =3.94 ≅ 4.0m |