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Paper 1 | Objectives | 41 Questions
WASSCE/WAEC MAY/JUNE
Year: 1988
Level: SHS
Time:
Type: Question Paper
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# | Question | Ans |
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1. |
Evaluate (101.5)2 - (100.5)2 A. 1 B. 2.02 C. 20.02 D. 202 E. 2020
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Detailed Solution(101.5)2 - (100.5)2;(101.5 + 100.5)202 x 1 = 202 |
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2. |
Express the product of 0.06 and 0.09 in standard form A. 5.4 * 10-1 B. 5.4*10-2 C. 5.4*10-3 D. 5.4*102 E. 5.4*103
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Detailed Solution0.06 x 0.09 = 0.0054= 5.4 x 10-3 |
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3. |
Simplify 36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\) A. 0 B. 1\24 C. 2/3 D. 11/2 E. 71/2
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Detailed Solution36\(^\frac{1}{2}\) x 64\(-^\frac{1}{3}\) x 5\(^0\)= \(6 \times \frac{1}{4} \times 1\) = \(1\frac{1}{2}\) |
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4. |
Find the 8th term of the A.P -3, -1, 1 ...... A. 13 B. 11 C. -8 D. -11 E. -17
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Detailed SolutionUn = a + (n-1)d     = -3 + (8 - 1)2      = 11 |
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5. |
A group of students took a test and the following frequency table shows the scores above A. 2 B. 3 C. 4 D. 5 E. 7
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Detailed SolutionThe mode=4. It has the highest frequency of 7 |
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6. |
A group of students took a test and the following frequency table shows the scores above A. 1.75 B. 2 C. 2.5 D. 2.75 E. 3
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Detailed Solution\(\bar{x} = \frac{\sum fx}{\sum f}\)= \(\frac{55}{20}\) = \(2.75\) |
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7. |
A group of students took a test and the following frequency table shows the scores above A. 0 B. 2.5 C. 3 D. 5 E. 7
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Detailed SolutionThere are 20 students. Hence, the median is found by the average of the 10th and 11th score.= \(\frac{3 + 3}{2}\) = 3 |
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8. |
If cos 60° = 1/2, which of the following angle has cosine of -1/2? A. 30o B. 120o C. 150o D. 210o E. 300o
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Detailed Solutioncos 60° = 1/2, cos(180° - 60°) = -1/2cos120° = -1/2 |
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9. |
In the diagram above, find the ratio |PQ|/|PR| A. 2 : 5 B. 3 : 5 C. 2 : 3 D. 3 : 2 E. 5 : 3 |
B |
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