Paper 1  Objectives  45 Questions
JAMB Exam
Year: 2003
Level: SHS
Time:
Type: Question Paper
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#  Question  Ans 

1. 
Evaluate \(log_{\sqrt{2}}4+log_{\frac{1}{2}}16log_{4}32\) A. 5.5 B. 2.5 C. 2.5 D. 5.5
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Detailed SolutionNote that if we set \(log_{\sqrt{2}}4 = x_{1}, \hspace{1mm}solving\hspace{1mm}gives\hspace{1mm}x_{1}=4\\if\hspace{1mm}log_{\frac{1}{2}}16 = x_{2}, \Rightarrow x_{2} = 4\\Also \hspace{1mm}for\hspace{1mm}log_{4}32 = x_{3} = 2.5\\Combining\hspace{1mm}results,\hspace{1mm}x_{1}+x_{2}+x_{3} = 4+(4)2.5=2.5\)Note that the solution has been separated to simplify solving difficulty due to different bases. 

2. 
Simplify 213\(_4\) x 23\(_4\) A. 10311_{4} B. 10321_{4} C. 12231_{4} D. 13211_{4}
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Detailed SolutionYou can either multiply directly in base 4 or you can decide to convert to base 10 and do the multiplication and reconvert. 

3. 
In a class of 40 students, 32 offer mathematics, 24 offer Physics, and 4 offer neither Mathematics nor Physics. How many offer both Mat A. 20 B. 16 C. 8 D. 4
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Detailed SolutionUsing a venn diagram, let x = number who offer both Maths and Physics. So that (32x) offer Maths and another (24x) offer Physics.(32x) + (24x) + (x) + (4 who offer neither) = 40 => 60  x = 40 => x = 20 Therefore x = 20. 

4. 
Find (\(\frac{1}{0.06} \div \frac{1}{0.042}\))1 A. 1.43 B. 1.53 C. 3.14 D. 4.42
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Detailed Solution\((\frac{1}{0.06} \div \frac{1}{0.042})^{1}\)= \((\frac{100}{6} \div \frac{1000}{42})^{1}\) = \((\frac{100}{6} \times \frac{42}{1000})^{1}\) = \((\frac{7}{10})^{1}\) = \(\frac{10}{7}\) = 1.4285 \(\approxeq\) 1.43. 

5. 
A woman buys 270 oranges for N1800.00 and sells at 5 for N40.00. What is her profit? A. N2,160.00 B. N1, 620.00 C. N630.00 D. N360.00
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Detailed SolutionC.P = N1800S.P = (270/5) x 40 = N2160.00 Profit = S.P  C.P = N2160  N1800 = N360.00 

6. 
Simplify 1  (7/3 x 5/4) + 3/5 A. 16/15 B. 79/60 C. 37/15 D. 151/60
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Detailed Solution\(1  (\frac{7}{3} \times \frac{5}{4}) + \frac{3}{5}\)= \(1  \frac{35}{12} + \frac{3}{5}\) = \(\frac{60  175 + 36}{60}\) = \(\frac{79}{60}\) 

7. 
Simplify (√98 √50)/√32 A. 3 B. 1 C. 1/2 D. 1/4
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Detailed Solution(√98  √50)/√32 = √(49x2)  √(25x2)=> (7√2  5√2)/4√2 = 1/2 

8. 
A cinema hall contains a certain number of people. If 22\(\frac{1}{2}\)% are children, 47\(\frac{1}{2}\)% are men and 84 are women, find the number of men in the hall. A. 63 B. 84 C. 113 D. 133
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Detailed Solution45/2% + 95/2% = 70%100%  70% = 30% (i.e women) => 30% = 84 1% = 84/30 95/2% = (84/30 x 95/2) = 133. 

9. 
If \(\frac{9^{2x1}}{27^{x+1}} = 1\), find the value of x. A. 8 B. 5 C. 3 D. 2
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Detailed Solution\(\frac{9^{2x  1}}{27^{x + 1}} = 1\)\(\implies 9^{2x  1} = 27^{x + 1}\) \((3^{2})^{2x  1} = (3^{3})^{x + 1}\) \(2(2x  1) = 3(x + 1) \implies 4x  2 = 3x + 3\) \(4x  3x = 3 + 2 \implies x = 5\) 
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