Mathematics (Core)
Paper 1 | Objectives | 45 Questions
JAMB Exam
Year: 2003
Level: SHS
Time:
Type: Question Paper
Answers provided
FREE
No description provided
Feedbacks
This paper is yet to be rated
Paper 1 | Objectives | 45 Questions
JAMB Exam
Year: 2003
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Effective ways of coping with exam stress and test anxiety which is supported by Science
Eat well during in test days for good grades. How can you plan your exam diet with good grades in mind?
Apply tips for stress-free eating before and during exams and what to avoid for good grades.
| # | Question | Ans |
|---|---|---|
| 1. |
Evaluate \(log_{\sqrt{2}}4+log_{\frac{1}{2}}16-log_{4}32\) A. -5.5 B. -2.5 C. 2.5 D. 5.5
Show Content
Detailed SolutionNote that if we set \(log_{\sqrt{2}}4 = x_{1}, \hspace{1mm}solving\hspace{1mm}gives\hspace{1mm}x_{1}=4\\if\hspace{1mm}log_{\frac{1}{2}}16 = x_{2}, \Rightarrow x_{2} = -4\\Also \hspace{1mm}for\hspace{1mm}log_{4}32 = x_{3} = 2.5\\Combining\hspace{1mm}results,\hspace{1mm}x_{1}+x_{2}+x_{3} = 4+(-4)-2.5=-2.5\)Note that the solution has been separated to simplify solving difficulty due to different bases. |
|
| 2. |
Simplify 213\(_4\) x 23\(_4\) A. 103114 B. 103214 C. 122314 D. 132114
Show Content
Detailed SolutionYou can either multiply directly in base 4 or you can decide to convert to base 10 and do the multiplication and re-convert. |
|
| 3. |
In a class of 40 students, 32 offer mathematics, 24 offer Physics, and 4 offer neither Mathematics nor Physics. How many offer both Mat A. 20 B. 16 C. 8 D. 4
Show Content
Detailed SolutionUsing a venn diagram, let x = number who offer both Maths and Physics. So that (32-x) offer Maths and another (24-x) offer Physics.(32-x) + (24-x) + (x) + (4 who offer neither) = 40 => 60 - x = 40 => -x = -20 Therefore x = 20. |
|
| 4. |
Find (\(\frac{1}{0.06} \div \frac{1}{0.042}\))-1 A. 1.43 B. 1.53 C. 3.14 D. 4.42
Show Content
Detailed Solution\((\frac{1}{0.06} \div \frac{1}{0.042})^{-1}\)= \((\frac{100}{6} \div \frac{1000}{42})^{-1}\) = \((\frac{100}{6} \times \frac{42}{1000})^{-1}\) = \((\frac{7}{10})^{-1}\) = \(\frac{10}{7}\) = 1.4285 \(\approxeq\) 1.43. |
|
| 5. |
A woman buys 270 oranges for N1800.00 and sells at 5 for N40.00. What is her profit? A. N2,160.00 B. N1, 620.00 C. N630.00 D. N360.00
Show Content
Detailed SolutionC.P = N1800S.P = (270/5) x 40 = N2160.00 Profit = S.P - C.P = N2160 - N1800 = N360.00 |
|
| 6. |
Simplify 1 - (7/3 x 5/4) + 3/5 A. -16/15 B. -79/60 C. -37/15 D. -151/60
Show Content
Detailed Solution\(1 - (\frac{7}{3} \times \frac{5}{4}) + \frac{3}{5}\)= \(1 - \frac{35}{12} + \frac{3}{5}\) = \(\frac{60 - 175 + 36}{60}\) = \(\frac{-79}{60}\) |
|
| 7. |
Simplify (√98 -√50)/√32 A. 3 B. 1 C. 1/2 D. 1/4
Show Content
Detailed Solution(√98 - √50)/√32 = √(49x2) - √(25x2)=> (7√2 - 5√2)/4√2 = 1/2 |
|
| 8. |
A cinema hall contains a certain number of people. If 22\(\frac{1}{2}\)% are children, 47\(\frac{1}{2}\)% are men and 84 are women, find the number of men in the hall. A. 63 B. 84 C. 113 D. 133
Show Content
Detailed Solution45/2% + 95/2% = 70%100% - 70% = 30% (i.e women) => 30% = 84 1% = 84/30 95/2% = (84/30 x 95/2) = 133. |
|
| 9. |
If \(\frac{9^{2x-1}}{27^{x+1}} = 1\), find the value of x. A. 8 B. 5 C. 3 D. 2
Show Content
Detailed Solution\(\frac{9^{2x - 1}}{27^{x + 1}} = 1\)\(\implies 9^{2x - 1} = 27^{x + 1}\) \((3^{2})^{2x - 1} = (3^{3})^{x + 1}\) \(2(2x - 1) = 3(x + 1) \implies 4x - 2 = 3x + 3\) \(4x - 3x = 3 + 2 \implies x = 5\) |
Preview displays only 9 out of the 45 Questions