Mathematics (Core)
Paper 1 | Objectives | 46 Questions
WASSCE/WAEC MAY/JUNE
Year: 2006
Level: SHS
Time:
Type: Question Paper
Answers provided
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Paper 1 | Objectives | 46 Questions
WASSCE/WAEC MAY/JUNE
Year: 2006
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
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| # | Question | Ans |
|---|---|---|
| 1. |
Evaluate (0.13)\(^3\)correct to three significant figures A. 0.00219 B. 0.00220 C. 0.00300 D. 0.00390
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Detailed Solution(0.13)\(^3\) = 0.13 x 0.13 x 0.13 = 0.002197= 0.00220 (3 s.f) |
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| 2. |
Simplify: 11011\(_2\) - 1101\(_2\) A. 101000\(_2\) B. 1100\(_2\) C. 1110\(_2\) D. 1011\(_2\)
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Detailed Solution11011\(_2\) - 1101\(_2\) = 1110\(_2\) |
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| 3. |
Simplify \(\frac{25 \frac{2}{3} \div 25 \frac{1}{6}}{( \frac{1}{5})^{-\frac{7}{6}} \times ( \frac{1}{5})^{\frac{1}{6}}}\) A. 25 B. \(\frac{1}{5}\) C. 1 D. \(\frac{1}{25}\)
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Detailed Solution\(\frac{25 \frac{2}{3} \div 25 \frac{1}{6}}{( \frac{1}{5})^{-\frac{7}{6}} \times ( \frac{1}{5})^{\frac{1}{6}}}\) = \(\frac{25^{4 - \frac{1}{6}}}{(\frac{1}{5})^{-7 + \frac{1}{6}}}\)= \(\frac{25^{\frac{1}{2}}}{(\frac{1}{5})^{-1}}\) = \(\frac{(5^2)^{\frac{1}{2}}}{(5^{-1})^{-1}}\) = \(\frac{5}{5}\) = 1 |
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| 4. |
Simplify \(\frac{x - 4}{4} - \frac{x - 3}{6}\) A. \(\frac{x - 18}{12}\) B. \(\frac{x - 6}{12}\) C. \(\frac{x - 18}{24}\) D. \(\frac{x - 6}{24}\)
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Detailed Solution\(\frac{x - 4}{4} - \frac{x - 3}{6}\) = \(\frac{3(x - 4) - 2(x - 3)}{12}\)= \(\frac{3x -12 - 2x + 6}{12}\) = \(\frac{3x - 2x - 12 + 6}{12}\) = \(\frac{x - 6}{12}\) |
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| 5. |
Given that y = 1 - \(\frac{2x}{4x - 3}\), find the value of x for which y is undefined A. 3 B. \(\frac{3}{4}\) C. \(\frac{-3}{4}\) D. -3
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Detailed Solutionfor undefined expression, the denomination is zero 4x - 3 = 04x = 3; x = \(\frac{3}{4}\) |
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| 6. |
P is a point on the same plane with a fixed point A. If P moves such that it is always equidistant from A, the locus of P is A. a straight line joining A and P B. the perpendicular bisector of AP C. a circle with centre A D. the triangle with centre P |
C |
| 7. |
A fair coin is tossed three times. Find the probability of getting two heads and one tail. A. \(\frac{1}{2}\) B. \(\frac{3}{8}\) C. \(\frac{1}{4}\) D. \(\frac{1}{8}\)
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Detailed SolutionPr(head) = \(\frac{1}{2}\), Pr(tail) = \(\frac{1}{2}\):Pr(2 heads)= \(\frac{1}{2}\) x \(\frac{1}{2}\) = \(\frac{1}{4}\) Pr(2 heads and tail) 3 times = (\(\frac{1}{4}\) x \(\frac{1}{2}\)) x 3 = \(\frac{3}{8}\) |
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| 8. |
If 30% of y is equal to x, what in terms of x, is 30% of 3y? A. \(\frac{x}{9}\) B. \(\frac{x}{3}\) C. x D. 3x
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Detailed SolutionIf 30% of y = x, then 30% of 3y = 3x |
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| 9. |
A baker used 40% of a 50kg bag of flour. If \(\frac{1}{8}\) of the amount used was for the cake, how many kilogram of flour was used for the cake? A. 2\(\frac{1}{2}\) B. 6\(\frac{1}{2}\) C. 15\(\frac{3}{8}\) D. 17\(\frac{1}{2}\)
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Detailed Solution\(\frac{40}{100} \times 50\)kg = 20kg\(\frac{1}{8}\) of 20kg for cake; \(\frac{1}{8}\) x \(\frac{20}{1}\) = 2\(\frac{1}{2}\)kg |
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| 10. |
If tan y = 0.404, where y is acute, find cos 2y A. 0.035 B. 0.719 C. 0.808 D. 0.927
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Detailed Solutiontan y = 0.404; y = tan-1 0.0404(tables);y = 22ocos 2y = cos 2(22o); cos 44o = 0.719 |
Preview displays only 10 out of the 46 Questions