Paper 1  Objectives  46 Questions
WASSCE/WAEC MAY/JUNE
Year: 2006
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Middle East and North Africa MENA Scholarship Program (MSP) initiative provides scholarships
Make sure you study hard but not into the latenight hours to give your body the enough rest you need.
Past questions are effective for revisions for all tests including WAEC, BECE, SAT, TOEFL, GCSE, IELTS
#  Question  Ans 

1. 
Evaluate (0.13)\(^3\)correct to three significant figures A. 0.00219 B. 0.00220 C. 0.00300 D. 0.00390
Show Content
Detailed Solution(0.13)\(^3\) = 0.13 x 0.13 x 0.13 = 0.002197= 0.00220 (3 s.f) 

2. 
Simplify: 11011\(_2\)  1101\(_2\) A. 101000\(_2\) B. 1100\(_2\) C. 1110\(_2\) D. 1011\(_2\)
Show Content
Detailed Solution11011\(_2\)  1101\(_2\) = 1110\(_2\) 

3. 
Simplify \(\frac{25 \frac{2}{3} \div 25 \frac{1}{6}}{( \frac{1}{5})^{\frac{7}{6}} \times ( \frac{1}{5})^{\frac{1}{6}}}\) A. 25 B. \(\frac{1}{5}\) C. 1 D. \(\frac{1}{25}\)
Show Content
Detailed Solution\(\frac{25 \frac{2}{3} \div 25 \frac{1}{6}}{( \frac{1}{5})^{\frac{7}{6}} \times ( \frac{1}{5})^{\frac{1}{6}}}\) = \(\frac{25^{4  \frac{1}{6}}}{(\frac{1}{5})^{7 + \frac{1}{6}}}\)= \(\frac{25^{\frac{1}{2}}}{(\frac{1}{5})^{1}}\) = \(\frac{(5^2)^{\frac{1}{2}}}{(5^{1})^{1}}\) = \(\frac{5}{5}\) = 1 

4. 
Simplify \(\frac{x  4}{4}  \frac{x  3}{6}\) A. \(\frac{x  18}{12}\) B. \(\frac{x  6}{12}\) C. \(\frac{x  18}{24}\) D. \(\frac{x  6}{24}\)
Show Content
Detailed Solution\(\frac{x  4}{4}  \frac{x  3}{6}\) = \(\frac{3(x  4)  2(x  3)}{12}\)= \(\frac{3x 12  2x + 6}{12}\) = \(\frac{3x  2x  12 + 6}{12}\) = \(\frac{x  6}{12}\) 

5. 
Given that y = 1  \(\frac{2x}{4x  3}\), find the value of x for which y is undefined A. 3 B. \(\frac{3}{4}\) C. \(\frac{3}{4}\) D. 3
Show Content
Detailed Solutionfor undefined expression, the denomination is zero 4x  3 = 04x = 3; x = \(\frac{3}{4}\) 

6. 
P is a point on the same plane with a fixed point A. If P moves such that it is always equidistant from A, the locus of P is A. a straight line joining A and P B. the perpendicular bisector of AP C. a circle with centre A D. the triangle with centre P 
C 
7. 
A fair coin is tossed three times. Find the probability of getting two heads and one tail. A. \(\frac{1}{2}\) B. \(\frac{3}{8}\) C. \(\frac{1}{4}\) D. \(\frac{1}{8}\)
Show Content
Detailed SolutionPr(head) = \(\frac{1}{2}\), Pr(tail) = \(\frac{1}{2}\):Pr(2 heads)= \(\frac{1}{2}\) x \(\frac{1}{2}\) = \(\frac{1}{4}\) Pr(2 heads and tail) 3 times = (\(\frac{1}{4}\) x \(\frac{1}{2}\)) x 3 = \(\frac{3}{8}\) 

8. 
If 30% of y is equal to x, what in terms of x, is 30% of 3y? A. \(\frac{x}{9}\) B. \(\frac{x}{3}\) C. x D. 3x
Show Content
Detailed SolutionIf 30% of y = x, then 30% of 3y = 3x 

9. 
A baker used 40% of a 50kg bag of flour. If \(\frac{1}{8}\) of the amount used was for the cake, how many kilogram of flour was used for the cake? A. 2\(\frac{1}{2}\) B. 6\(\frac{1}{2}\) C. 15\(\frac{3}{8}\) D. 17\(\frac{1}{2}\)
Show Content
Detailed Solution\(\frac{40}{100} \times 50\)kg = 20kg\(\frac{1}{8}\) of 20kg for cake; \(\frac{1}{8}\) x \(\frac{20}{1}\) = 2\(\frac{1}{2}\)kg 

10. 
If tan y = 0.404, where y is acute, find cos 2y A. 0.035 B. 0.719 C. 0.808 D. 0.927
Show Content
Detailed Solutiontan y = 0.404; y = tan^{1} 0.0404(tables);y = 22^{o}cos 2y = cos 2(22^{o}); cos 44^{o} = 0.719 
Preview displays only 10 out of the 46 Questions