Mathematics (Core)
Paper 1 | Objectives | 67 Questions
WASSCE/WAEC MAY/JUNE
Year: 2007
Level: SHS
Time:
Type: Question Paper
Answers provided
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Paper 1 | Objectives | 67 Questions
WASSCE/WAEC MAY/JUNE
Year: 2007
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Eat well during in test days for good grades. How can you plan your exam diet with good grades in mind?
African Canadian Continuing Education Society (ACCES) Post-secondary Scholarship Program 2022 Kenya
The goal of mocks tests is to create a bench-marking tool to help students assess their performances.
| # | Question | Ans |
|---|---|---|
| 1. |
Evaluate \((111_{two})^2\) and leave your answer in base 2 A. \(111001_{two}\) B. \(110001_{two}\) C. \(101001_{two}\) D. \(10010_{two}\)
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Detailed Solution\((111_{two})^{2}=(111_{two})(111_{two})\\=1 \times 2^{2}+1\times2^{1}+1\times 2^{0}=4+2+1=7_{_{ten}}\\ (111_{two})^{2}=7\times 7=49\\ \begin{matrix} 2 & 49\\ 2 & 24\hspace{1mm}R\hspace{1mm}1\\ 2 & 12\hspace{1mm}R\hspace{1mm}0\\ 2 & 6\hspace{1mm}R\hspace{1mm}0\\ 2 & 3\hspace{1mm}R\hspace{1mm}0\\ 2 & 1\hspace{1mm}R\hspace{1mm}1\\ & 0\hspace{1mm}R\hspace{1mm}1\hspace{1mm}\uparrow \end{matrix} \\ =110001_{2}\) |
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| 2. |
Find the LCM of \(2^{3}\times 3\times 5^{2}, 2\times 3^{2}\times 5 \hspace{1mm}and \hspace{1mm}2^{2}\times 3^{2}\times 5\) A. \(2^{2}\times 3^{3}\times 5^{2}\) B. \(2^{3}\times 3^{23}\times 5\) C. \(2^{2}\times 3^{2}\times 5^{2}\) D. \(2^{3}\times 3^{3}\times 5^{2}\) |
D |
| 3. |
Simplify \((0.3\times 10^{5})\div (0.4\times 10^{7})\)leaving your answer in standard form A. \(7.5\times 10^{-4}\) B. \(7.5\times 10^{-3}\) C. \(7.5\times 10^{-2}\) D. \(7.5\times 10^{-1}\)
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Detailed Solution\((0.3\times 10^{5})\div (0.4\times 10^{7})\\\frac{3}{10}\times 10^{5}\div \frac{4}{10}\times 10^{7}=3\times 10^{4}\div 4\times 10^{6}\\ \frac{3\times 10^{4}}{4\times 10^{7}}=\frac{3}{4}\times 10^{-2}=0.75\times 10^{-2}\\ 7.5\times 10^{-3}\) |
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| 4. |
If \(p\propto \frac{1}{q}\), which of the following is true? A. \(\propto p^{2}\) B. \(p\propto \frac{1}{q^{2}}\) C. \(q\propto \sqrt{p}\) D. \(q\propto \frac{1}{p}\)
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Detailed Solution\(p\propto \frac{1}{q} = q \propto \frac{1}{p}\) |
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| 5. |
Simplify \(3\sqrt{45}-12\sqrt{5}+16\sqrt{20}\)leaving your answer in surd form A. \(29\sqrt{5}\) B. \(14\sqrt{15}\) C. \(12\sqrt{15}\) D. \(11\sqrt{5}\)
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Detailed Solution\(3\sqrt{45}-12\sqrt{5}+16\sqrt{20}\\3\sqrt{5\times 9}-12\sqrt{5}+16\sqrt{4\times 5}\\ 3\times 3\sqrt{5}-12\sqrt{5}+16\times 2\sqrt{5}\\ 9\sqrt{5}-12\sqrt{5}+32\sqrt{5}\\ 29\sqrt{5}\) |
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| 6. |
Which of the following is true for the set \(P = \{-3.2\leq x< 5\}\) where x is an integer A. least value of x is -3.2 B. least value of x is -3 C. greatest value of x is 4.9 D. greatest value of x is 5 |
A |
| 7. |
Simplify\(\frac{3x^{3}}{(3x)^{3}}\) A. 1 B. \(\frac{1}{3}\) C. \(\frac{1}{9}\) D. \(\frac{1}{27}\)
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Detailed Solution\(\frac{3x^{3}}{(3x)^{3}}\\\frac{3x^{3}}{3x\times 3x\times 3x}=\frac{3\times x\times x\times x}{3\times 3\times 3\times x\times x\times x}=\frac{1}{9}\) |
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| 8. |
N140,000 is shared between ABU, Kayode and Uche. Abu has twice as much as Kayode, and Kayode has twice as much as Uche. What is Kayode's share? A. N80,000 B. N40,000 C. N20,000 D. N10,000
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Detailed Solution\(Abu = 2x\\Kayode = x\\ Uche = \frac{x}{2}\\ 2x+x+\frac{x}{2}=140,000\\ \frac{7x}{2}=140,000\\ 7x = 280,000\\ x=\frac{280,000}{7}\\ x=40,000\)Kayode receives N40,000 |
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| 9. |
I am x years old and my brother is 3 years older how old was my brother last year A. (x - 4) years B. (x + 2) years C. (3x - 1) years D. (3x + 1) years |
C |
| 10. |
For what value of x is the expression \(\frac{2x-1}{x+3}\)not defined? A. 3 B. 2 C. 1/2 D. -3
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Detailed Solutionx + 3 = 0 => x = -3 |
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| 11. |
If x =3, y = 2 and z = 4 what is the value of \(3x^{2}-2y+z\) A. 17 B. 27 C. 35 D. 71
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Detailed Solution\(3x^{2}-2y+z=3(3)^{2}-2(2)+4=27-4+4=27\) |
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| 12. |
Solve the simultaneous equation: x+y=2 and 3x-2y=1 A. x=2 and y=1 B. x=1 and y=1 C. x=1 and y=2 D. x=-1 and y=1
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Detailed Solutionx + y = 2 --- eqn I3x - 2y = 1 --- eqn II Multiply eqn by 2 2x + 2y = 2 --- eqn III Subtract eqn II from eqnI 5x = 5 => x = 1 Substitute 1 for x in eqn 1 1 + y = 2 => y = 1 |
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| 13. |
If \(8^{x+1}=\frac{1}{4}\), find x A. \(-\frac{5}{3}\) B. -1 C. \(-\frac{1}{3}\) D. \(\frac{1}{3}\)
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Detailed Solution\(8^{x+1}=\frac{1}{4}\\2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\\ 3x=-5\Rightarrow x=\frac{5}{3}\) |
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| 14. |
The area of a square field is 110.25m2. Find the cost of fencing it round at N75.00 per meter square A. N1,575.00 B. N3,150.00 C. N4,734.30 D. N8,268.75
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Detailed SolutionN75.00 x 110.25 = N8,268.75 |
Preview displays only 14 out of the 67 Questions