Mathematics (Core)
Paper 1 | Objectives | 50 Questions
WASSCE/WAEC MAY/JUNE
Year: 2019
Level: SHS
Time:
Type: Question Paper
Answers provided
FREE
No description provided
Feedbacks
This paper is yet to be rated
Paper 1 | Objectives | 50 Questions
WASSCE/WAEC MAY/JUNE
Year: 2019
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Norway Kvaroy Arctic Women in Aquaculture Postgraduate Scholarship Program 2022 for African Women
Get full scholarship paid tuition from 5 countries with free education in 2022 for international students
Eat well during in test days for good grades. How can you plan your exam diet with good grades in mind?
| # | Question | Ans |
|---|---|---|
| 1. |
Express, correct to three significant figures, 0.003597. A. 0.359 B. 0.004 C. 0.00360 D. 0.00359
Show Content
Detailed Solution0,00 3597 = 0.00360 to 3 s.f |
|
| 2. |
Evaluate: (0.064) - \(\frac{1}{3}\) A. \(\frac{5}{2}\) B. \(\frac{2}{5}\) C. -\(\frac{2}{5}\) D. -\(\frac{5}{2}\)
Show Content
Detailed Solution(0.064)\(^{- \frac{1}{3}}\)= (\(\frac{64}{1000}\))\(^{-\frac{1}{3}}\) = 3\(\sqrt{\frac{1000}{64}}\) = \(\frac{10}{4}\) = \(\frac{5}{2}\) |
|
| 3. |
Solve: \(\frac{y + 1}{2} - \frac{2y - 1}{3}\) = 4 A. y = 19 B. y = -19 C. y = -29 D. y = 29
Show Content
Detailed Solution\(\frac{y + 1}{2} - \frac{2y - 1}{3}\) = \(\frac{4}{1}\)- \(\frac{3(y + 1) - 2(2y - 1)}{6} = \frac{4}{1}\) 3y + 3 - 4y + 2 = 24 - y + 5 = 24 - y = 24 - 5 = 19 y = - 19 |
|
| 4. |
Simplify, correct to three significant figures, (27.63)\(^2\) - (12.37)\(^2\) A. 614 B. 612 C. 611 D. 610
Show Content
Detailed Solution(27.63)\(^2\) - (12.37)\(^2\)= (27.63 + 12.37)(27.63 - 12.37) = 40 x 15.26 = 610 |
|
| 5. |
If 7 + y = 4 (mod 8), find the least value of y, 10 \(\leq y \leq 30\) A. 11 B. 13 C. 19 D. 21
Show Content
Detailed Solution7 + y = 4 (mod 8)y = 4 - 7 (mod 8) y = -3 + 8 (mod 8) y = 5 + 8 (mod 8) y = 13 |
|
| 6. |
If T = {prime numbers} and M = {odd numbers} are subsets of \(\mu\) = {x : 0 < x < 10} and x is an integer, find (T\(^{\prime}\) \(\mu\) M\(^{\prime}\)). A. {4, 6, 8, 10} B. {1 C. {1, 2, 4, 6, 8, 10} D. {1, 2, 3, 5, 7, 8, 9}
Show Content
Detailed SolutionT = {2, 3, 5, 7}M = {1, 3, 5, 7, 9} \(\mu\) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} T\(^{\prime}\) = = {1, 4, 6, 8, 9, 10} M\(^{\prime}\) = {2, 4, 6, 8, 10} (T\(^{\prime}\) \(\cap\) M\(^{\prime}\)) = {4, 6, 8, 10} |
|
| 7. |
Evaluate; \(\frac{\log_3 9 - \log_2 8}{\log_3 9}\) A. -\(\frac{1}{3}\) B. \(\frac{1}{2}\) C. \(\frac{1}{3}\) D. -\(\frac{1}{2}\)
Show Content
Detailed Solution\(\frac{\log_3 9 - \log_2 8}{\log_3 9}\)= \(\frac{\log_3 3^2 - \log_2 2^3}{\log_3 3^2}\) = \(\frac{2 -3}{2}\) = \(\frac{-1}{2}\) |
|
| 8. |
If 23\(_y\) = 1111\(_{\text{two}}\), find the value of y A. 4 B. 5 C. 6 D. 7
Show Content
Detailed Solution23\(_y\) = 1111\(_{\text{two}}\),2 x y\(^1\) + 3 x y\(^0\) = 1 x 2\(^3\) + 1 x 2\(^1\) + 1 x 2\(^o\) 2y + 3 = 8 + 4 + 2 + 1 2y + 3 = 15 \(\frac{2y}{2}\) \(\frac{12}{2}\) y = 6 |
|
| 9. |
If 6, P, and 14 are consecutive terms in an Arithmetic Progression (AP), find the value of P. A. 9 B. 10 C. 6 D. 8
Show Content
Detailed Solution6, p, 1414 - p = p - 6 14 + 6 = p - 6 14 + 6 = p + p \(\frac{2p}{2}\) = \(\frac{20}{2}\) p = 10 |
|
| 10. |
Evaluate: 2\(\sqrt{28} - 3\sqrt{50} + \sqrt{72}\) A. 4\(\sqrt{7} - 21 \sqrt{2}\) B. 4\(\sqrt{7} - 11 \sqrt{2}\) C. 4\(\sqrt{7} - 9 \sqrt{2}\) D. 4\(\sqrt{7} + \sqrt{2}\)
Show Content
Detailed Solution2\(\sqrt{28} - 3\sqrt{50} + \sqrt{22}\)4\(\sqrt{7} - 15\sqrt{2} + 6\sqrt{2}\) 6\(\sqrt{7} - 9\sqrt{2}\) |
Preview displays only 10 out of the 50 Questions