Mathematics (Core)
Paper 1 | Objectives | 50 Questions
WASSCE/WAEC MAY/JUNE
Year: 2019
Level: SHS
Time:
Type: Question Paper
Answers provided
FREE
No description provided
Feedbacks
This paper is yet to be rated
Paper 1 | Objectives | 50 Questions
WASSCE/WAEC MAY/JUNE
Year: 2019
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
8 Tips To Be More Productive in Test Revision for good grades and higher performance in exams
Five revision strategies that are strange but effective for memorization for high exams performance
The best study methods and strategies and tips for successful exam preparation for good grades
| # | Question | Ans |
|---|---|---|
| 1. |
Express, correct to three significant figures, 0.003597. A. 0.359 B. 0.004 C. 0.00360 D. 0.00359
Show Content
Detailed Solution0,00 3597 = 0.00360 to 3 s.f |
|
| 2. |
Evaluate: (0.064) - \(\frac{1}{3}\) A. \(\frac{5}{2}\) B. \(\frac{2}{5}\) C. -\(\frac{2}{5}\) D. -\(\frac{5}{2}\)
Show Content
Detailed Solution(0.064)\(^{- \frac{1}{3}}\)= (\(\frac{64}{1000}\))\(^{-\frac{1}{3}}\) = 3\(\sqrt{\frac{1000}{64}}\) = \(\frac{10}{4}\) = \(\frac{5}{2}\) |
|
| 3. |
Solve: \(\frac{y + 1}{2} - \frac{2y - 1}{3}\) = 4 A. y = 19 B. y = -19 C. y = -29 D. y = 29
Show Content
Detailed Solution\(\frac{y + 1}{2} - \frac{2y - 1}{3}\) = \(\frac{4}{1}\)- \(\frac{3(y + 1) - 2(2y - 1)}{6} = \frac{4}{1}\) 3y + 3 - 4y + 2 = 24 - y + 5 = 24 - y = 24 - 5 = 19 y = - 19 |
|
| 4. |
Simplify, correct to three significant figures, (27.63)\(^2\) - (12.37)\(^2\) A. 614 B. 612 C. 611 D. 610
Show Content
Detailed Solution(27.63)\(^2\) - (12.37)\(^2\)= (27.63 + 12.37)(27.63 - 12.37) = 40 x 15.26 = 610 |
|
| 5. |
If 7 + y = 4 (mod 8), find the least value of y, 10 \(\leq y \leq 30\) A. 11 B. 13 C. 19 D. 21
Show Content
Detailed Solution7 + y = 4 (mod 8)y = 4 - 7 (mod 8) y = -3 + 8 (mod 8) y = 5 + 8 (mod 8) y = 13 |
|
| 6. |
If T = {prime numbers} and M = {odd numbers} are subsets of \(\mu\) = {x : 0 < x < 10} and x is an integer, find (T\(^{\prime}\) \(\mu\) M\(^{\prime}\)). A. {4, 6, 8, 10} B. {1 C. {1, 2, 4, 6, 8, 10} D. {1, 2, 3, 5, 7, 8, 9}
Show Content
Detailed SolutionT = {2, 3, 5, 7}M = {1, 3, 5, 7, 9} \(\mu\) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} T\(^{\prime}\) = = {1, 4, 6, 8, 9, 10} M\(^{\prime}\) = {2, 4, 6, 8, 10} (T\(^{\prime}\) \(\cap\) M\(^{\prime}\)) = {4, 6, 8, 10} |
|
| 7. |
Evaluate; \(\frac{\log_3 9 - \log_2 8}{\log_3 9}\) A. -\(\frac{1}{3}\) B. \(\frac{1}{2}\) C. \(\frac{1}{3}\) D. -\(\frac{1}{2}\)
Show Content
Detailed Solution\(\frac{\log_3 9 - \log_2 8}{\log_3 9}\)= \(\frac{\log_3 3^2 - \log_2 2^3}{\log_3 3^2}\) = \(\frac{2 -3}{2}\) = \(\frac{-1}{2}\) |
|
| 8. |
If 23\(_y\) = 1111\(_{\text{two}}\), find the value of y A. 4 B. 5 C. 6 D. 7
Show Content
Detailed Solution23\(_y\) = 1111\(_{\text{two}}\),2 x y\(^1\) + 3 x y\(^0\) = 1 x 2\(^3\) + 1 x 2\(^1\) + 1 x 2\(^o\) 2y + 3 = 8 + 4 + 2 + 1 2y + 3 = 15 \(\frac{2y}{2}\) \(\frac{12}{2}\) y = 6 |
|
| 9. |
If 6, P, and 14 are consecutive terms in an Arithmetic Progression (AP), find the value of P. A. 9 B. 10 C. 6 D. 8
Show Content
Detailed Solution6, p, 1414 - p = p - 6 14 + 6 = p - 6 14 + 6 = p + p \(\frac{2p}{2}\) = \(\frac{20}{2}\) p = 10 |
|
| 10. |
Evaluate: 2\(\sqrt{28} - 3\sqrt{50} + \sqrt{72}\) A. 4\(\sqrt{7} - 21 \sqrt{2}\) B. 4\(\sqrt{7} - 11 \sqrt{2}\) C. 4\(\sqrt{7} - 9 \sqrt{2}\) D. 4\(\sqrt{7} + \sqrt{2}\)
Show Content
Detailed Solution2\(\sqrt{28} - 3\sqrt{50} + \sqrt{22}\)4\(\sqrt{7} - 15\sqrt{2} + 6\sqrt{2}\) 6\(\sqrt{7} - 9\sqrt{2}\) |
Preview displays only 10 out of the 50 Questions