Mathematics (Core)
Paper 1 | Objectives | 49 Questions
WASSCE/WAEC MAY/JUNE
Year: 2010
Level: SHS
Time:
Type: Question Paper
Answers provided
FREE
No description provided
Feedbacks
This paper is yet to be rated
Paper 1 | Objectives | 49 Questions
WASSCE/WAEC MAY/JUNE
Year: 2010
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Past questions are effective for revisions for all tests including WAEC, BECE, SAT, TOEFL, GCSE, IELTS
8 Tips To Be More Productive in Test Revision for good grades and higher performance in exams
12 Most Effective Ways to Pass Any Exams Without Studying Hard even when you don't have enough time.
| # | Question | Ans |
|---|---|---|
| 1. |
Simplify 0.000215 x 0.000028 and express your answer in standard form A. 6.03 x 109 B. 6.02 x 109 C. 6.03 x 10-9 D. 6.02 x 10-9
Show Content
Detailed Solution0.000215215 x 0.000028= 215 x 10-4 x 28 x 10-4 = 215 x 28 x 10-6-6 = 6020 x 10-12 = 6.020 x 103 x 10-12 = 6.02 x 103 - 12 = 6.02 x 10-9 |
|
| 2. |
Factorize: x + y - ax = ay A. (x - y)(1 - a) B. (x + y)(1 + a) C. (x + y)(1 - a) D. (x - y)(1 + a)
Show Content
Detailed Solutionx + y - ax = ay= (x + y) -a(x + y) = (x + y)(1 - a) |
|
| 3. |
A car uses one litre of petrol for every 14km. If one of petrol cost N63.00, how far can the car go with N900.00 worth of petrol? A. 420km B. 405km C. 210km D. 200km
Show Content
Detailed Solution1 litre = N63.00xlitres = N900.00 x x N63 = N900 x 1 litre x = \(\frac{900}{63} \times litre\) x = \(\frac{100}{7}\) litres Also, 1 litre = 14km \(\frac{100}{7}\) = y y x 1 litre = \(\frac{100litre}{7}\) x 14km y = 20km |
|
| 4. |
Correct 0.002473 to 3 significant figure A. 0.002 B. 0.0024 C. 0.00247 D. 0.0025 |
C |
| 5. |
Simplify 1\(\frac{1}{2} + 2\frac{1}{3} \times \frac{3}{4} - \frac{1}{2}\) A. -2\(\frac{1}{3}\) B. -2\(\frac{1}{4}\) C. 2\(\frac{1}{8}\) D. 2\(\frac{3}{4}\)
Show Content
Detailed Solution1\(\frac{1}{2} + 2\frac{1}{3} \times \frac{3}{4} - \frac{1}{2}\)\(\frac{3}{2} + \frac{7}{3} \times \frac{3}{4} - \frac{1}{2} = \frac{3}{2} + \frac{7}{4} - \frac{1}{2}\) = \(\frac{6 + 7 - 2}{4} = \frac{11}{4}\) = 2\(\frac{3}{4}\) |
|
| 6. |
The sum of 2 consecutive whole numbers is \(\frac{5}{6}\) of their product, find the numbers A. 3, 4 B. 1, 2 C. 2, 3 D. 0, 1
Show Content
Detailed SolutionLet the no. be x and x + 1x + (x + 1) = \(\frac{5}{6}\) of x(x + 1) 2x + 1 = \(\frac{5}{6}\) x(x + 1) 6(2x + 1) = 5x2 + 5x 12x + 6 = 5x2 + 5x 5x2 + 5x - 12x - 6 = 0 5x2 - 7x - 6 = 0 5x2 - 10x + 3x - 6 = 0 5x(x - 2) + 3(x - 2) = 0 (5x + 3)(x - 2) = 0 (5x + 3)(x - 2) = 0 (5x + 3) = 0 x - 2 = 0 for (5x + 3) = 0 5x = -3 |
|
| 7. |
A casting is made up of Copper and Zinc. If 65% of the casting is Zinc and there are 147g of Copper. What is the mass of the casting? A. 320g B. 420g C. 520g D. 620g
Show Content
Detailed Solution%Zinc + %Copper = 100%65% + %Copper = 100% %Copper = 100% - 65% = 35% %Copper = \(\frac{\text{Mass of % Copper}}{\text{Mass of Casting}}\) x 100% Mass of Casting = \(\frac{147}{35}\) x 100% = 420g |
|
| 8. |
Given that P = {x : 1 \(\leq x \leq 6\)}, and Q = {x : 2 \(\leq x \leq 10\)} where x is an integer. Find n(P \(\cap\) Q) A. 5 B. 6 C. 8 D. 10
Show Content
Detailed SolutionP = {1, 2, 3, 4, 5, 6}; Q = {3, 4, 5, 6, 7, 8, 9}P \(\cap\) Q) = {2, 3, 4, 5, 6} n(P \(\cap\) Q) = 5 |
|
| 9. |
The sum of 6 and one-third of x is one more than twice x, find x A. x = 7 B. x = 5 C. x = 3 D. x = 2
Show Content
Detailed Solution6 = \(\frac{1}{3}x\) = 1 + 2x6 = 1 = \(\frac{2x}{1} - \frac{x}{3}\) 5 = \(\frac{6x - x}{3} = \frac{5x}{3}\) 5 = \(\frac{5x}{3}\) 3 x 5 = 5x 15 = 5x x = \(\frac{15}{5}\) = 3 |
|
| 10. |
Given that = {x: -2 < x \(\leq\) 9}, where x is an integer what is n(T)? A. 9 B. 10 C. 11 D. 12
Show Content
Detailed SolutionT = {-1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9}n(T) = 11 |
Preview displays only 10 out of the 49 Questions