Mathematics (Core)
Paper 1 | Objectives | 49 Questions
WASSCE/WAEC MAY/JUNE
Year: 2017
Level: SHS
Time:
Type: Question Paper
Answers provided
FREE
No description provided
Feedbacks
This paper is yet to be rated
Paper 1 | Objectives | 49 Questions
WASSCE/WAEC MAY/JUNE
Year: 2017
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Managing Stress and anxiety in exams, 10 tips and strategies for Coping exam stress and test anxiety.
Middle East and North Africa MENA Scholarship Program (MSP) initiative provides scholarships
How can past papers boost your revision? See how practicing past test is a good way to get higher grades.
| # | Question | Ans |
|---|---|---|
| 1. |
Express 0.0000407, correct to 2 significant figures A. 0.0 B. 0.00004 C. 0.000041 D. 0.0000407
Show Content
Detailed Solution0.0000407 to 2 s.f0.000041 (2 s.f) |
|
| 2. |
If x varies inversely as y and y varies directly as z, what is the relationship between x and z? A. x \(\alpha\) z B. x \(\alpha\) \(\frac{1}{z}\) C. a \(\alpha\) z\(^2\) D. x \(\alpha\) \(\frac{1}{z^2}\)
Show Content
Detailed Solution\(x \propto \frac{1}{y}\), y \(\propto\) zx = \(\frac{k}{y}\) y = mz Since y = mz, x = \(\frac{k}{mz}\), where k and m are constants. Hence, x \(\propto\) \(\frac{1}{z}\) |
|
| 3. |
Evaluate \(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} - 5 \frac{1}{3}}\) A. \(\frac{14}{15}\) B. \(\frac{13}{15}\) C. \(\frac{4}{5}\) D. \(\frac{11}{15}\)
Show Content
Detailed Solution\(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} - 5 \frac{1}{3}}\) = \(\frac{\frac{26}{5}}{\frac{18}{3}}\) = \(\frac{26}{5} \div \frac{18}{3}\)= \(\frac{13}{15}\) |
|
| 4. |
The ages of Tunde and Ola are in the ratio 1:2. If the ratio of Ola's age to Musa's age is 4:5, what is the ratio of Tunde's age to Musa's age? A. 1 : 4 B. 1 : 5 C. 2 : 5 D. 5 : 2
Show Content
Detailed SolutionTunde: Ola \(\to\) 1 : 2 ; Ola; Musa \(\to\) 4 : 5\(\frac{1}{2}\) x \(\frac{4}{5}\) = \(\frac{2}{5}\) |
|
| 5. |
If M = {x : 3 \(\leq\) x < 8} and N = {x : 8 < x \(\leq\) 12}, which of the following is true?i. 8 \(\in\) M \(\cap\) Nii. 8 \(\in\) M \(\cup\) Niii. M \(\cap\) N = \(\varnothing\) A. iii only B. i and ii C. ii and iii only D. i, ii and iii
Show Content
Detailed SolutionM = {3, 4, 5, 6, 7,}, N = {9, 10, 11, 12} |
|
| 6. |
Given that a = log 7 and b = \(\log\) 2, express log 35 in terms of a and b. A. a + b + 1 B. ab - 1 C. a - b + 1 D. b - a + 1
Show Content
Detailed Solution\(\frac{\log 7 \times \log 10}{\log 2}\)log 7 x log 10 \(\div\) log 2 a + 1 - b a - b + 1 |
|
| 7. |
If x = \(\frac{2}{3}\) and y = - 6, evaluate xy - \(\frac{y}{x}\) A. 0 B. 5 C. 8 D. 9
Show Content
Detailed Solutionx = \(\frac{2}{3}\) and y = - 6xy - \(\frac{y}{x}\) \(\frac{2}{3} - (6)^2 - (-6) \div \frac{2}{3}\) = -4 - (6) x \(\frac{3}{2}\) = -4 - (-6) x \(\frac{3}{2}\) = -4 - (-9) = -4 + 9 = 5 |
|
| 8. |
Solve the equation: \(\frac{1}{5x} + \frac{1}{x}\)= 3 A. \(\frac{1}{5}\) B. \(\frac{2}{5}\) C. \(\frac{3}{5}\) D. \(\frac{4}{5}\)
Show Content
Detailed Solution\(\frac{1}{5x} + \frac{1}{x}\)= 3\(\frac{1 + 5}{5x}\) = 3 6 = 15x x = \(\frac{6}{15}\) = \(\frac{2}{5}\) |
|
| 9. |
A sum of N18,100 was shared among 5 boys and 4 girls with each boy taking N20.00 more than each girl. Find a boy's share. A. N1,820.00 B. 2,000.00 C. N2,020.00 D. N2,040.00
Show Content
Detailed SolutionLet a girl's share = x + 204x + 5(x + 20) = 18,100 4x + 5x + 100 = 18,100 9x + 100 = 18,100 9x = 18,000 x = \(\frac{18,000}{9}\) x = 2,000 \(\therefore\) Each boy gets N(2,000 + 20) = N2,020. |
|
| 10. |
One factor of \(7x^2 + 33x - 10\) is A. 7x + 5 B. x - 2 C. 7x - 2 D. x - 5
Show Content
Detailed Solution\(7x^2 + 33x - 10\)\(7x^2 + 35x - 2x - 10\) 7x (x + 5) - 2 (x + 5) (7x - 2) (x + 5) |
Preview displays only 10 out of the 49 Questions