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Mathematics (Core)
Paper 1 | Objectives | 48 Questions
WASSCE/WAEC MAY/JUNE
Year: 1995
Level: SHS
Time:
Type: Question Paper
Answers provided
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Paper has been added to Favourites!
Paper 1 | Objectives | 48 Questions
WASSCE/WAEC MAY/JUNE
Year: 1995
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
| # | Question | Ans |
|---|---|---|
| 1. |
Find (101\(_2\))\(^2\), expressing the answer in base 2. A. 10101 B. 11001 C. 10010 D. 11101 E. 10110 Detailed SolutionYou can convert it to base 10 and square, then re-convert it after the operation.OR You can multiply it straight applying the rules of binary multiplication. |
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| 2. |
If three children shares N10.50 among themselves in ratio 6:7:8, how much is the largest share? A. N3.00 B. N3.50 C. N4.00 D. N4.50 E. N5.00 Detailed SolutionRatio = 6 + 7 + 8 = 2121 = N10.50 1 = 1050K/21 = 50K 6 = 6 x 50K = N3.00 7 = 7 x 50K = N3.50 8 = 8 x 50K = N4.00 the Largest share = N4.00 |
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| 3. |
Express 0.000834 in standard form A. 8.34 x 10-4 B. 8.34 x 10-3 C. 8.34 x 103 D. 8.34 x 104 E. 8.34 x 106 |
A |
| 4. |
Given that log2a = log84, find a A. 21/3 B. 42/3 C. 42/3 D. 22/3 E. 23 Detailed SolutionLog2a = Log84Log2a = Log882/3 → 2/3Log88 → 2/3 x 1 Log2a = 2/3 Recall; If Logax = y ∴ ay = x Log2a = 2/3 22/3 = a |
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| 5. |
By selling some crates of soft drinks for N600.00, a dealer makes a profit of 50%. How much did the dealer pay for the drinks? A. N1,200.00 B. N900.00 C. N450.00 D. N400.00 E. N200.00 Detailed SolutionS.P = N600.00(100 + 50)% = N600 150% = N600 1% = \(\frac{600}{150}\) 100% = \(\frac{600}{150} \times 100%\) = N400 |
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| 6. |
Find the nth term Un of the A.P., 11, 4, -3,....... . A. Un=19+7n B. Un=19-7n C. Un=18+7n D. Un= 18-7n E. Un= 17-7n Detailed SolutionA.P 11, 4, -31st term = 11 A.P = a, a + d, a + 2d ...... a + (n - 1)d If a = 11 a + d = 4 d = 4 - 11 = -7 nth term = a + (n-1)d = 11 + (n-1)(-7) = 11 - 7n + 7 = 18 - 7n |
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| 7. |
Lf 16/9 , x, 1, y are in Geometric Progression (GP), find the product of x and y. A. 9/16 B. 3/4 C. 1 D. 4/3 E. 16/6 Detailed Solution16/9, x, 1, y => a, ar, ar2, ar3ar2 = 1 => 16r2/9 = 1 => 16r2 9 => r2 = 9/16 => r = 3/4 ar2 = y = ar2 x r = 1 x 3/4 = 3/4 x xy = 4/3 x 3/4 = 1 |
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| 8. |
If R = [2, 4, 6, 7] and S = [1, 2, 4, 8], then R∪S equal A. [1,2,4,6,7,8] B. [1,2,4,7,8] C. [1,4.7,8] D. [2.6.7] E. [2.4] Detailed SolutionR = {2, 4, 6, 7}; S = {1, 2, 4, 8}R \(\cup\) S = {1, 2, 4, 6, 7, 8} |
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| 9. |
Find the value(s) of x for which the expression is undefined: \(\frac{6x - 1}{x^2 + 4x - 5}\) A. +4 or+1 B. -5 or +1 C. -5 or -1 D. +5 or -1 E. \(\frac{1}{6}\) Detailed Solution\(\frac{6x - 1}{x^2 + 4x - 5}\)The expression is undefined when \(x^2 + 4x - 5 = 0\) \(x^2 + 5x - x - 5 = 0\) \(x(x + 5) - 1(x + 5) = 0\) \((x - 1)(x + 5) = 0\) The expression is undefined when x = 1 or -5. |
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| 10. |
 Which of the following could be the inequality illustrated in the sketch graph above? A. y≥2x+3 B. y≤-3x+3 C. y < 3x+2 D. y≤x +3 E. y≥3x+2. Detailed SolutionGradient of the line = \(\frac{3 - 0}{0 - 1}\)= -3 y = -3x + b. Using (1,0), we have 0 = -3(1) + b 0 = -3 + b b = 3 y = -3x + 3 \(\therefore\) The graph illustrates y \(\leq\) -3x + 3. |
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