Paper 1 | Objectives | 48 Questions
JAMB Exam
Year: 2012
Level: SHS
Time:
Type: Question Paper
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# | Question | Ans |
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1. |
Convert 112\(_6\) to a number in base three A. 2211 B. 2121 C. 1212 D. 1122
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Detailed SolutionFirst, convert to base 10112\(_6\) = (1 x 6\(^2\)) + (1 x 6\(^1\)) + (2 x 6\(^0\)) = 36 + 6 + 2 = 44\(_{10}\) \(\begin{array}{c|c} 3 & 44 \\ \hline 3 & 14 & r 2 \\ \hline 3 & 4 & r 2 \\ \hline 3 & 1 & r 1 \\ \hline 3 & 0 & r 1 \end{array}\) Ans = 1122 = D There is an explanation video available below. |
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2. |
Simply \(\frac{2\frac{2}{3} \times 1\frac{1}{2}}{4\frac{4}{5}}\) A. \(1\frac{1}{4}\) B. \(1\frac{1}{6}\) C. \(\frac{5}{6}\) D. \(\frac{4}{5}\) |
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3. |
Evaluate \(\frac{21}{9}\) to 3 significant figures A. 2.30 B. 2.31 C. 2.32 D. 2.33
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Detailed Solution\(\frac{21}{9} = \frac{7}{3}\)= 2.33 (to 3 sig. figs) There is an explanation video available below. |
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4. |
A man earns N3,500 per month out of which he spends 15% on his children's education. If he spends additional N1,950 on food, how much does he have left? A. N525 B. N1,025 C. N1,950 D. N2,975 |
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5. |
If 27\(^{x + 2}\) \(\div\) 9\(^{x + 1}\) = 3\(^{2x}\), find x. A. 3 B. 4 C. 5 D. 6
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Detailed Solution\(27^{x + 2} \div 9^{x + 1} = 3^{2x}\)\(3^{3(x + 2)} \div 3^{2(x + 1)} = 3^{2x}\) \(3^{3x + 6} \div 3^{2x + 2} = 3^{2x}\) \(\therefore (3x + 6) - (2x + 2) = 2x\) \(x + 4 = 2x \implies x = 4\) There is an explanation video available below. |
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6. |
If log3x2 = -8, what is x? A. \(\frac{1}{3}\) B. \(\frac{1}{9}\) C. \(\frac{1}{27}\) D. \(\frac{1}{81}\) |
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7. |
Simplify \((\sqrt{6} + 2)^2 - (\sqrt{6} - 2)^2\) A. \(2\sqrt{6}\) B. \(4\sqrt{6}\) C. \(8\sqrt{6}\) D. \(16\sqrt{6}\) |
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8. |
If P is a set of all prime factors of 30 and Q is a set of all factors of 18 less than 10, find P \(\cap\) Q A. {3} B. {2,3} C. {2,3,5} D. {1,2}
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Detailed SolutionP = {2,3,5}Q = {2,3,6,9} P \(\cap\) Q = {2,3} There is an explanation video available below. |
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9. |
In a class of 46 students, 22 play football and 26 play volleyball. If 3 students play both games, how many play neither? A. 1 B. 2 C. 3 D. 4 |
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10. |
Make 'n' the subject of the formula if w = \(\frac{v(2 + cn)}{1 - cn}\) A. \(\frac{1}{c}(\frac{w - 2v}{v + w})\) B. \(\frac{1}{c}(\frac{w - 2v}{v - w})\) C. \(\frac{1}{c}(\frac{w + 2v}{v - w})\) D. \(\frac{1}{c}(\frac{w + 2v}{v + w})\) |
Preview displays only 10 out of the 48 Questions