Paper 1  Objectives  48 Questions
JAMB Exam
Year: 1982
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
8 Tips To Be More Productive in Test Revision for good grades and higher performance in exams
Past questions are effective for revisions for all tests including WAEC, BECE, SAT, TOEFL, GCSE, IELTS
These are the best study techniques and methods that get higher grades in any school tests or exams.
#  Question  Ans 

1. 
Rationalize the expression \(\frac{1}{\sqrt{2} + \sqrt{5}}\) A. \(\frac{1}{3}\)(\(\sqrt{5}  \sqrt{2}\) B. \(\frac{\sqrt{2}}{3}\) + \(\frac{\sqrt{5}}{5}\) C. \(\sqrt{2}  \sqrt{5}\) D. 5(\(\sqrt{2}  \sqrt{5}\) E. \(\frac{1}{3}\)(\(\sqrt{2}  \sqrt{5}\)
Show Content
Detailed Solution\(\frac{1}{\sqrt{2} + \sqrt{5}}\)\(\frac{1}{\sqrt{2} + \sqrt{5}} \times \frac{(\sqrt{2}  \sqrt{5})}{(\sqrt{2}  \sqrt{5})}\) = \(\frac{\sqrt{2}  \sqrt{5}}{2  5}\) = \(\frac{\sqrt{2}  \sqrt{5}}{3}\) = \(\frac{1}{3} (\sqrt{5}  \sqrt{2})\) 

2. 
Simplify 3  2 \(\div\) \(\frac{4}{5}\) + \(\frac{1}{2}\) A. 1\(\frac{3}{4}\) B. 1 C. 1\(\frac{3}{10}\) D. 1 E. 1\(\frac{9}{10}\)
Show Content
Detailed Solution3  2 \(\div\) (\(\frac{4}{5}\)) + \(\frac{1}{2}\)3  (2 x \(\frac{5}{4}\)) + \(\frac{1}{2}\) = 3  \(\frac{10}{4}\) + \(\frac{1}{2}\) = 3  \(\frac{5}{2}\) + \(\frac{1}{2}\) = \(\frac{6  5 + 1}{2}\) = \(\frac{2}{2}\) = 1 

3. 
If N560.70 is shared in the ratio 7 : 2 : 1, what is the smallest share? A. N392.49 B. N56.70 C. N113.40 D. N112.14 E. N56.07
Show Content
Detailed Solution7 + 2 + 1 = 10\(\frac{1}{10}\) x 560.70 = N56.07 

4. 
Seven years ago, the age of a father was three times that of his son, but in six years time the age of the son will be half that of his father, representing the present ages of the father and son by x and y, respectively, the two equations relating x and y are A. 3y  x = 0; 2y  x = 0 B. 3y  x = 14; x  2y = 6 C. 3y  x =7; x  2y = 6 D. 3y  x = 14; y  2x = 6 E. x + 3y = 7; x = 2y = 12
Show Content
Detailed Solution7 years ago, Father(x  7) years old, Son (y  7) yearsx  7 = 3(y  7) x  7 = 3y  21 3y  x = 7 + 21 = 14 3y  x = 14 ... (1) In six years time, x + 6 = 2(y + 6) x + 6 = 2y + 12 2y + 12 = x + 6 12  6 = x  2y 6 = x  2y ... (2) 

5. 
The factors of 6x  5  x2 are A. (x + 3)(x + 2) B. (x + 5)(x + 1) C. (x  5)(1  x) D. (x + 1)(x + 5)
Show Content
Detailed Solution6x  5  x2 = (1)(x2  5 + 6x)= x2  6x + 5 = (x  5)(x  1) (x  1) = 1  x = (x  5)(1  x) 

6. 
The solution of the quadratic equation bx2 + cx + a = 0 is given by A. x = b \(\pm\) \(\frac{\sqrt{b^2  4ac}}{2a}\) B. x = c \(\pm\) \(\frac{\sqrt{b^2  4ab}}{2b}\) C. x = c \(\pm\) \(\frac{\sqrt{c^2  4ab}}{2b}\) D. x = b \(\pm\) \(\frac{\sqrt{b^2  4ac}}{2b}\)
Show Content
Detailed Solutionbx2 + cx + a = 0a = b; b = c; c = a x = b \(\pm\) \(\frac{\sqrt{b^2  4ac}}{2a}\) x = c \(\pm\) \(\frac{\sqrt{c^2  4ab}}{2b}\) 

7. 
The graphical method of solving the equation x3 + 3x2 + 4x  28 = 0 is by drawing the graphs of the curves A. y = x^{3} and y = 3x^{2} + x  28 B. y = x^{3} + 3x^{2} + 4x + 4 and the line y = \(\frac{28}{x}\) C. y = x^{3} + 3x^{2} + 4x and y D. y = x^{2} + 3x + 4 and y = \(\frac{28}{x}\) E. y = x^{2} + 3x + 4 and line y = 28x
Show Content
Detailed SolutionThe graphical method of solving the equation x3 + 3x2 + 4x  28 = 0 is by drawing the graphs of the curvesy = x2 + 3x + 4 and y = \(\frac{28}{x}\)`. 

8. 
Write the equation 2 log2x  x log2(1 + y) = 3 in a form not involving logarithms A. 2^{x}(1 + y) = 3 B. 2^{x}  x(1 + y) = 8 C. x^{2} = 8(1 + y)^{x} D. x^{2}  x(1 + y) = 8 E. x^{2}  (1 + y)^{2} = 8
Show Content
Detailed Solution2log2 x  x log2 (1 + y) = 3log2 \(\frac{x^2}{(1 + y)^x}\) = 3 = \(\frac{x^2}{(1 + y)^x}\) = 23 = 8 = x2 = 8(1 + y)x 

9. 
Find \(\alpha\) and \(\beta\) such that x\(\frac{3}{8}\) x y\(\frac{6}{7}\) x (\(\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}\))\(\frac{1}{9}\) = \(\frac{y^{\alpha}}{y^{\beta}}\) A. \(\alpha\) = 1, \(\beta\) = \(\frac{5}{7}\) B. \(\alpha\)= 1, \(\beta\) = \(\frac{5}{7}\) C. \(\alpha\)= \(\frac{3}{5}\), \(\beta\) = 6 D. \(\alpha\)= 1, \(\beta\) = \(\frac{3}{5}\)
Show Content
Detailed Solutionx\(\frac{3}{8}\) x y\(\frac{6}{7}\) x (\(\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}\))\(\frac{1}{9}\) = \(\frac{y^{\alpha}}{y^{\beta}}\)x\(\frac{3}{8}\) x y\(\frac{6}{7}\) x y\(\frac{1}{7}\) = x\(\alpha\) = x\(\frac{3}{8}\) + \(\frac{5}{8}\) + y\(\frac{6}{7}\) + \(\frac{1}{7}\) = x\(\alpha\)y\(\beta\) x1y\(\frac{5}{7}\) = x\(\alpha\)y\(\beta\) \(\alpha\) = 1, \(\beta\) = \(\frac{5}{7}\) 

10. 
Which of the following lines is not parallel to the line 3y + 2x + 7 = 0? A. 3y + 2x  7 = 0 B. 9y + 6x + 17 = 0 C. 24y + 16x + 19 = 0 D. 3y  2x + 7 = 0 E. 15y + 10x  13 = 0
Show Content
Detailed SolutionTwo lines are said to be parallel if the slope of the two lines are equal.The equation : \(3y + 2x + 7 = 0\) \(3y = 2x  7\) \(y = \frac{2}{3} x  \frac{7}{3}\) \(\frac{\mathrm d y}{\mathrm d x} =  \frac{2}{3}\) All the options have the same slope except \(3y  2x + 7 = 0\). 
Preview displays only 10 out of the 48 Questions