Paper 1  Objectives  47 Questions
JAMB Exam
Year: 2007
Level: SHS
Time:
Type: Question Paper
Source: Nigeria
Answers provided
No description provided
This paper is yet to be rated
The goal of mocks tests is to create a benchmarking tool to help students assess their performances.
The best study methods and strategies and tips for successful exam preparation for good grades
8 Tips To Be More Productive in Test Revision for good grades and higher performance in exams
#  Question  Ans 

1. 
If 5, 8, 6 and 2 occur with frequencies 3, 2, 4 and 1 respectively. Find the product of the modal and the median number A. 36 B. 48 C. 30 D. 40
Show Content
Detailed Solution2, 5, 5, 6, 6, ,6, 6, 8, 8 Position of median = ^{N}/_{2} = ^{8}/_{2} = 4th and 5th ∴Median = (6+6) / 2 = ^{12}/_{2} = 6 Mode the item that repeat itself most = 6 ∴Product of modal and median number = 6 x 6 = 36 

2. 
In a basket, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random. What is the probability that the fruit is either a grape or a banana A. ^{6}/_{30} B. ^{5}/_{30} C. ^{17}/_{30} D. ^{11}/_{30}
Show Content
Detailed SolutionNumber of grapes = 6Number of banana = 11 Number of oranges = 13 Total = 30 P(Grape) = ^{6}/_{30}, P(Banana) = ^{11}/_{30} P(Orange) = ^{13}/_{30} ∴P(Either grape or banana) = ^{6}/_{30} + ^{11}/_{30} = ^{17}/_{30} 

3. 
The histogram above represents the weights of students who traveled out to their school for an examination. How many people made the trip? A. 78 B. 38 C. 29 D. 69
Show Content
Detailed Solutionstudents who made the trip = 2 + 3 + 4 + 5 + 6 + 8 + 1 = 29 

4. 
A senatorial candidate had planned to visit seven cities prior to a primary election. However, he could only visit four of the cities. How many different itineraries could be considered? A. 640 B. 840 C. 520 D. 920
Show Content
Detailed SolutionNumber of itineraries = ^{7}P_{4}=\(\frac{7!}{(74)!}\\ =\frac{7!}{3!}\\ =\frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}\\ =840\) 

5. 
The pie chart above illustrate the amount of private time a student spends in a week studying various subjects. Find the value of k A. 90^{o} B. 60^{o} C. 30^{o} D. 40^{o}
Show Content
Detailed SolutionK + 5K + 3K + 75 + 105 = 360 (at a point)6K + 180 = 360 6K = 360  180 6K = 180 k = 180/6 = 30^{o} 

6. 
The table above shows the number of pupils in each age group in a class. What is the probability that a pupil chosen at random is at least 11 years old? A. ^{27}/_{40} B. ^{17}/_{20} C. ^{3}/_{30} D. ^{33}/_{40}
Show Content
Detailed SolutionP(At least 11 yrs) = P(11yrs) + P(12yrs)= 27/40 + 7/40 = 34/40 = 17/20 

7. 
What is the mean deviation of 3, 5, 8, 11, 12 and 21? A. 4.7 B. 60 C. 3.7 D. 10
Show Content
Detailed Solutionmean deviation \(= \frac{\sumx\bar{x}}{n} = \frac{28}{6}\) = 4.7 

8. 
Table: A. 15 B. 13 C. 11 D. 8
Show Content
Detailed SolutionTotal mark scored = 200∴200 = 15 + 4y  4 + 5y + 54 + 28 + 8 200 = 9y + 101 200  101 = 9y 99 = 9y ∴y = 11 

9. 
In how many ways can 6 subjects be selected from 10 subjects for an examination A. 218 B. 216 C. 215 D. 210
Show Content
Detailed Solution\(^{10}C_6 = \frac{10!}{(106)!6!}=\frac{10!}{4!6!}\\=\frac{(10\times 9\times 8\times 7 \times 6!)}{4\times 3\times 2\times 1\times 6!}\\ =210\) 

10. 
Integrate \(\frac{x^2 \sqrt{x}}{x}\) with respect to x A. \(\frac{x^2}{2}2\sqrt{x}+K\) B. \(\frac{2(x^2  x)}{3x}+K\) C. \(\frac{x^2}{2}\sqrt{x}+K\) D. \(\frac{(x^2  x)}{3x}+K\)
Show Content
Detailed Solution\(\int \frac{x^2 \sqrt{x}}{x} = \int \frac{x^2}{x}  \frac{x^{\frac{1}{2}}}{x}\\\int x  x^{\frac{1}{2}}\\ =\left(\frac{1}{2}\right)x^2  \frac{x^{\frac{1}{2}}}{\frac{1}{2}}+K\\ =\frac{x^2}{2}2x^{\frac{1}{2}}+K\\ =\frac{x^2}{2}2\sqrt{x}+K\) 
Preview displays only 10 out of the 47 Questions