Mathematics (Core), 2006, WASSCE/WAEC MAY/JUNE, Exam, Paper 1 | Objectives

Paper Info

Year :

2006

Title :

Mathematics (Core)

Exam :

WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

41 - 46 of 46 Questions

#	Question	Ans
41.	In the diagram, PQR is a straight line, QRST is a parallelogram, < TPQ = 72^o and < RST = 126^o. What type of triangle is \(\bigtriangleup\) PQT? A. An equilateral triangle B. A right-angled triangle C. An isosceles triangle D. A scalene triangle	C
42.	How many pupils took the test? A. 36 B. 38 C. 39 D. 40 Show Content Detailed Solution No. of pupils = 1 + 3 + 4 + 7 + 8 + 6 + 6 + 4 + 1 = 40	D
43.	If the pass mark was 4. What percentage of the pupils failed the test? A. 20.0% B. 37% C. 62.5% D. 80.0% Show Content Detailed Solution No. of pupils that failed = 1 + 3 + 4 + 8 % failed = \(\frac{8}{40} \times 100\)% = 20.0%	A
44.	The diagram shows an arc MN of a circle, centre O, with 10cm. If < MON = 72^o. calculate the length of the arc, correct to three significant figures. [Take \(\pi = \frac{22}{7}\)] A. 6.28cm B. 12.6cm C. 22.6cm D. 62.8cm Show Content Detailed Solution Length of arc = \(\frac{\theta}{360 \times 2 \pi r}\) = \(\frac{72}{360} \times 2 \times \frac{22}{7} \times 10\)cm = 12.57 = 12.6cm(3 s.f)	B
45.	In the diagram what is x + y in terms of z? A. 180^o - z B. 180^o + z C. z - 180^o D. z Show Content Detailed Solution x + y + z = 180(sum of angles in a \(\bigtriangleup\)) x + y = 180 - z	A
46.	In the diagram \|XY\| = 12cm, \|XZ\| = 9cm, \|ZN\| = 3cm and ZY\|\|NM, calculate \|MY\| A. 3cm B. 4cm C. 5cm D. 6cm Show Content Detailed Solution \(\frac{\|YM\|}{\|YX\|} = \frac{\|ZM\|}{\|ZX\|}\) \(\frac{\|YM\|}{12} = \frac{3}{9}\) \|YM\| = 3 x \(\frac{12}{9}\) \|MY\| = 4cm	B

41.	In the diagram, PQR is a straight line, QRST is a parallelogram, < TPQ = 72^o and < RST = 126^o. What type of triangle is \(\bigtriangleup\) PQT? A. An equilateral triangle B. A right-angled triangle C. An isosceles triangle D. A scalene triangle	C
42.	How many pupils took the test? A. 36 B. 38 C. 39 D. 40 Show Content Detailed Solution No. of pupils = 1 + 3 + 4 + 7 + 8 + 6 + 6 + 4 + 1 = 40	D
43.	If the pass mark was 4. What percentage of the pupils failed the test? A. 20.0% B. 37% C. 62.5% D. 80.0% Show Content Detailed Solution No. of pupils that failed = 1 + 3 + 4 + 8 % failed = \(\frac{8}{40} \times 100\)% = 20.0%	A

44.	The diagram shows an arc MN of a circle, centre O, with 10cm. If < MON = 72^o. calculate the length of the arc, correct to three significant figures. [Take \(\pi = \frac{22}{7}\)] A. 6.28cm B. 12.6cm C. 22.6cm D. 62.8cm Show Content Detailed Solution Length of arc = \(\frac{\theta}{360 \times 2 \pi r}\) = \(\frac{72}{360} \times 2 \times \frac{22}{7} \times 10\)cm = 12.57 = 12.6cm(3 s.f)	B
45.	In the diagram what is x + y in terms of z? A. 180^o - z B. 180^o + z C. z - 180^o D. z Show Content Detailed Solution x + y + z = 180(sum of angles in a \(\bigtriangleup\)) x + y = 180 - z	A
46.	In the diagram \|XY\| = 12cm, \|XZ\| = 9cm, \|ZN\| = 3cm and ZY\|\|NM, calculate \|MY\| A. 3cm B. 4cm C. 5cm D. 6cm Show Content Detailed Solution \(\frac{\|YM\|}{\|YX\|} = \frac{\|ZM\|}{\|ZX\|}\) \(\frac{\|YM\|}{12} = \frac{3}{9}\) \|YM\| = 3 x \(\frac{12}{9}\) \|MY\| = 4cm	B