Year :
2007
Title :
Mathematics (Core)
Exam :
WASSCE/WAEC MAY/JUNE
Paper 1 | Objectives
21 - 30 of 67 Questions
| # | Question | Ans |
|---|---|---|
| 21. |
If p \(\alpha \frac{I}{Q}\) which of the following is true? A. q \(\alpha p^2\) B. q \(\alpha \frac{1}{p^2}\) C. q \(\alpha \sqrt{p}\) D. q \(\alpha \frac{1}{p}\) Detailed Solutionp \(\alpha \frac{I}{Q}\); p \(\frac{k}{q}\) (where k is constant)q = \(\frac{k}{p}\) q \(\alpha \frac{1}{p}\) |
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| 22. |
Simplify 3\(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\), leaving your answer in surd form. A. 29\(\sqrt{5}\) B. 14\(\sqrt{15}\) C. 12\(\sqrt{15}\) D. 11\(\sqrt{15}\) Detailed Solution3 \(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\)= 3 x \(\sqrt{9 \times 5} - 12 \times \sqrt{5} + 16 \times \sqrt{4 \times 5}\) = 3 x 3 x \(\sqrt{5} - 12 \times \sqrt{5} + 16 \times 2 \times \sqrt{5}\) = 9\(\sqrt{5} - 2 \sqrt{5} + 32 \sqrt{5}\) = 9\(\sqrt{5} + 32\sqrt{5} - 12\sqrt{5}\) = 29\(\sqrt{5}\) |
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| 23. |
Which of the following statement is true for the ste P = {-3.2 \(\leq\) x < 5} where x is an integer? A. least value of x is -3.2 B. least value of x is -3 C. greatest value of x is 4.9 D. greatest value of x is 5 Detailed Solutionp = {-3.2.....4.9}; Since x is an integerleast value of x is -3 |
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| 24. |
Simplify \(\frac{3x^3}{(3x)^3}\) A. 1 B. \(\frac{1}{3}\) C. \(\frac{1}{9}\) D. \(\frac{1}{27}\) Detailed Solution\(\frac{3x^3}{(3x)^3}\) = \(\frac{3 \times x^3}{3^3 \times x^3}\)= \(\frac{3 \times x^3}{3 \times 3 \times 3 \times x^3}\) = \(\frac{1}{3^2}\) = \(\frac{1}{9}\) |
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| 25. |
N140,000 is shared between Abu, Kayode and Uche. Abu has twice as much as Kayode and Kayode has twice as much as Uche. What is Kayode'sshare? A. N80,000 B. N40,000 C. N2,000 D. 10,000 Detailed SolutionLet Abu's share = 2x;Kayode's = x Uche's share = \(\frac{x}{2}\) Total: 2x + x + \(\frac{x}{2}\) = N140,000 \(\frac{7x}{2}\) = N140,000 x = \(\frac{280,000}{7}\) = N40,000 Kayode's share = N40,000 |
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| 26. |
I am x years old and my brother is 3 years older. How old was my brother last year? A. (x - 4)years B. (x + 2) years C. (3x - 10years D. (3x + 1)years Detailed SolutionI am x years old; My brother = 3 + x; My brotherlast year = (3 + x) - 1 = x + 3 - 1 = (x + 2) years |
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| 27. |
For what value of x is the expression \(\frac{2x - 1}{x + 3}\) not defined? A. 3 B. 2 C. \(\frac{1}{2}\) D. -3 Detailed Solution\(\frac{2x - 1}{x + 3}\) not definedx + 3 = 0 x = -3 |
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| 28. |
If x = 3, Y = 2 and z = 4, what is the value of 3x2 - 2y + z? A. 17 B. 27 C. 35 D. 71 Detailed Solutionx = 3, y = 2, z = 43x2 - 2y + z = 3(3)2 - 2(2) + 4 3(9) - 4 + 4 = 27 |
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| 29. |
Solve the simultaneous equations x + y = 2 and 3x - 2y = 1 A. x = 2 and y = 1 B. x = 1 and y = 1 C. x = 1 and y = 2 D. x = -1 and y = 1 Detailed Solutionx + y = 2........... (i)3x - 2y = 1......(ii) From (i): x = 2 - y ..........(iii) subt. (2 - y) for x in (ii) 3(2 - y) 2y = 1 6 - 3y - 2y = 1 -5y = 1 - 6 = -5 y = \(\frac{-5}{-5}\) = 1 subst. (i) for y in (iii) x = 2 - 1 = 1 x = 1, y = 1 |
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| 30. |
If 8x-1 = \(\frac{1}{4}\), find x A. -\(\frac{-5}{3}\) B. -1 C. -\(\frac{1}{3}\) D. \(\frac{1}{3}\) Detailed Solution8x-1 = \(\frac{1}{4}\)23(x - 1 = 2-2 3x - 3 = -2 3x = -2 + 3 3x = 1 x = \(\frac{1}{3}\) |
| 21. |
If p \(\alpha \frac{I}{Q}\) which of the following is true? A. q \(\alpha p^2\) B. q \(\alpha \frac{1}{p^2}\) C. q \(\alpha \sqrt{p}\) D. q \(\alpha \frac{1}{p}\) Detailed Solutionp \(\alpha \frac{I}{Q}\); p \(\frac{k}{q}\) (where k is constant)q = \(\frac{k}{p}\) q \(\alpha \frac{1}{p}\) |
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| 22. |
Simplify 3\(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\), leaving your answer in surd form. A. 29\(\sqrt{5}\) B. 14\(\sqrt{15}\) C. 12\(\sqrt{15}\) D. 11\(\sqrt{15}\) Detailed Solution3 \(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\)= 3 x \(\sqrt{9 \times 5} - 12 \times \sqrt{5} + 16 \times \sqrt{4 \times 5}\) = 3 x 3 x \(\sqrt{5} - 12 \times \sqrt{5} + 16 \times 2 \times \sqrt{5}\) = 9\(\sqrt{5} - 2 \sqrt{5} + 32 \sqrt{5}\) = 9\(\sqrt{5} + 32\sqrt{5} - 12\sqrt{5}\) = 29\(\sqrt{5}\) |
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| 23. |
Which of the following statement is true for the ste P = {-3.2 \(\leq\) x < 5} where x is an integer? A. least value of x is -3.2 B. least value of x is -3 C. greatest value of x is 4.9 D. greatest value of x is 5 Detailed Solutionp = {-3.2.....4.9}; Since x is an integerleast value of x is -3 |
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| 24. |
Simplify \(\frac{3x^3}{(3x)^3}\) A. 1 B. \(\frac{1}{3}\) C. \(\frac{1}{9}\) D. \(\frac{1}{27}\) Detailed Solution\(\frac{3x^3}{(3x)^3}\) = \(\frac{3 \times x^3}{3^3 \times x^3}\)= \(\frac{3 \times x^3}{3 \times 3 \times 3 \times x^3}\) = \(\frac{1}{3^2}\) = \(\frac{1}{9}\) |
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| 25. |
N140,000 is shared between Abu, Kayode and Uche. Abu has twice as much as Kayode and Kayode has twice as much as Uche. What is Kayode'sshare? A. N80,000 B. N40,000 C. N2,000 D. 10,000 Detailed SolutionLet Abu's share = 2x;Kayode's = x Uche's share = \(\frac{x}{2}\) Total: 2x + x + \(\frac{x}{2}\) = N140,000 \(\frac{7x}{2}\) = N140,000 x = \(\frac{280,000}{7}\) = N40,000 Kayode's share = N40,000 |
| 26. |
I am x years old and my brother is 3 years older. How old was my brother last year? A. (x - 4)years B. (x + 2) years C. (3x - 10years D. (3x + 1)years Detailed SolutionI am x years old; My brother = 3 + x; My brotherlast year = (3 + x) - 1 = x + 3 - 1 = (x + 2) years |
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| 27. |
For what value of x is the expression \(\frac{2x - 1}{x + 3}\) not defined? A. 3 B. 2 C. \(\frac{1}{2}\) D. -3 Detailed Solution\(\frac{2x - 1}{x + 3}\) not definedx + 3 = 0 x = -3 |
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| 28. |
If x = 3, Y = 2 and z = 4, what is the value of 3x2 - 2y + z? A. 17 B. 27 C. 35 D. 71 Detailed Solutionx = 3, y = 2, z = 43x2 - 2y + z = 3(3)2 - 2(2) + 4 3(9) - 4 + 4 = 27 |
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| 29. |
Solve the simultaneous equations x + y = 2 and 3x - 2y = 1 A. x = 2 and y = 1 B. x = 1 and y = 1 C. x = 1 and y = 2 D. x = -1 and y = 1 Detailed Solutionx + y = 2........... (i)3x - 2y = 1......(ii) From (i): x = 2 - y ..........(iii) subt. (2 - y) for x in (ii) 3(2 - y) 2y = 1 6 - 3y - 2y = 1 -5y = 1 - 6 = -5 y = \(\frac{-5}{-5}\) = 1 subst. (i) for y in (iii) x = 2 - 1 = 1 x = 1, y = 1 |
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| 30. |
If 8x-1 = \(\frac{1}{4}\), find x A. -\(\frac{-5}{3}\) B. -1 C. -\(\frac{1}{3}\) D. \(\frac{1}{3}\) Detailed Solution8x-1 = \(\frac{1}{4}\)23(x - 1 = 2-2 3x - 3 = -2 3x = -2 + 3 3x = 1 x = \(\frac{1}{3}\) |