Year : 
1994
Title : 
Mathematics (Core)
Exam : 
WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

31 - 40 of 50 Questions

# Question Ans
31.

A circle has radius x cm. What is the area of a sector of the circle with angle 135°, leaving the answer in terms of x and π?

A. \( \frac{\pi x^2}{8} \)

B. \( \frac{3\pi x^2}{8} \)

C. \( \frac{5\pi x^2}{8} \)

D. \( \frac{3\pi x}{8} \)

Detailed Solution

A = θ 360 x πr2 = 135 360 x π x x2 = (3πx2)/8
32.

In the diagram, PQRS is a trapezium with PQ||SR. STR is a straight line, PSHQT, PTHQR. If |PQ| = 12cm and the height of the trapezium is 9cm, find its area.

A. 96cm2

B. 108cm2

C. 135cm2

D. 162cm2

E. 216cm2

Detailed Solution

A = 1/2(A + B)h = 1/2(24 + 12) x 9 = 162
33.

Two solid spheres have volumes 250cmo and 128cmo respectively. Find the ratio of their radii.

A. 125:64

B. 25:16

C. 2:1

D. 4:3

E. 5:4

Detailed Solution

4/3πR3/4/3πr3
=
250/180
= (R/r)3 = 5:4

34.

In the diagram ST and QR are parallel. |PS| = 6cm, |SQ| = 8cm and |PR] = 18 2/3. Find |PT|

A. 7cm

B. 8cm

C. 8 2/3cm

D. 10cm

E. 10 2/3cm

B

35.

In the diagram, PQ||RS and angles are as shown. Find x

A. 145o

B. 150o

C. 155o

D. 160o

E. 165o

Detailed Solution

Join PR to a pentagon
90 + 90 + 140 + 55 + x = 540o
x = 165o
36.

IF the exterior angles of a quadilateral are yo, (2y + 5)o , (y + 15)o and (3y - 10)o, find yo

A. 61.43

B. 60

C. 52.86

D. 51.43

E. 50

E

37.

The sum of the angles of regular polygon is 2520o. How many sides does the polygon have?

A. 20

B. 18

C. 17

D. 16

E. 15

Detailed Solution

2(n-2) x 90o = 2520; n = 16
38.

Which of the following is not a property of all parallelogram?

A. the diagonal bisects each other

B. Each diagonal bisects the area

C. the diagonal cut at right angles

D. The opposite sides are equal

E. The opposite angles are equal

C

39.

In the diagram above, PQ is the tangent to the circle RST at T.|ST| = ST and ∠RTQ = 68o. Find ∠PTS

A. 68o

B. 62o

C. 61o

D. 56o

E. 34o

Detailed Solution

∠TSR = 68o ∴ STR =
180-68/2
= 56o

PTS= 180-(68+56) = 56o
40.

The diagram above shows a circle PQRS in which ∠PRQ = 54o and ∠SPQ = 97o. Find ∠PQS

A. 61o

B. 51o

C. 43o

D. 39o

E. 29o

Detailed Solution

PSQ = 54o ∴PQS = 180o - (97 + 54)o = 29o
31.

A circle has radius x cm. What is the area of a sector of the circle with angle 135°, leaving the answer in terms of x and π?

A. \( \frac{\pi x^2}{8} \)

B. \( \frac{3\pi x^2}{8} \)

C. \( \frac{5\pi x^2}{8} \)

D. \( \frac{3\pi x}{8} \)

Detailed Solution

A = θ 360 x πr2 = 135 360 x π x x2 = (3πx2)/8
32.

In the diagram, PQRS is a trapezium with PQ||SR. STR is a straight line, PSHQT, PTHQR. If |PQ| = 12cm and the height of the trapezium is 9cm, find its area.

A. 96cm2

B. 108cm2

C. 135cm2

D. 162cm2

E. 216cm2

Detailed Solution

A = 1/2(A + B)h = 1/2(24 + 12) x 9 = 162
33.

Two solid spheres have volumes 250cmo and 128cmo respectively. Find the ratio of their radii.

A. 125:64

B. 25:16

C. 2:1

D. 4:3

E. 5:4

Detailed Solution

4/3πR3/4/3πr3
=
250/180
= (R/r)3 = 5:4

34.

In the diagram ST and QR are parallel. |PS| = 6cm, |SQ| = 8cm and |PR] = 18 2/3. Find |PT|

A. 7cm

B. 8cm

C. 8 2/3cm

D. 10cm

E. 10 2/3cm

B

35.

In the diagram, PQ||RS and angles are as shown. Find x

A. 145o

B. 150o

C. 155o

D. 160o

E. 165o

Detailed Solution

Join PR to a pentagon
90 + 90 + 140 + 55 + x = 540o
x = 165o
36.

IF the exterior angles of a quadilateral are yo, (2y + 5)o , (y + 15)o and (3y - 10)o, find yo

A. 61.43

B. 60

C. 52.86

D. 51.43

E. 50

E

37.

The sum of the angles of regular polygon is 2520o. How many sides does the polygon have?

A. 20

B. 18

C. 17

D. 16

E. 15

Detailed Solution

2(n-2) x 90o = 2520; n = 16
38.

Which of the following is not a property of all parallelogram?

A. the diagonal bisects each other

B. Each diagonal bisects the area

C. the diagonal cut at right angles

D. The opposite sides are equal

E. The opposite angles are equal

C

39.

In the diagram above, PQ is the tangent to the circle RST at T.|ST| = ST and ∠RTQ = 68o. Find ∠PTS

A. 68o

B. 62o

C. 61o

D. 56o

E. 34o

Detailed Solution

∠TSR = 68o ∴ STR =
180-68/2
= 56o

PTS= 180-(68+56) = 56o
40.

The diagram above shows a circle PQRS in which ∠PRQ = 54o and ∠SPQ = 97o. Find ∠PQS

A. 61o

B. 51o

C. 43o

D. 39o

E. 29o

Detailed Solution

PSQ = 54o ∴PQS = 180o - (97 + 54)o = 29o