Paper 1  Objectives  48 Questions
JAMB Exam
Year: 2002
Level: SHS
Time:
Type: Question Paper
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#  Question  Ans 

1. 
Without using tables, evaluate \((343)^{\frac{1}{3}} \times (0.14)^{1} \times (25)^{\frac{1}{2}}\) A. 10 B. 12 C. 8 D. 7
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Detailed Solution\((343)^{\frac{1}{3}} \times (0.14)^{1} \times (25)^{\frac{1}{2}}\)= \(\sqrt[3]{343} \times (\frac{14}{100})^{1} \times (\sqrt{25})^{1}\) = \(7 \times \frac{100}{14} \times \frac{1}{5}\) = 10. 

2. 
In a school, 220 students offer Biology or Mathematics or both. 125 offer Biology and 110 mathematics. How many offer Biology but not Mathematics? A. 95 B. 80 C. 125 D. 110
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Detailed SolutionHint: Represent the question in a venn diagram, such thatn(B ∩ M) = x n(B) only = 125x n(M) only = 110x => 125x + 110x + x = 220 => x = 15. n(B) only = 125  15 = 110 

3. 
Simplify 52.4  5.7  3.45  1.75 A. 41.4 B. 41.5 C. 42.1 D. 42.2
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Detailed Solution52.4  5.7  3.45  1.75= 52.4  (5.7 + 3.45 + 1.75) = 52.4  10.90 = 41.5 

4. 
Simplify \((\sqrt{0.7} + \sqrt{70})^{2}\) A. 84.7 B. 70.7 C. 217.7 D. 168.7
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Detailed Solution\((\sqrt{0.7} + \sqrt{70})^{2}\)= \((\sqrt{0.7} + \sqrt{70})(\sqrt{0.7} + \sqrt{70})\) = \(0.7 + 2\sqrt{0.7 \times 70} + 70\) = \(0.7 + 14 + 70 \) = 84.7 

5. 
Evaluate: \(\frac{0.21 \times 0.072 \times 0.00054}{0.006 \times 1.68 \times 0.063}\) A. 0.01286 B. 0.01285 C. 0.1286 D. 0.1285
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Detailed Solution\(\frac{0.21 \times 0.072 \times 0.00054}{0.006 \times 1.68 \times 0.063}\)= \(\frac{9 \times 10^{10}}{7 \times 10^{8}}\) = \(1.2857 \times 10^{2}\) = \(0.012857 \approxeq 0.01286\) (to 4 s.f) 

6. 
A trader bought goats for N4000 each. He sold them for N180,000 at a loss of 25%. How many goats did he buy? A. 60 B. 50 C. 45 D. 36
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Detailed SolutionLet the number of goats be XC.P of X goats = N4000X S.P of X goats = (75/100) x 4000X = N3000X 3000X = 180,000 => X = 180000/3000 = 60. X = 60 goats 

7. 
If dy/dx = 2x  3 and y = 3 when x = 0, find y in terms of x. A. 2x^{2}  3x B. x^{2}  3x C. x^{2}  3x  3 D. x^{2}  3x + 3
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Detailed Solutiondy/dx = 2x  3y = ∫2x  3 dx => y = x^{2}  3x + c 3 = (0)^{2}  3(0) + c => c = 3 Thus y = x^{2}  3x + 3 

8. 
Find the derivative of \(y = \sin^{2} (5x)\) with respect to x. A. 10 sin 5x cos 5x B. 5 sin5x cos 5x C. 2 sin 5x cos 5x D. 15 sin 5x cos 5x
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Detailed Solution\(y = \sin^{2} (5x)\)Let u = sin 5x \(\frac{\mathrm d u}{\mathrm d x} = 5 \cos 5x\) \(\therefore y = u^{2}\) \(\frac{\mathrm d y}{\mathrm d u} = 2u\) \(\frac{\mathrm d y}{\mathrm d x} = 2u . 5 \cos 5x\) = \(10u \cos 5x\) = \(10 \sin 5x \cos 5x\) 

9. 
The slope of the tangent to the curve y = 3x\(^2\)  2x + 5 at the point (1, 6) is A. 4 B. 1 C. 6 D. 5
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Detailed Solutiony = 3x\(^2\)  2x + 5Slope = \(\frac{\mathrm d y}{\mathrm d x} = 6x  2\) At x = 1, Slope : 6(1)  2 = 4. 

10. 
Evaluate \(\int \sin 3x \mathrm d x\) A. (2/3) cos 3x + c B. (1/3) cos 3x + c C. (1/3) cos 3x + c D. (2/3) cos 3x + c
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Detailed Solution\(\int \sin 3x \mathrm d x =  \frac{\cos 3x}{3} + c\)= \(\frac{1}{3} (\cos 3x) + c\) 
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