Paper 1 | Objectives | 27 Questions
WASSCE/WAEC MAY/JUNE
Year: 2006
Level: SHS
Time:
Type: Question Paper
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# | Question | Ans |
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1. |
How many orbitals are in the d-sub shell? A. 1 B. 3 C. 5 D. 7 |
C |
2. |
An element X has isotopic masses of 6 and 7. if the relative abundance is 1 to 12.5 respectively, what is the relative atomic mass of X? A. 6.0 B. 6.1 C. 6.9 D. 7.0
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Detailed SolutionContribution by isotope 6 = 6 x 1 = 6contribution by isotope 7 = 7 x 12.5 = 87.5 This contribution is made by 1 + 12.5 = 13.5 atoms Relative atomic mass of = 87.5 + 6 = 93.5/13.5 = 6.9 |
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3. |
An atom 23892X decays by alpha particle emission to give an atom Y. The atomic number and mass number of Y are A. 90 and 234 respectively B. 91 and 238 respectively C. 92 and 236 respectively D. 93 and 238 respectively
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Detailed Solution23892 X 234 90Y + 4 2 He Atomic number is 90 while mass number is 234 |
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4. |
If 1 mole of sodium contains 6 x 1023 atoms, how many atoms are contained in 0.6 g of sodium? [Na = 23] A. 1.56 x 1023 B. 1.56 x 1022 C. 3.6 x 1023 D. 3.6 x 1022
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Detailed Solution23g of sodium contain 6 x 1023 atoms :. 0.6g of sodium will contain \(\frac{0.6 x 6 x 1023}{23}/) = 1.56 x 1022 |
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5. |
If 20 cm3 of distilled water is added to 80cm 3 of 0. 50 mol dm-3 hydrochloric acid, the new concentration of the acid will be A. 0.10mol dm-3 B. 0.20mol dm-3 C. 0.40mol dm-3 D. 2.00mol dm-3
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Detailed SolutionC1 x 100 = 0.5 x 80C1 = \(\frac{0.5 x 80}{100}/) = \(\frac{4}{10}/) = 0 . 40mol/dm-3 |
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6. |
Consider the reaction represented by the equation. 2NaHCO3(s) \(\rightarrow\) 2Na2CO 3(S) + CO 2(g) + H2O(g) what volume of carbon (IV)oxide at s.t.p is evolved when 0. 5 moles of NaHCO3 is heated? [Molar volume = 22.4 dm3 at s.t. p] A. 1.12dm3 B. 2.24dm3 C. 5.6dm3 D. 56.0dm3
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Detailed Solution2NaHCO3(s) \(\rightarrow\) 2Na2CO 3(S) + CO 2(g) + H2O(g)2 moles of 2NaHCO3(s) produces 22.4dm3 of CO2 0.5 moles of 2NaHCO3 will produce \(\frac{0.5 \times 22.4}{2}\) = \(\frac{11.2}{2}\) = 5.6 dm3 |
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