Paper 1 | Objectives | 36 Questions
WASSCE/WAEC MAY/JUNE
Year: 1988
Level: SHS
Time:
Type: Question Paper
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# | Question | Ans |
---|---|---|
1. |
Equilibrium is said to be attained in reversible reaction when A. all the reactants have been used up B. all the products have been formed C. there is no further change in temperature D. the rates of the forward and backward reactions are equal E. the rate of formation of the products decreases with time |
D |
2. |
An acid present in proteins is A. lactic acid B. amino acid C. propanoic acid D. palmitic acid E. stearic acid |
B |
3. |
The following are uses of sulphur except A. manufacture of tetraoxosulphate (VI) acid B. prevention of the growth of fungi C. vulcanization rubber D. manufacture of dyes E. coating of steel to prevent rusting |
E |
4. |
The reaction represented by the equation NaOH(aq) + HCI(aq) → NaCI(aq) + H2O(/) A. is a double decomposition B. is a neutralization C. is reversible D. is usually catalysed E. attains equilibrium after a few seconds |
B |
5. |
Which of the following compound is aromatic? A. Benzene B. Cyclobutane C. Cyclopentane D. Hexane E. Ethene |
A |
6. |
Which of the following does not affect the rate of a chemical reaction? A. Addition or presence of a catalyst B. Size of the reacting particles C. The enthalpy change for the reaction D. Concentration of the reactants E. Temperatureat which the reaction is carried out |
C |
7. |
Which of the following does not affect the rate of a chemical reaction? A. Addition or presence of a catalyst B. Size of the reacting particles C. The enthalpy change for the reaction D. Concentration of the reactants E. Temperatureat which the reaction is carried out |
C |
8. |
Given that 32.0g sulphur contains 6.02 x 10 23 sulphur atoms how many atoms are there in 2.70g of aluminium? {Al = 27, S =32} A. 6.02 x 10 23 B. 3.01 x 1022 C. 6.02 x 1022 D. 08 x 1022 E. 3.01 x 1022
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Detailed Solution27g Aluminium = \(6.02 \times 10^{23}\)1g Al = \(\frac{6.02 \times 10^{23}}{27}\) 2.7g Al = \(\frac{6.02 \times 10^{23}}{27} \times 2.7\) = \(6.02 \times 10^{22} Al \) atoms |
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