Contribution by isotope 6 = 6 x 1 = 6 contribution by isotope 7 = 7 x 12.5 = 87.5 This contribution is made by 1 + 12.5 = 13.5 atoms Relative atomic mass of = 87.5 + 6 = 93.5/13.5 = 6.9
Consider the reaction represented by the equation. 2NaHCO3(s) \(\rightarrow\) 2Na2CO 3(S) + CO 2(g) + H2O(g) what volume of carbon (IV)oxide at s.t.p is evolved when 0. 5 moles of NaHCO3 is heated? [Molar volume = 22.4 dm3 at s.t. p]