Mathematics (Core)
Paper 1 | Objectives | 45 Questions
JAMB Exam
Year: 1997
Level: SHS
Time:
Type: Question Paper
Answers provided
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Paper 1 | Objectives | 45 Questions
JAMB Exam
Year: 1997
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
Make sure you study hard but not into the late-night hours to give your body the enough rest you need.
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| # | Question | Ans |
|---|---|---|
| 1. |
Evaluate 64.764\(^2\) - 35.236\(^2\) correct to 3 significant figures A. 2960 B. 2950 C. 2860 D. 2850
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Detailed Solution(64.764 - 35.236)(64.764 + 35.236)= 29.528 x 100 = 2950 to 3 sig. fig. |
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| 2. |
Find the value of (0.006)3 + (0.004)3 in standard form A. 2.8 x 10-9 B. 2.8 x 10-7 C. 2.8 x 10-8 D. 2.8 x 10-6
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Detailed Solution(0.006)3 + (0.004)3 = 2.16 x 10-7(2.16 + 0.64) x 10-7 = 2.8 x 10-7 |
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| 3. |
Given that loga2 = 0.693 and loga3 = 1.097, find loga 13.5 A. 1.404 B. 1.790 C. 2.598 D. 2.790
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Detailed Solutionloga 13.5 = loga \(\frac{27}{2}\)= 3loga 3 - log2a = 3 x 1.097 - 0.693 = 2.598 |
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| 4. |
If 8\(\frac{x}{2}\) = (2\(\frac{3}{8}\))(4\(\frac{3}{4}\)), find x A. \(\frac{3}{8}\) B. \(\frac{3}{4}\) C. \(\frac{4}{5}\) D. \(\frac{5}{4}\)
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Detailed Solution8\(\frac{x}{2}\) = 2\(\frac{3}{8}\)22 x \(\frac{3}{4}\) 2\(\frac{3x}{2}\)= 2\(\frac{3}{4}\) \(\frac{3x}{2}\) = \(\frac{15}{8}\) \(\frac{2 \times 15}{3 \times 8}\) = \(\frac{5}{4}\) |
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| 5. |
Simplify \(\frac{2\sqrt{3} + 3\sqrt{5}}{3\sqrt{5} - 2\sqrt{3}}\) A. \(\frac{19 + 4\sqrt{25}}{11}\) B. \(\frac{19 + 4\sqrt{15}}{11}\) C. \(\frac{19 + 2\sqrt{15}}{11}\) D. \(\frac{19 + 2\sqrt{15}}{19}\)
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Detailed Solution\(\frac{(2\sqrt{3} + 3\sqrt{5})(3\sqrt{5} + 2\sqrt{3})}{(3\sqrt{5} - 2\sqrt{3})(3\sqrt{5} - 2\sqrt{3})}\)= \(\frac{5 + 12\sqrt{15}}{33}\) =\(\frac{19 + 4\sqrt{15}}{11}\) |
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| 6. |
Find the simple interest rate percent per annum at which N1,000 accumulates to N1,240 in 3 years A. 6% B. 8% C. 10% D. 12%
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Detailed Solution1 = \(\frac{PRT}{100}\)1 = 1240 - 1000 = 240 R = \(\frac{240 \times 100}{100 \times 3}\)% = 8% |
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| 7. |
If U = (s, p, i, e, n, d, o, u, r), X = (s, p, e, n, d) Y = (s, e, n, o, u), Z = (p, n, o, u, r) find X ∩( Y ∪ Z) A. (p, o, u, r) B. (s, p, d, r) C. (s, p, n, e) D. (n, d, u)
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Detailed Solution\(Y \cup Z\) = \({s, e, n, o, u, p, r}\)\(X \cap (Y \cup Z)\) = \({p, e, n}\) |
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| 8. |
A survey of 100 students in an institution shows that 80 students speak Hausa and 20 students speak Igbo, while only 9 students speak both language. How many students speak neither Hausa nor Igbo? A. 0 B. 9 C. 11 D. 20
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Detailed SolutionLet the number of students that speak Hausa and Igbo be represented by H and I respectively.n(H only) = 80 - 9 = 71. n(I only) = 20 - 9 = 11. n(neither H nor I) = 100 - (71 + 9 + 11) = 100 - 91 = 9 students. |
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| 9. |
If the function f(fx) = x3 + 2x2 + qx - 6 is divisible by x + 1, find q A. -5 B. -2 C. 2 D. 5
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Detailed Solutionx + 1 = 0, x = -1; f(x) = x3 + 2x2 + qx - 60 = -1 + 2 - q - 6 q = -5 |
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