Year : 
1999
Title : 
Mathematics (Core)
Exam : 
WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

11 - 20 of 43 Questions

# Question Ans
11.

Calculate the value of Y in the diagram

A. 18o

B. 42o

C. 48o

D. 132o

Detailed Solution


x = 180° - 123° = 57°
z = 180° - 105° = 75°
y = 180° - 57° - 75° = 48°
12.

In the diagram, POR is a circle with center O. ∠QPR = 50°, ∠PQO = 30° and ∠ORP = m. Find m.

A. 20o

B. 25o

C. 30o

D. 50o

Detailed Solution

< QOR = 50° x 2 = 100°
Reflex < QOR = 360° - 100° = 260°
\(\therefore\) 30° + 50° + 260° + m = (4 - 2) x 180°
340° + m = 360°
m = 360° - 340° = 20°
13.

Given that m = -3 and n = 2 find the value of \(\frac{3n^2 - 2m^3}{m}\)

A. -22

B. -14

C. 14

D. 22

Detailed Solution

Given that m = -3, n = 2, the value of
\(\frac{3n^2 - 2n^3}{m}\\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)
14.

Simplify \(\frac{2-18m^2}{1+3m}\)

A. \(2(1+3m)\)

B. \(2(1+3m^2)\)

C. \(2(1-3m)\)

D. \(2(1-3m^2)\)

Detailed Solution

\(\frac{2-18m^2}{1+3m}=\frac{2(1-(3m)^2)}{1+3m}\\
\frac{2(1-(3m)(1+3m)}{1+3m}=2(1-3m)\)
15.

If \(y = \sqrt{ax-b}\) express x in terms of y, a and b

A. \(x = \frac{y^2-b}{a}\)

B. \(x = \frac{y+b}{a}\)

C. \(x = \frac{y-b}{a}\)

D. \(x = \frac{y^2 + b}{a}\)

Detailed Solution

\(y = \sqrt{ax-b}\)
\(y^2 = ax-b\)
\(y^2 +b = ax\)
\(x = \frac{y^2 + b}{a}\)
16.

Given that \(81\times 2^{2n-2} = K, find \sqrt{K}\)

A. \(4.5\times 2^{n}\)

B. \(4.5\times 2^{2n}\)

C. \(9\times 2^{n-1}\)

D. \(9\times 2^{2n}\)

Detailed Solution

\(K = 81 \times 2^{2n - 2}\)
\(\sqrt{K} = \sqrt{81 \times 2^{2n - 2}}\)
= \(9 \times 2^{n - 1}\)
17.

Simplify \(\frac{4}{x+1}-\frac{3}{x-1}\)

A. \(\frac{x+7}{x^2 - 1}\)

B. \(\frac{x-7}{x^2 + 1}\)

C. \(\frac{x-7}{x^2 - 1}\)

D. \(\frac{x-11}{x^2 - 1}\)

Detailed Solution

\(\frac{4}{x+1}-\frac{3}{x-1} \\
=\frac{4x - 4 - 3x - 3}{(x+1)(x-1)}=\frac{x-7}{x^2 - 1}\)
18.

If y varies inversely as x\(^2\), how does x vary with y?

A. x varies inversely as y2

B. x varies inversely as y

C. x varies directly as y2

D. x varies directly as y

Detailed Solution

\(y \propto \frac{1}{x^2}\)
\(y = \frac{k}{x^2}\)
\(x^2 = \frac{k}{y}\)
\(x = \frac{\sqrt{k}}{\sqrt{y}}\)
Since k is a constant, then \(\sqrt{k}\) is also a constant.
\(\therefore x \propto \frac{1}{\sqrt{y}}\)
19.

If \(tan x = \frac{1}{\sqrt{3}}\), find cos x - sin x such that \(0^o \leq x \leq 90^o\)

A. \(\frac{\sqrt{3}+1}{2}\)

B. \(\frac{2}{\sqrt{3}+1}\)

C. \(\frac{\sqrt{3}-1}{2}\)

D. \(\frac{2}{\sqrt{3}-1}\)

Detailed Solution


\(\cos x = \frac{\sqrt{3}}{2}\)
\(\sin x = \frac{1}{2}\)
\(\cos x - \sin x = \frac{\sqrt{3} - 1}{2}\)
20.

From the top of a cliff 20m high, a boat can be sighted at sea 75m from the foot of the cliff. Calculate the angle of depression of the boat from the top of the cliff

A. 14.9 o

B. 15.5 o

C. 74.5 o

D. 75.1 o

Detailed Solution

\(\tan x = \frac{20}{75} = 0.267\)
\(x = \tan^{-1} 0.267 = 14.93°\)
\(\approxeq\) 14.9°
11.

Calculate the value of Y in the diagram

A. 18o

B. 42o

C. 48o

D. 132o

Detailed Solution


x = 180° - 123° = 57°
z = 180° - 105° = 75°
y = 180° - 57° - 75° = 48°
12.

In the diagram, POR is a circle with center O. ∠QPR = 50°, ∠PQO = 30° and ∠ORP = m. Find m.

A. 20o

B. 25o

C. 30o

D. 50o

Detailed Solution

< QOR = 50° x 2 = 100°
Reflex < QOR = 360° - 100° = 260°
\(\therefore\) 30° + 50° + 260° + m = (4 - 2) x 180°
340° + m = 360°
m = 360° - 340° = 20°
13.

Given that m = -3 and n = 2 find the value of \(\frac{3n^2 - 2m^3}{m}\)

A. -22

B. -14

C. 14

D. 22

Detailed Solution

Given that m = -3, n = 2, the value of
\(\frac{3n^2 - 2n^3}{m}\\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)
14.

Simplify \(\frac{2-18m^2}{1+3m}\)

A. \(2(1+3m)\)

B. \(2(1+3m^2)\)

C. \(2(1-3m)\)

D. \(2(1-3m^2)\)

Detailed Solution

\(\frac{2-18m^2}{1+3m}=\frac{2(1-(3m)^2)}{1+3m}\\
\frac{2(1-(3m)(1+3m)}{1+3m}=2(1-3m)\)
15.

If \(y = \sqrt{ax-b}\) express x in terms of y, a and b

A. \(x = \frac{y^2-b}{a}\)

B. \(x = \frac{y+b}{a}\)

C. \(x = \frac{y-b}{a}\)

D. \(x = \frac{y^2 + b}{a}\)

Detailed Solution

\(y = \sqrt{ax-b}\)
\(y^2 = ax-b\)
\(y^2 +b = ax\)
\(x = \frac{y^2 + b}{a}\)
16.

Given that \(81\times 2^{2n-2} = K, find \sqrt{K}\)

A. \(4.5\times 2^{n}\)

B. \(4.5\times 2^{2n}\)

C. \(9\times 2^{n-1}\)

D. \(9\times 2^{2n}\)

Detailed Solution

\(K = 81 \times 2^{2n - 2}\)
\(\sqrt{K} = \sqrt{81 \times 2^{2n - 2}}\)
= \(9 \times 2^{n - 1}\)
17.

Simplify \(\frac{4}{x+1}-\frac{3}{x-1}\)

A. \(\frac{x+7}{x^2 - 1}\)

B. \(\frac{x-7}{x^2 + 1}\)

C. \(\frac{x-7}{x^2 - 1}\)

D. \(\frac{x-11}{x^2 - 1}\)

Detailed Solution

\(\frac{4}{x+1}-\frac{3}{x-1} \\
=\frac{4x - 4 - 3x - 3}{(x+1)(x-1)}=\frac{x-7}{x^2 - 1}\)
18.

If y varies inversely as x\(^2\), how does x vary with y?

A. x varies inversely as y2

B. x varies inversely as y

C. x varies directly as y2

D. x varies directly as y

Detailed Solution

\(y \propto \frac{1}{x^2}\)
\(y = \frac{k}{x^2}\)
\(x^2 = \frac{k}{y}\)
\(x = \frac{\sqrt{k}}{\sqrt{y}}\)
Since k is a constant, then \(\sqrt{k}\) is also a constant.
\(\therefore x \propto \frac{1}{\sqrt{y}}\)
19.

If \(tan x = \frac{1}{\sqrt{3}}\), find cos x - sin x such that \(0^o \leq x \leq 90^o\)

A. \(\frac{\sqrt{3}+1}{2}\)

B. \(\frac{2}{\sqrt{3}+1}\)

C. \(\frac{\sqrt{3}-1}{2}\)

D. \(\frac{2}{\sqrt{3}-1}\)

Detailed Solution


\(\cos x = \frac{\sqrt{3}}{2}\)
\(\sin x = \frac{1}{2}\)
\(\cos x - \sin x = \frac{\sqrt{3} - 1}{2}\)
20.

From the top of a cliff 20m high, a boat can be sighted at sea 75m from the foot of the cliff. Calculate the angle of depression of the boat from the top of the cliff

A. 14.9 o

B. 15.5 o

C. 74.5 o

D. 75.1 o

Detailed Solution

\(\tan x = \frac{20}{75} = 0.267\)
\(x = \tan^{-1} 0.267 = 14.93°\)
\(\approxeq\) 14.9°