11 - 20 of 41 Questions
# | Question | Ans |
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11. |
What is the difference in longitude between P (lat. 50°N. long. 50°W) and Q (lat.50°N, long. 150°W)? A. 300o B. 200o C. 130o D. 100o E. 30o Detailed SolutionLet \(\theta\) be the angular difference between P (50°N. 50°W), and Q (50°N, 150°W),\(\theta\) = 150° - 50° =100° |
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12. |
The number 186,470 was corrected to 186,000. Which of the following describe the degree of approximation made? A. I & III only B. I & IV only C. II & III only D. II & IV only E. All of the above |
C |
13. |
Points P and Q respectively 24m north and 7m east point R. Calculate |PQ| in meters A. 20 B. 24 C. 25 D. 31 E. 84 Detailed SolutionPQ\(^2\) = 24\(^2\) + 7\(^2\)PQ\(^2\) = 625 PQ = 25 |
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14. |
Points P and Q respectively 24m north and 7m east point R. What is the bearing of Q from P to the nearest whole degree? A. 16o B. 17o C. 73o D. 106o E. 164o Detailed SolutionUsing pythagoras' theorem:Hyp\(^2\) = Adj\(^2\) + Opp\(^2\) → 24\(^2\) + 7\(^2\) Hyp = √625 → 25 \(\tan P = \frac{7}{24}\) \(\tan P = 0.2917\) \(P = \tan^{-1} (0.2917)\) = 16.26° Bearing of Q from P = 180° - 16.26° = 163.74° \(\approxeq\) 164° |
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15. |
If sinθ = 3/5 find tanθ for 0 < θ < 90o A. 4\5 B. 3\4 C. 5\8 D. 1\2 E. 3\8 Detailed Solutionsinθ = 3/5tanθ = 3/4 |
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16. |
Simplify (271/3)2 A. 41/2 B. 6 C. 9 D. 18 E. 81 Detailed Solution(271/3)2= (33 x 1/3)2 = 32 = 9 |
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17. |
A student told to draw the graph of y = x2 + 4x - 6. He is then told to draw a liner graph on the same axis such that the intersection of the two graphs will give the solutions to the equation x2 + 4x - 7 = 0, What is the equation of the linear graph he needs to draw? A. x = 1 B. x = -1 C. y = 1 D. y = -1 E. x + y = 1 Detailed SolutionThe linear equation will be the difference between the equation.y=x2 + 4x - 6 and x2 + 4x - 7 = 0 y=x2 + 4x - 6, ( 0 = x2 + 4x - 7) y = -(-1) y = 1 |
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18. |
Calculate the value of x in the diagram above A. 18o B. 30o C. 40o D. 60o E. 15° Detailed Solutionvertically opposite angles are equal, hence3x + 6x + 3x = 180° 12x = 180° x = 15° |
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19. |
Find the quadratic equation whose roots are x = -2 or x = 7 A. x2 + 2x - 7 = 0 B. x2 - 2x + 7 = 0 C. x2 + 5 +14 = 0 D. x2 - 5x - 14 = 0 E. x2 + 5x - 14 = 0 Detailed Solutionx + 2 and x - 7 are factors(x+2)(x+7) = 0 x(x-7) + 2(x-7) = 0 x2 - 7x + 2x - 14 = 0 x2 - 5x - 14 = 0 |
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20. |
A sales girl gave a change of N1.15 to a customer instead of N1.25. Calculate her percentage error A. 10% B. 7% C. 8.0% D. 2.4% E. 10% Detailed SolutionError = 1.25 - 1.15 = 0.10 0.101.25 * 100 = 8.0% |
11. |
What is the difference in longitude between P (lat. 50°N. long. 50°W) and Q (lat.50°N, long. 150°W)? A. 300o B. 200o C. 130o D. 100o E. 30o Detailed SolutionLet \(\theta\) be the angular difference between P (50°N. 50°W), and Q (50°N, 150°W),\(\theta\) = 150° - 50° =100° |
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12. |
The number 186,470 was corrected to 186,000. Which of the following describe the degree of approximation made? A. I & III only B. I & IV only C. II & III only D. II & IV only E. All of the above |
C |
13. |
Points P and Q respectively 24m north and 7m east point R. Calculate |PQ| in meters A. 20 B. 24 C. 25 D. 31 E. 84 Detailed SolutionPQ\(^2\) = 24\(^2\) + 7\(^2\)PQ\(^2\) = 625 PQ = 25 |
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14. |
Points P and Q respectively 24m north and 7m east point R. What is the bearing of Q from P to the nearest whole degree? A. 16o B. 17o C. 73o D. 106o E. 164o Detailed SolutionUsing pythagoras' theorem:Hyp\(^2\) = Adj\(^2\) + Opp\(^2\) → 24\(^2\) + 7\(^2\) Hyp = √625 → 25 \(\tan P = \frac{7}{24}\) \(\tan P = 0.2917\) \(P = \tan^{-1} (0.2917)\) = 16.26° Bearing of Q from P = 180° - 16.26° = 163.74° \(\approxeq\) 164° |
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15. |
If sinθ = 3/5 find tanθ for 0 < θ < 90o A. 4\5 B. 3\4 C. 5\8 D. 1\2 E. 3\8 Detailed Solutionsinθ = 3/5tanθ = 3/4 |
16. |
Simplify (271/3)2 A. 41/2 B. 6 C. 9 D. 18 E. 81 Detailed Solution(271/3)2= (33 x 1/3)2 = 32 = 9 |
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17. |
A student told to draw the graph of y = x2 + 4x - 6. He is then told to draw a liner graph on the same axis such that the intersection of the two graphs will give the solutions to the equation x2 + 4x - 7 = 0, What is the equation of the linear graph he needs to draw? A. x = 1 B. x = -1 C. y = 1 D. y = -1 E. x + y = 1 Detailed SolutionThe linear equation will be the difference between the equation.y=x2 + 4x - 6 and x2 + 4x - 7 = 0 y=x2 + 4x - 6, ( 0 = x2 + 4x - 7) y = -(-1) y = 1 |
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18. |
Calculate the value of x in the diagram above A. 18o B. 30o C. 40o D. 60o E. 15° Detailed Solutionvertically opposite angles are equal, hence3x + 6x + 3x = 180° 12x = 180° x = 15° |
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19. |
Find the quadratic equation whose roots are x = -2 or x = 7 A. x2 + 2x - 7 = 0 B. x2 - 2x + 7 = 0 C. x2 + 5 +14 = 0 D. x2 - 5x - 14 = 0 E. x2 + 5x - 14 = 0 Detailed Solutionx + 2 and x - 7 are factors(x+2)(x+7) = 0 x(x-7) + 2(x-7) = 0 x2 - 7x + 2x - 14 = 0 x2 - 5x - 14 = 0 |
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20. |
A sales girl gave a change of N1.15 to a customer instead of N1.25. Calculate her percentage error A. 10% B. 7% C. 8.0% D. 2.4% E. 10% Detailed SolutionError = 1.25 - 1.15 = 0.10 0.101.25 * 100 = 8.0% |