Mathematics (Core), 2013, WASSCE/WAEC MAY/JUNE, Exam, Paper 1 | Objectives

Paper Info

Year :

2013

Title :

Mathematics (Core)

Exam :

WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

41 - 48 of 48 Questions

#	Question	Ans
41.	Using the histogram, estimate the mode of distribution A. 51.5 B. 52.5 C. 53.5 D. 54.5	C
42.	Using the histogram, what is the median class? A. 60.5 - 70.5 B. 50.5 - 60.5 C. 40.5 - 50.5 D. 30.5 - 40.5	C
43.	The pie chart shows the distribution of 600 mathematics textbooks for Arts, Business, Science and Technical Classes. How many textbooks are for the technical class? A. 100 B. 150 C. 200 D. 250 Show Content Detailed Solution Arts = 90^o business = 75^o, science = 45^o Technical 360^o - (90^o - 75^o + 45^o) = 360^o - 210^o Technical = 150^o textbooks for technical class = \(\frac{150^o}{360^o}\) x 600 = 250	D
44.	The pie chart shows the distribution of 600 mathematics textbooks for Arts, Business, Science and Technical Classes. What percentage of the total number of textbooks belongs to science? A. 12\(\frac{1}{2}\)% B. \(\frac{205}{6}\)% C. 25% D. \(\frac{412}{3}\)% Show Content Detailed Solution \(\frac{45^o}{360}\) x 100% = 12\(\frac{1}{2}\)%	A
45.	In the diagram, PQRST is a regular polygon with sides QR and TS produced to meet at V. Find the size of < RVS A. 36^o B. 54^o C. 60^o D. 72^o Show Content Detailed Solution PQRST is a regular polygon with 5 sides-pentagon n = 5, Each exterior angle = \(\frac{360^o}{n}\) = \(\frac{350}{5}\) = 70^o Each interior angle = 180 - 72^o (< s on str. line) = 180^o Since the pentagon is regular, the exterior angles are equal < R = 72^o and < S = 72^o < RVS = 180^o - (< R + < S) = 180^o - (72^o + 72^o) = 180^o - 144^o	A
46.	In the diagram, PQ is a straight line. Calculate the value of the angle labelled 2y A. 130^o B. 120^o C. 110^o D. 100^o Show Content Detailed Solution Sum of angles on straight line = 180^o 80^o + 50^o + x + 10^o = 180^o 140^o + x = 180^o x = 180^o - 140^o x = 40^o total sum of all angles = 360^o 2y^o + 2x^o + 80^o + 50^o + x + 10^o = 360^o 2y^o + 2(	D
47.	In the diagram, ST//PQ reflex angle SRQ = 198^o and < RQp = 72^o. Find the value of y A. 18^o B. 54^o C. 87^o D. 92^o Show Content Detailed Solution R +198 = 360(angles at a point) R = 360 - 198 = 162^o C = 72(alternate angle), b + c = 180(angles or straight line) b = 190 - c = 180 - 72 = 108 a + b = R = 162 a = R - b = 162 - 108 = 54, but a = y(alternate angles) y = 54^o	B
48.	Using the venn diagram, find n(x \(\cap\) y¹) A. 2 B. 3 C. 4 D. 6 Show Content Detailed Solution (x \(\cap\) y²) = [a, b] n(x \(\cap\) y²) = 2	A

41.	Using the histogram, estimate the mode of distribution A. 51.5 B. 52.5 C. 53.5 D. 54.5	C
42.	Using the histogram, what is the median class? A. 60.5 - 70.5 B. 50.5 - 60.5 C. 40.5 - 50.5 D. 30.5 - 40.5	C
43.	The pie chart shows the distribution of 600 mathematics textbooks for Arts, Business, Science and Technical Classes. How many textbooks are for the technical class? A. 100 B. 150 C. 200 D. 250 Show Content Detailed Solution Arts = 90^o business = 75^o, science = 45^o Technical 360^o - (90^o - 75^o + 45^o) = 360^o - 210^o Technical = 150^o textbooks for technical class = \(\frac{150^o}{360^o}\) x 600 = 250	D
44.	The pie chart shows the distribution of 600 mathematics textbooks for Arts, Business, Science and Technical Classes. What percentage of the total number of textbooks belongs to science? A. 12\(\frac{1}{2}\)% B. \(\frac{205}{6}\)% C. 25% D. \(\frac{412}{3}\)% Show Content Detailed Solution \(\frac{45^o}{360}\) x 100% = 12\(\frac{1}{2}\)%	A

45.	In the diagram, PQRST is a regular polygon with sides QR and TS produced to meet at V. Find the size of < RVS A. 36^o B. 54^o C. 60^o D. 72^o Show Content Detailed Solution PQRST is a regular polygon with 5 sides-pentagon n = 5, Each exterior angle = \(\frac{360^o}{n}\) = \(\frac{350}{5}\) = 70^o Each interior angle = 180 - 72^o (< s on str. line) = 180^o Since the pentagon is regular, the exterior angles are equal < R = 72^o and < S = 72^o < RVS = 180^o - (< R + < S) = 180^o - (72^o + 72^o) = 180^o - 144^o	A
46.	In the diagram, PQ is a straight line. Calculate the value of the angle labelled 2y A. 130^o B. 120^o C. 110^o D. 100^o Show Content Detailed Solution Sum of angles on straight line = 180^o 80^o + 50^o + x + 10^o = 180^o 140^o + x = 180^o x = 180^o - 140^o x = 40^o total sum of all angles = 360^o 2y^o + 2x^o + 80^o + 50^o + x + 10^o = 360^o 2y^o + 2(	D
47.	In the diagram, ST//PQ reflex angle SRQ = 198^o and < RQp = 72^o. Find the value of y A. 18^o B. 54^o C. 87^o D. 92^o Show Content Detailed Solution R +198 = 360(angles at a point) R = 360 - 198 = 162^o C = 72(alternate angle), b + c = 180(angles or straight line) b = 190 - c = 180 - 72 = 108 a + b = R = 162 a = R - b = 162 - 108 = 54, but a = y(alternate angles) y = 54^o	B
48.	Using the venn diagram, find n(x \(\cap\) y¹) A. 2 B. 3 C. 4 D. 6 Show Content Detailed Solution (x \(\cap\) y²) = [a, b] n(x \(\cap\) y²) = 2	A