41 - 45 of 45 Questions
# | Question | Ans |
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41. |
In the figure, PQRS is a circle with ST||RQ. Find the value of x if PT = pS A. 70o B. 55o C. 40o D. 35o Detailed Solution< PST = < RQT = x(corresponding angle)< PST = < PTS = < PTS x (PS = PT0 < SRQ = < SPT = 180o (sum of < on straight line) < SPT = 180o - 110o = 70o in < SPT, < PST = PTS = < PSt = 180o 2x + 70 = 180o 2x = 180o - 70o = 110o x = \(\frac{110^o}{2}\) = 55o |
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42. |
In the figure, TZ is tangent to the circle QPZ. Find x if TZ = 6 units and PQ = 9 units A. 3 B. 4 C. 5 D. 6 Detailed SolutionIn \(\bigtriangleup\)WOP, b2 = r2 - (4.502...........(i)In \(\bigtriangleup\)WOT, b\(\bigtriangleup\) + (4.5 + x)2 = a2...........(ii) In \(\bigtriangleup\)ZOT, a2 = 62 + r2 ..........(iii) subst. equation (iii) and (i) in eqn (ii) r2 - (4.5)2 + (4.5 + x)2 = 36 = 20.25 = (4.5 + x)2 = \(\sqrt{56.25}\) = (4.5 + x) = 56.25 |
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43. |
Find the value of L in the frustum A. 5cm B. 6cm C. 7cm D. 8cm |
A |
44. |
Find the length XZ in the triangle A. \(\sqrt{7m}\) B. \(\sqrt{6m}\) C. \(\sqrt{5m}\) D. \(\sqrt{3m}\) Detailed Solutionxz2 = xy2 + yx2 - 2(xy) (yz) cos 120o= 22 + 12 - 2(2) (1) cos 1202 = 4 + 1 - 4x - cos 60 = 5 - 4x - \(\frac{1}{2}\) 5 + 2 = 7 xz = \(\sqrt{7}\)m |
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45. |
The grades of 36 students in a class test are as shown in the pie chart. How many student has excellent? A. 7 B. 8 C. 9 D. 12 Detailed Solutiondegree of excellent in the pie-chart = 360o - (90o + 120o + 80o) = 360o - 290o = 70o= 360o = 36 students 70 = \(\frac{70^o}{360^o}\) x 36 = 7 |
41. |
In the figure, PQRS is a circle with ST||RQ. Find the value of x if PT = pS A. 70o B. 55o C. 40o D. 35o Detailed Solution< PST = < RQT = x(corresponding angle)< PST = < PTS = < PTS x (PS = PT0 < SRQ = < SPT = 180o (sum of < on straight line) < SPT = 180o - 110o = 70o in < SPT, < PST = PTS = < PSt = 180o 2x + 70 = 180o 2x = 180o - 70o = 110o x = \(\frac{110^o}{2}\) = 55o |
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42. |
In the figure, TZ is tangent to the circle QPZ. Find x if TZ = 6 units and PQ = 9 units A. 3 B. 4 C. 5 D. 6 Detailed SolutionIn \(\bigtriangleup\)WOP, b2 = r2 - (4.502...........(i)In \(\bigtriangleup\)WOT, b\(\bigtriangleup\) + (4.5 + x)2 = a2...........(ii) In \(\bigtriangleup\)ZOT, a2 = 62 + r2 ..........(iii) subst. equation (iii) and (i) in eqn (ii) r2 - (4.5)2 + (4.5 + x)2 = 36 = 20.25 = (4.5 + x)2 = \(\sqrt{56.25}\) = (4.5 + x) = 56.25 |
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43. |
Find the value of L in the frustum A. 5cm B. 6cm C. 7cm D. 8cm |
A |
44. |
Find the length XZ in the triangle A. \(\sqrt{7m}\) B. \(\sqrt{6m}\) C. \(\sqrt{5m}\) D. \(\sqrt{3m}\) Detailed Solutionxz2 = xy2 + yx2 - 2(xy) (yz) cos 120o= 22 + 12 - 2(2) (1) cos 1202 = 4 + 1 - 4x - cos 60 = 5 - 4x - \(\frac{1}{2}\) 5 + 2 = 7 xz = \(\sqrt{7}\)m |
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45. |
The grades of 36 students in a class test are as shown in the pie chart. How many student has excellent? A. 7 B. 8 C. 9 D. 12 Detailed Solutiondegree of excellent in the pie-chart = 360o - (90o + 120o + 80o) = 360o - 290o = 70o= 360o = 36 students 70 = \(\frac{70^o}{360^o}\) x 36 = 7 |