Mathematics (Core), 2020, WASSCE/WAEC MAY/JUNE, Exam, Paper 1 | Objectives

Paper Info

Year :

2020

Title :

Mathematics (Core)

Exam :

WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

41 - 50 of 50 Questions

#	Question	Ans
41.	The points on a linear graph are as shown in the table. Find the gradient (slope) of the line. A. 2\(\frac{1}{2}\) B. 2 C. 1 D. \(\frac{1}{2}\) Show Content Detailed Solution Gradient = \(\frac{y_2 - y_ 1}{x_2 - x_1}\) = \(\frac{5.20 - 3.90}{6.85 - 6.20}\) = \(\frac{1.3}{0.5}\) = 2	B
42.	In the diagram, O is the centre of the circle, PQ and RS are tangents to the circle. Find the value of (m + n). A. 120\(^o\) B. 90\(^o\) C. 75\(^o\) D. 60\(^o\) Show Content Detailed Solution m + n + 90\(^o\) + 180\(^o\) (sum of angle in a \(\triangle\)) m + n = 180\(^o\) - 90\(^o\) m + n =90\(^o\)	B
43.	Which of the following is not a sufficient condition for two triangles to be congruent? A. AAS B. SSS C. SAS D. SSA	D
44.	A woman received a discount of 20% on a piece of cloth she purchased from a shop. If she paid $525.00, what was the original price? A. $675.25 B. $660.25 C. $656.25 D. $616.25 Show Content Detailed Solution \(\frac{20}{100}\) x \(x\) = \(x - 525\) \(\frac{x}{5} = x\) - 535 x = 5x - 2625 \(\frac{4x}{4} = \frac{2625}{4}\) x = $656.25	C
45.	The interquartile range of distribution is 7. If the 25th percentile is 16, find the upper quartile. A. 35 B. 30 C. 23 D. 9 Show Content Detailed Solution Q\(_3\) - Q\(_1\) = 7 Q\(_3\) - 16 = 7 Q\(_3\) - 7 + 16 = 23	C
46.	The graph of the equations y = 2x + 5 and y = 2x\(^2\) + x - 1 are shown below. Find the points of intersection of the two graphs. A. (2.0, 9.0) and (-1.5, 2.0) B. (2.0, 8.5) and (-1.5, 2.0) C. (2.0, 8.0) and (-1.5, 2.5) D. (2.0, 7.5) and (-1.5, 2.5)	A
47.	The graph of the equations y = 2x + 5 and y = 2x\(^2\) + x - 1 are shown. If x = -2.5, what is the value of u on the curve? A. y = 8.0 B. y = 8.5 C. y = 9.0 D. y = 9.5 Show Content Detailed Solution If x = -2.5 y = 8.5	B
48.	If (x + 2) is a factor of x\(^2\) +px - 10, find the value of P. A. 3 B. -3 C. 7 D. -7 Show Content Detailed Solution x + 2 = 0 x -2 x\(^2\) = px - 10 = 0 (-2)\(^2\) - 2p - 10 = 0 4 - 2p - 10 = 0 \(\frac{-2p}{-2} = \frac{6}{-2}\) \(\to\) p = -3	B
49.	In the diagram, O is the centre of the circle. If < NLM = 74\(^o\), < LMN = 39\(^o\) and < LOM = x, find the value of x. A. 134\(^o\) B. 126\(^o\) C. 113\(^o\) D. 106\(^o\) Show Content Detailed Solution L\(N\)M = 180\(^o\) - (74\(^o\) + 39\(^o\)) 180\(^o\) - 113\(^o\) = 67\(^o\) L\(^O\) M = x = 2 x 67\(^o\) = 134\(^o\)	A
50.	Find the least value of x which satisfies the equation 4x = 7(mod 9) A. 7 B. 6 C. 5 D. 4 Show Content Detailed Solution 4x = 7 (mod 9) 4x = 7 + 9 (mod 9) \(\frac{4x}{4} = \frac{16}{4}\) (mod 9) x = 4	D

41.	The points on a linear graph are as shown in the table. Find the gradient (slope) of the line. A. 2\(\frac{1}{2}\) B. 2 C. 1 D. \(\frac{1}{2}\) Show Content Detailed Solution Gradient = \(\frac{y_2 - y_ 1}{x_2 - x_1}\) = \(\frac{5.20 - 3.90}{6.85 - 6.20}\) = \(\frac{1.3}{0.5}\) = 2	B
42.	In the diagram, O is the centre of the circle, PQ and RS are tangents to the circle. Find the value of (m + n). A. 120\(^o\) B. 90\(^o\) C. 75\(^o\) D. 60\(^o\) Show Content Detailed Solution m + n + 90\(^o\) + 180\(^o\) (sum of angle in a \(\triangle\)) m + n = 180\(^o\) - 90\(^o\) m + n =90\(^o\)	B
43.	Which of the following is not a sufficient condition for two triangles to be congruent? A. AAS B. SSS C. SAS D. SSA	D
44.	A woman received a discount of 20% on a piece of cloth she purchased from a shop. If she paid $525.00, what was the original price? A. $675.25 B. $660.25 C. $656.25 D. $616.25 Show Content Detailed Solution \(\frac{20}{100}\) x \(x\) = \(x - 525\) \(\frac{x}{5} = x\) - 535 x = 5x - 2625 \(\frac{4x}{4} = \frac{2625}{4}\) x = $656.25	C
45.	The interquartile range of distribution is 7. If the 25th percentile is 16, find the upper quartile. A. 35 B. 30 C. 23 D. 9 Show Content Detailed Solution Q\(_3\) - Q\(_1\) = 7 Q\(_3\) - 16 = 7 Q\(_3\) - 7 + 16 = 23	C

46.	The graph of the equations y = 2x + 5 and y = 2x\(^2\) + x - 1 are shown below. Find the points of intersection of the two graphs. A. (2.0, 9.0) and (-1.5, 2.0) B. (2.0, 8.5) and (-1.5, 2.0) C. (2.0, 8.0) and (-1.5, 2.5) D. (2.0, 7.5) and (-1.5, 2.5)	A
47.	The graph of the equations y = 2x + 5 and y = 2x\(^2\) + x - 1 are shown. If x = -2.5, what is the value of u on the curve? A. y = 8.0 B. y = 8.5 C. y = 9.0 D. y = 9.5 Show Content Detailed Solution If x = -2.5 y = 8.5	B
48.	If (x + 2) is a factor of x\(^2\) +px - 10, find the value of P. A. 3 B. -3 C. 7 D. -7 Show Content Detailed Solution x + 2 = 0 x -2 x\(^2\) = px - 10 = 0 (-2)\(^2\) - 2p - 10 = 0 4 - 2p - 10 = 0 \(\frac{-2p}{-2} = \frac{6}{-2}\) \(\to\) p = -3	B
49.	In the diagram, O is the centre of the circle. If < NLM = 74\(^o\), < LMN = 39\(^o\) and < LOM = x, find the value of x. A. 134\(^o\) B. 126\(^o\) C. 113\(^o\) D. 106\(^o\) Show Content Detailed Solution L\(N\)M = 180\(^o\) - (74\(^o\) + 39\(^o\)) 180\(^o\) - 113\(^o\) = 67\(^o\) L\(^O\) M = x = 2 x 67\(^o\) = 134\(^o\)	A
50.	Find the least value of x which satisfies the equation 4x = 7(mod 9) A. 7 B. 6 C. 5 D. 4 Show Content Detailed Solution 4x = 7 (mod 9) 4x = 7 + 9 (mod 9) \(\frac{4x}{4} = \frac{16}{4}\) (mod 9) x = 4	D