31 - 40 of 50 Questions
# | Question | Ans |
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31. |
In the diagram, \(\overline{PS}\)/\(\overline{SR}\), \(\overline{PS}\)/\(\overline{TR}\), \(\overline{QS}\)/\(\overline{UR}\), \(\overline{PS}\) = 15cm, \(\overline{SR}\) = 8cm, \(\overline{PS}\) = 10cm and area of \(\triangle\) SUR = 24cm\(^2\). Calculate the area of PTRS. A. 40 cm\(^2\) B. 48 cm\(^2\) C. 80 cm\(^2\) D. 120 cm\(^2\) Detailed SolutionArea PTRS = 10cm x 8cm= 80cm |
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32. |
In the diagram, PQR is a circle with centre O. If < OPQ = 48\(^o\), find the value of m A. 96\(^o\) B. 90\(^o\) C. 68\(^o\) D. 42\(^o\) Detailed Solution< O\(Q\)P = 48\(^o\) (base angles of isoceles \(\triangle\))m = 48\(^o\) + 48\(^o\) = 96\(^o\) (exterior angle of a \(\triangle\)) |
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33. |
The pie chart shows the population of men, women, and children in a city. If the population of the city is 1,800,000, how many men are in the city? A. 845,000 B. 600,000 C. 355,000 D. 250,000 Detailed SolutionAngle of Men = 360\(^o\) - (120 + 169)= 360\(^o\) - 289\(^o\) = 71\(^o\) No. of men \(\frac{71}{360}\) x 1800,000 = 355,000 |
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34. |
The mean of the numbers 15, 21, 17, 26, 18, and 29 is 21. Calculate the standard deviation A. 9 B. 6 C. 5 Detailed Solutionx15 21 17 26 18 29 -6 0 -4 5 -3 -8 36 0 16 25 9 64 Standard deviation = \(\sqrt{\frac{ \sum (x - \overline{x})^2}{n} }\) = \(\frac{150}{6}\) = \(\sqrt{25}\) = 5 |
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35. |
In the diagram, O is the centre of the circle. SOQ is the diameter and < SRP = 37\(^o\). Find < PSQ. A. 127\(^o\) B. 65\(^o\) C. 53\(^o\) D. 37\(^o\) Detailed Solution< PSQ = 180\(^o\) - (37\(^o\) + 90\(^o\)) = 180\(^o\) - 127\(^o\) = 53\(^o\) |
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36. |
Find the sum of the interior angle of a pentagon. A. 340\(^o\) B. 350\(^o\) C. 540\(^o\) D. 550\(^o\) Detailed SolutionSum = (5 - ) 180\(^o\)= (5 - 2) 180\(^o\) = 3 x 180\(^o\) = 540\(^o\) |
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37. |
The diameter of a sphere is 12 cm. Calculate, correct of the nearest cm\(^3\), the volume of the sphere, [Take \(\pi = \frac{22}{7}\)] A. 903 cm\(^3\) B. 904 cm\(^3\) C. 905 cm\(^3\) D. 906 cm\(^3\) |
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38. |
A box contains 12 identical balls of which 5 are red, 4 blue, and the rest are green. If a ball is selected at random from the box, what is the probability that it is green? A. \(\frac{3}{4}\) B. \(\frac{1}{2}\) C. \(\frac{1}{3}\) D. \(\frac{1}{4}\) Detailed SolutionNo. of red = 5No. of blue = 4 No. of green = 3 Total = 12 Pr(Green) = \(\frac{3}{12} = \frac{1}{4}\) |
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39. |
A box contains 12 identical balls of which 5 are red, 4 blue, and the rest are green. If two balls are selected at random one after the other with replacement, what is the probability that both are red? A. \(\frac{25}{144}\) B. \(\frac{5}{33}\) C. \(\frac{5}{6}\) D. \(\frac{103}{132}\) Detailed SolutionPr(RR) = \(\frac{5}{12}\) = \(\frac{5}{12} \times \frac{5}{12} = \frac{25}{144}\) |
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40. |
In the diagram PQ is a straight line. If m = \(\frac{1}{2}\) (x + y + z), find value of m. A. 45\(^o\) B. 60\(^o\) C. 90\(^o\) D. 100\(^o\) Detailed Solutionx + y + m + 2 = 180\(^o\)\(\frac{x + y + 2}{2} + \frac{m}{2}\) = 90\(^o\) m + \(\frac{m}{2} = 90^o\) 3m = 2 x 90\(^o\) \(\frac{3m}{3} = \frac{180^o}{3}\) m = 60\(^o\) |
31. |
In the diagram, \(\overline{PS}\)/\(\overline{SR}\), \(\overline{PS}\)/\(\overline{TR}\), \(\overline{QS}\)/\(\overline{UR}\), \(\overline{PS}\) = 15cm, \(\overline{SR}\) = 8cm, \(\overline{PS}\) = 10cm and area of \(\triangle\) SUR = 24cm\(^2\). Calculate the area of PTRS. A. 40 cm\(^2\) B. 48 cm\(^2\) C. 80 cm\(^2\) D. 120 cm\(^2\) Detailed SolutionArea PTRS = 10cm x 8cm= 80cm |
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32. |
In the diagram, PQR is a circle with centre O. If < OPQ = 48\(^o\), find the value of m A. 96\(^o\) B. 90\(^o\) C. 68\(^o\) D. 42\(^o\) Detailed Solution< O\(Q\)P = 48\(^o\) (base angles of isoceles \(\triangle\))m = 48\(^o\) + 48\(^o\) = 96\(^o\) (exterior angle of a \(\triangle\)) |
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33. |
The pie chart shows the population of men, women, and children in a city. If the population of the city is 1,800,000, how many men are in the city? A. 845,000 B. 600,000 C. 355,000 D. 250,000 Detailed SolutionAngle of Men = 360\(^o\) - (120 + 169)= 360\(^o\) - 289\(^o\) = 71\(^o\) No. of men \(\frac{71}{360}\) x 1800,000 = 355,000 |
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34. |
The mean of the numbers 15, 21, 17, 26, 18, and 29 is 21. Calculate the standard deviation A. 9 B. 6 C. 5 Detailed Solutionx15 21 17 26 18 29 -6 0 -4 5 -3 -8 36 0 16 25 9 64 Standard deviation = \(\sqrt{\frac{ \sum (x - \overline{x})^2}{n} }\) = \(\frac{150}{6}\) = \(\sqrt{25}\) = 5 |
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35. |
In the diagram, O is the centre of the circle. SOQ is the diameter and < SRP = 37\(^o\). Find < PSQ. A. 127\(^o\) B. 65\(^o\) C. 53\(^o\) D. 37\(^o\) Detailed Solution< PSQ = 180\(^o\) - (37\(^o\) + 90\(^o\)) = 180\(^o\) - 127\(^o\) = 53\(^o\) |
36. |
Find the sum of the interior angle of a pentagon. A. 340\(^o\) B. 350\(^o\) C. 540\(^o\) D. 550\(^o\) Detailed SolutionSum = (5 - ) 180\(^o\)= (5 - 2) 180\(^o\) = 3 x 180\(^o\) = 540\(^o\) |
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37. |
The diameter of a sphere is 12 cm. Calculate, correct of the nearest cm\(^3\), the volume of the sphere, [Take \(\pi = \frac{22}{7}\)] A. 903 cm\(^3\) B. 904 cm\(^3\) C. 905 cm\(^3\) D. 906 cm\(^3\) |
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38. |
A box contains 12 identical balls of which 5 are red, 4 blue, and the rest are green. If a ball is selected at random from the box, what is the probability that it is green? A. \(\frac{3}{4}\) B. \(\frac{1}{2}\) C. \(\frac{1}{3}\) D. \(\frac{1}{4}\) Detailed SolutionNo. of red = 5No. of blue = 4 No. of green = 3 Total = 12 Pr(Green) = \(\frac{3}{12} = \frac{1}{4}\) |
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39. |
A box contains 12 identical balls of which 5 are red, 4 blue, and the rest are green. If two balls are selected at random one after the other with replacement, what is the probability that both are red? A. \(\frac{25}{144}\) B. \(\frac{5}{33}\) C. \(\frac{5}{6}\) D. \(\frac{103}{132}\) Detailed SolutionPr(RR) = \(\frac{5}{12}\) = \(\frac{5}{12} \times \frac{5}{12} = \frac{25}{144}\) |
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40. |
In the diagram PQ is a straight line. If m = \(\frac{1}{2}\) (x + y + z), find value of m. A. 45\(^o\) B. 60\(^o\) C. 90\(^o\) D. 100\(^o\) Detailed Solutionx + y + m + 2 = 180\(^o\)\(\frac{x + y + 2}{2} + \frac{m}{2}\) = 90\(^o\) m + \(\frac{m}{2} = 90^o\) 3m = 2 x 90\(^o\) \(\frac{3m}{3} = \frac{180^o}{3}\) m = 60\(^o\) |