Mathematics (Core), 2012, JAMB Exam, Exam, Paper 1 | Objectives

Paper Info

Year :

2012

Title :

Mathematics (Core)

Exam :

JAMB Exam

Paper 1 | Objectives

41 - 48 of 48 Questions

#	Question	Ans
41.	In diagram above, QR//TU, < PQR = 80° and < PSU = 95°. Calculate < SUT. A. 15^o B. 25^o C. 30^o D. 80^o Show Content Detailed Solution < PQR = < PTU = 80° < TSU = 85° x = 180° - (80° + 85°) = 15° There is an explanation video available below.	A
42.	In the diagram above, PQR is a circle centre O. If < QPR is x°, find < QRP. A. x° B. (90 – x)° C. (90 + x)° D. (180 – x)° Show Content Detailed Solution < PQR = 90° (angle in a semi-circle) < QRP = (90 - x)° There is an explanation video available below.	B
43.	Find the area of the trapezium above. A. 91 cm² B. 78 cm² C. 60 cm² D. 19 cm² Show Content Detailed Solution Area of trapezium = \(\frac{1}{2} (a + b) \times h\) = \(\frac{1}{2} (7 + 13) \times 6\) = \(60 cm^{2}\) There is an explanation video available below.	C
44.	The grades of 36 students in a class test are as shown in the pie chart above. How many students have excellent? A. 12 B. 9 C. 8 D. 7 Show Content Detailed Solution Excellent = 360° - (120° + 90° + 80°) = 70° Number of excellent students = \(\frac{70}{360} \times 36\) = 7 students There is an explanation video available below.	D
45.	The bar chart above shows the distribution of marks in a class test. If the pass mark is 5, what percentage of students failed the test? A. 10% B. 20% C. 50% D. 60% Show Content Detailed Solution Number that score less than 5: 5 + 6 + 4 + 3 + 2 = 20 Total number of students: 5 + 6 + 4 + 3 + 2 + 4 + 6 + 5 + 1 + 3 + 1 = 40. %age of students that failed: \(\frac{20}{40} \times 100% = 50%\) There is an explanation video available below.	C
46.	A circular arc subtends angle 150° at the centre of a circle of radius 12cm. Calculate the area of the sector of the arc. A. 30\(\pi\) cm\(^2\) B. 60\(\pi\) cm\(^2\) C. 120\(\pi\) cm\(^2\) D. 150\(\pi\) cm\(^2\) Show Content Detailed Solution Area of sector = \(\frac{\theta}{360°} \times \pi r^{2}\) = \(\frac{150}{360} \times \pi \times 12^{2}\) = 60\(\pi\) cm\(^{2}\) There is an explanation video available below.	B
47.	A man stands on a tree 150 cm high and sees a boat at an angle of depression of 74°. Find the distance of the boat from the base of the tree. A. 52 cm B. 43 cm C. 40 cm D. 15 cm Show Content Detailed Solution \(\tan 16 = \frac{x}{150}\) \(x = 150 \tan 16\) = \(43 cm\) There is an explanation video available below.	B
48.	Find \(\frac{\mathrm d y}{\mathrm d x}\) if \(y = \cos x\). A. \(\sin x\) B. \(- \sin x\) C. \(\tan x\) D. \(- \tan x\) Show Content Detailed Solution If \(y = \cos x\) \(\frac{\mathrm d y}{\mathrm d x}\) =—\(\sin x\) There is an explanation video available below.	B

41.	In diagram above, QR//TU, < PQR = 80° and < PSU = 95°. Calculate < SUT. A. 15^o B. 25^o C. 30^o D. 80^o Show Content Detailed Solution < PQR = < PTU = 80° < TSU = 85° x = 180° - (80° + 85°) = 15° There is an explanation video available below.	A
42.	In the diagram above, PQR is a circle centre O. If < QPR is x°, find < QRP. A. x° B. (90 – x)° C. (90 + x)° D. (180 – x)° Show Content Detailed Solution < PQR = 90° (angle in a semi-circle) < QRP = (90 - x)° There is an explanation video available below.	B
43.	Find the area of the trapezium above. A. 91 cm² B. 78 cm² C. 60 cm² D. 19 cm² Show Content Detailed Solution Area of trapezium = \(\frac{1}{2} (a + b) \times h\) = \(\frac{1}{2} (7 + 13) \times 6\) = \(60 cm^{2}\) There is an explanation video available below.	C
44.	The grades of 36 students in a class test are as shown in the pie chart above. How many students have excellent? A. 12 B. 9 C. 8 D. 7 Show Content Detailed Solution Excellent = 360° - (120° + 90° + 80°) = 70° Number of excellent students = \(\frac{70}{360} \times 36\) = 7 students There is an explanation video available below.	D

45.	The bar chart above shows the distribution of marks in a class test. If the pass mark is 5, what percentage of students failed the test? A. 10% B. 20% C. 50% D. 60% Show Content Detailed Solution Number that score less than 5: 5 + 6 + 4 + 3 + 2 = 20 Total number of students: 5 + 6 + 4 + 3 + 2 + 4 + 6 + 5 + 1 + 3 + 1 = 40. %age of students that failed: \(\frac{20}{40} \times 100% = 50%\) There is an explanation video available below.	C
46.	A circular arc subtends angle 150° at the centre of a circle of radius 12cm. Calculate the area of the sector of the arc. A. 30\(\pi\) cm\(^2\) B. 60\(\pi\) cm\(^2\) C. 120\(\pi\) cm\(^2\) D. 150\(\pi\) cm\(^2\) Show Content Detailed Solution Area of sector = \(\frac{\theta}{360°} \times \pi r^{2}\) = \(\frac{150}{360} \times \pi \times 12^{2}\) = 60\(\pi\) cm\(^{2}\) There is an explanation video available below.	B
47.	A man stands on a tree 150 cm high and sees a boat at an angle of depression of 74°. Find the distance of the boat from the base of the tree. A. 52 cm B. 43 cm C. 40 cm D. 15 cm Show Content Detailed Solution \(\tan 16 = \frac{x}{150}\) \(x = 150 \tan 16\) = \(43 cm\) There is an explanation video available below.	B
48.	Find \(\frac{\mathrm d y}{\mathrm d x}\) if \(y = \cos x\). A. \(\sin x\) B. \(- \sin x\) C. \(\tan x\) D. \(- \tan x\) Show Content Detailed Solution If \(y = \cos x\) \(\frac{\mathrm d y}{\mathrm d x}\) =—\(\sin x\) There is an explanation video available below.	B