Mathematics (Core), 1991, WASSCE/WAEC MAY/JUNE, Exam, Paper 1 | Objectives

Paper Info

Year :

1991

Title :

Mathematics (Core)

Exam :

WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

31 - 40 of 50 Questions

#	Question	Ans
31.	P = {2, 1,3, 9, 1/2}; Q = {1,21/2,3, 7} and R = {5, 4, 21/2}. Find P∩Q∩R A. (2¹/₂) B. ∅ C. (1, 3, 7) D. (4) E. (5,7,9)	B
32.	In a class of 80 students, every student had to study Economics or Geography or both Economics and Geography. lf 65 students studied Economics and 50 studied Geography, how many studied both subjects? A. 15 B. 30 C. 35 D. 45 E. 50 Show Content Detailed Solution Applying the formula 80 = 65 - x + x + 50 - x x = 35	C
33.	Which of the following is not a measure of dispersion? A. Mode B. Mean deviation C. Range D. interquartile range E. Standard deviation	A
34.	The mean of 30 observations recorded in an experiment is 5. lf the observed largest value of 34 is deleted, find the mean of the remaining observations A. 5 B. 4 C. 3.9 D. 3.4 E. 3.0 Show Content Detailed Solution x = 5, \(\frac{\sum {fx}}{\sum {f}}\) = 5= \(\frac{\sum {fx}}{30}\) \(\sum {fx}\) = 5 x 30 = 150; 150 - 34 = 116 \(\sum {f}\) = 29 \(\sum {fx}\) = 116 = \(\frac{116}{29}\) = 4	B
35.	Find the mean of the distribution A. 3.5 B. 4.0 C. 4.4 D. 5.0 E. 5 Show Content Detailed Solution \(\bar{x}\) = \(\frac{2 + 14 + 15 + 16 + 45 + 42 + 42}{40}\) = \(\frac{176}{40}\) = 4.4	C
36.	Find the mode of the distribution A. 40 B. 9 C. 7 D. 5 E. 2	D
37.	Find the median of the distribution A. 9 B. 6.5 C. 5 D. 4.5 E. 4	C
38.	If events X and Y are mutually exclusive, . P(X) = 1/3 and P(Y) = 2/5, P(X∩Y) is A. o B. 2/15 C. 11/15 D. 4/15 E. 1 Show Content Detailed Solution P(X \(\cap\) Y) = \(\frac{1}{3} \times \frac{2}{5}\) = \(\frac{2}{15}\)	B
39.	If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is A. o B. 2/15 C. 4/14 D. 11/15 E. 1 Show Content Detailed Solution P(X \(\cup\) Y) = \(\frac{1}{3} + \frac{2}{5}\) = \(\frac{11}{15}\)	D
40.	A box contains 2 white and 3 blue identical marbles. If two marbles are picked at random, one after the other without replacement, what is the probability of picking two marbles of different colors? A. 2/3 B. 3/5 C. 2/5 D. 7/20 E. 3/10 Show Content Detailed Solution Total number of marbles = 5; 1st pick = 2/5 2nd pick = 3/4; 3rd pick = 3/5; 4th pick = 2/4 ∴ Probability of picking two marbles of different colors = (2/5 x 3/4) + (3/5 + 2/4) = 12/20 = 3/5	B

31.	P = {2, 1,3, 9, 1/2}; Q = {1,21/2,3, 7} and R = {5, 4, 21/2}. Find P∩Q∩R A. (2¹/₂) B. ∅ C. (1, 3, 7) D. (4) E. (5,7,9)	B
32.	In a class of 80 students, every student had to study Economics or Geography or both Economics and Geography. lf 65 students studied Economics and 50 studied Geography, how many studied both subjects? A. 15 B. 30 C. 35 D. 45 E. 50 Show Content Detailed Solution Applying the formula 80 = 65 - x + x + 50 - x x = 35	C
33.	Which of the following is not a measure of dispersion? A. Mode B. Mean deviation C. Range D. interquartile range E. Standard deviation	A
34.	The mean of 30 observations recorded in an experiment is 5. lf the observed largest value of 34 is deleted, find the mean of the remaining observations A. 5 B. 4 C. 3.9 D. 3.4 E. 3.0 Show Content Detailed Solution x = 5, \(\frac{\sum {fx}}{\sum {f}}\) = 5= \(\frac{\sum {fx}}{30}\) \(\sum {fx}\) = 5 x 30 = 150; 150 - 34 = 116 \(\sum {f}\) = 29 \(\sum {fx}\) = 116 = \(\frac{116}{29}\) = 4	B
35.	Find the mean of the distribution A. 3.5 B. 4.0 C. 4.4 D. 5.0 E. 5 Show Content Detailed Solution \(\bar{x}\) = \(\frac{2 + 14 + 15 + 16 + 45 + 42 + 42}{40}\) = \(\frac{176}{40}\) = 4.4	C

36.	Find the mode of the distribution A. 40 B. 9 C. 7 D. 5 E. 2	D
37.	Find the median of the distribution A. 9 B. 6.5 C. 5 D. 4.5 E. 4	C
38.	If events X and Y are mutually exclusive, . P(X) = 1/3 and P(Y) = 2/5, P(X∩Y) is A. o B. 2/15 C. 11/15 D. 4/15 E. 1 Show Content Detailed Solution P(X \(\cap\) Y) = \(\frac{1}{3} \times \frac{2}{5}\) = \(\frac{2}{15}\)	B
39.	If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is A. o B. 2/15 C. 4/14 D. 11/15 E. 1 Show Content Detailed Solution P(X \(\cup\) Y) = \(\frac{1}{3} + \frac{2}{5}\) = \(\frac{11}{15}\)	D
40.	A box contains 2 white and 3 blue identical marbles. If two marbles are picked at random, one after the other without replacement, what is the probability of picking two marbles of different colors? A. 2/3 B. 3/5 C. 2/5 D. 7/20 E. 3/10 Show Content Detailed Solution Total number of marbles = 5; 1st pick = 2/5 2nd pick = 3/4; 3rd pick = 3/5; 4th pick = 2/4 ∴ Probability of picking two marbles of different colors = (2/5 x 3/4) + (3/5 + 2/4) = 12/20 = 3/5	B