Mathematics (Core)
Paper 1 | Objectives | 48 Questions
JAMB Exam
Year: 1991
Level: SHS
Time:
Type: Question Paper
Answers provided
FREE
No description provided
Feedbacks
This paper is yet to be rated
Paper 1 | Objectives | 48 Questions
JAMB Exam
Year: 1991
Level: SHS
Time:
Type: Question Paper
Answers provided
No description provided
This paper is yet to be rated
DAAD scholarship to assist Sub-Saharan African students fleeing war in Ukraine to complete their studies
Scholarship in Norway universities are open for application in 2022 also for developing countries.
Did you apply the MTN Ghana Bright Scholarships 2022 for Ghana Undergraduate Students?
| # | Question | Ans |
|---|---|---|
| 1. |
Simplify 3\(\frac{1}{3}\) - 1\(\frac{1}{4}\) x \(\frac{2}{3}\) + 1\(\frac{2}{5}\) A. 2 B. 3 C. 4 D. 5
Show Content
Detailed Solution3 - \(\frac{1}{3}\) - (\(\frac{5}{4}\) x \(\frac{2}{3}\)) + 1\(\frac{2}{5}\)= \(\frac{10}{3}\) - \(\frac{5}{6}\) + \(\frac{7}{5}\) = \(\frac{100 - 25 + 42}{30}\) = \(\frac{117}{30}\) = 3.9 \(\approx\) 4 |
|
| 2. |
If 2257 is the result of subtracting 4577 from 7056 in base n, find n A. 8 B. 9 C. 10 D. 11
Show Content
Detailed Solution\(\begin{array}{c|c} 7056 \\ \text{- 4577} \\\hline 2257 \end{array}\)By trial and error method Let the base to 8 i.e. Let n = 8 and it is easily verified that the subtraction holds. The subtraction does not hold when other values of n are tried n = 8 |
|
| 3. |
Find correct to 3 decimal places (\(\frac{1}{0.05}\) + \(\frac{1}{5.005}\)) - (0.05 x 2.05) A. 99.998 B. 98.999 C. 89.899 D. 9.998
Show Content
Detailed Solution(\(\frac{1}{0.05}\) + \(\frac{1}{5.005}\)) - (0.05 x 2.05)(\(\frac{1}{0.05}\) x 5.005) - (0.05 x 2.05) \(\frac{5.005}{0.05}\) - 0.1025 100.1 - 0.1025 = 99.9975 99.998 to 3 decimal place. |
|
| 4. |
Express 62 \(\div\) 3 as a decimal correct to 3 significant figures A. 20.6 B. 20.667 C. 20.67 D. 20.7
Show Content
Detailed Solution\(\frac{62}{3}\) = 20.6666.....= 20.7 to 3 sig. fig. |
|
| 5. |
Factory P produces 20,000 bags of cement per day while factory Q produces 15,000 bags per day. If P reduces production by 5% and Q increases production by 5%, determine the effective loss in the number of bags produced per day by the two factories A. 250 B. 750 C. 1000 D. 1250
Show Content
Detailed SolutionP produces 20,000 bagsP reduces production by 5% i.e. reduction = \(\frac{5}{100}\) x \(\frac{20000}{1}\) = 1000 Q produces 15000 bags Q increases production by 5% i.e. increase = \(\frac{5}{100}\) x \(\frac{15000}{1}\) = 750 Effective loss by the two = 1000 - 750 = 250 bags |
|
| 6. |
Musa borrows N10.00 at 2% per month simple interest and repays N8.00 after 4 months. How much does he still owe? A. N10.80 B. N10.67 C. N2.80 D. N2.67
Show Content
Detailed SolutionI = \(\frac{PRT}{100}\)= \(\frac{10 \times 2 \times 4}{100}\) = \(\frac{4}{5}\) = 0.8 Total amount = N10.80 He pays N8.00 Remainder = 10.80 - 8.00 = N2.80 |
|
| 7. |
If 3 gallons of spirit containing 20% water are added to 5 gallons of another spirit containing 15% water, what percentage of the mixture is water? A. 2\(\frac{4}{5}\)% B. 16\(\frac{7}{8}\)% C. 18\(\frac{1}{8}\)% D. 18\(\frac{7}{8}\)%
Show Content
Detailed Solution% of water in the mixture= \(\frac{\text{Total Amount of water}}{\text{Total quantity of spirit}}\) x \(\frac{100}{1}\) \(\frac{3(\frac{20}{100}) + 5 (\frac{15}{100})}{3 + 5}\) x \(\frac{100}{1}\) = \(\frac{\frac{6}{10} + \frac{75}{100}}{8}\) x \(\frac{100}{1}\) = \(\frac{0.6 + 0.75}{8}\) x \(\frac{100}{1}\) = \(\frac{1.35}{8}\) x \(\frac{100}{1}\) = \(\frac{33.75}{2}\) = 16.875 = 16\(\frac{7}{8}\) |
|
| 8. |
What is the product of \(\frac{27}{5^1}\)(3)-3 and \(\frac{(1)^{-1}}{5}\)? A. 5 B. 3 C. 1 D. \(\frac{1}{25}\)
Show Content
Detailed Solution\(\frac{27}{5^1}\)(3)-3 x \(\frac{(1)^{-1}}{5}\) = \(\frac{27}{5}\) x \(\frac{1}{3^3}\) x \(\frac{1}{\frac{1}{5}}\)= \(\frac{27}{5}\) x \(\frac{1}{27}\) x \(\frac{1}{5}\) = \(\frac{1}{25}\) |
|
| 9. |
Simplify 2log \(\frac{2}{5}\) - log\(\frac{72}{125}\) + log 9 A. 1 - 4 log3 B. -1 + 2 log 3 C. -1 + 5 log2 D. 1 - 2log 2
Show Content
Detailed Solution2log \(\frac{2}{5}\) - log\(\frac{72}{125}\) + log 9[\(\frac{2}{5}\))2 x 9] = log \(\frac{4}{25}\) x \(\frac{9}{1}\) x \(\frac{125}{72}\) = log \(\frac{72}{125}\) = log \(\frac{5}{2}\) = log \(\frac{10}{4}\) = log 10 - log 4 = log10 10 - log10 22 = 1 - 2 log2 |
|
| 10. |
Simplify \(\frac{1}{1 + \sqrt{5}}\) - \(\frac{1}{1 - \sqrt{5}}\) A. - \(\frac{1}{2}\sqrt{5}\) B. \(\frac{1}{2}\sqrt{5}\) C. -- \(\frac{1}{4}\sqrt{5}\) D. 5
Show Content
Detailed Solution\(\frac{1}{1 + \sqrt{5}}\) - \(\frac{1}{1 - \sqrt{5}}\)= \(\frac{1 - \sqrt{5} - 1 - \sqrt{5}}{(1 + \sqrt{5}) (1 - \sqrt{5}}\) = \(\frac{-2\sqrt{5}}{1 - 5}\) = \(\frac{-2\sqrt{5}}{- 4}\) = \(\frac{1}{2}\sqrt{5}\) |
Preview displays only 10 out of the 48 Questions