21 - 30 of 48 Questions
# | Question | Ans |
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21. |
Calculate the surface area of a hallow cylinder which is closed at one end, if the base radius is 3.5cm and the height 8cm.[take π = 22/7] A. 126.5cm2 B. 165cm2 C. 176cm2 D. 214.5cm2 E. 253.5cm2 Detailed Solutionsince it is an open cylinder; r= 3.5cm = 7/2cmh= 8cm; S.A = 2πrh + πr 2 = πr(2h + r) (16 + 3.5); 11 x 19.5 = 214.5cm2 |
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22. |
Solve the following equation: 6x\(^2\) - 7x - 5 = 0 A. x = 1/2 or x = -21/2 B. x = 1/3 or x = 21/2 C. x = 1 2/3 or x = -1/2 D. x = 12/3 or x = 1/2 E. x = 5/6 or x = -1 Detailed Solution6x\(^2\) - 7x - 5 = 06x\(^2\) - 10x + 3x - 5 = 0 2x(3x - 5) + 1(3x - 5) = 0 (2x + 1)(3x - 5) = 0 x = \(\frac{5}{3}\) or x = \(-\frac{1}{2}\) |
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23. |
What angle represents grown up girls ? Correct to one decimal place A. 37.5o B. 26.7o C. 25.7o D. 20o E. 3.75o Detailed SolutionTotal population = 1400 + 550 + 200 + 150 + 400 = 2700grown up girls = 200 = \(\frac {200}{2700}\) x \(\frac {360}{1}\) =80/3 = 26.7° |
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24. |
What percentage of the population are married? correct to one decimal place A. 14.8% B. 20.4% C. 30.5% D. 35.2% E. 36.5% Detailed SolutionMarried = 550 + 400 = 950Married% = \(\frac {950}{2700}\) x \(\frac {100}{1}\) =35.2% |
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25. |
If A = {a,b,c}, B = {a,b,c,d,e} and C = {a,b,c,d,e,f}. Find (A∪B)∩(A∪C) A. {a,b,c,d} B. {a,b,c,d,e} C. {a,b,c,d,e,f} D. {a,b,c} E. Φ Detailed SolutionA = {a, b, c}; B = {a, b, c, d, e}; C = {a, b, c, d, e, f}(A \(\cup\) B) = {a, b, c, d, e} (A \(\cup\) C) = {a, b, c, d, e, f} (A \(\cup\) B) \(\cap\) (A \(\cup\) C) = {a, b, c, d, e} |
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For a class of 30 students, the scores in a Mathematics test out of 10 marks were as follows; |
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26. |
What is the mode of the score A. 3 B. 4 C. 5 D. 6 E. 7 |
E |
27. |
What is the median score? A. 2 B. 7 C. 8 D. 9 E. 10 |
C |
28. |
What is the range of the distribution? A. 2 B. 7 C. 8 D. 9 E. 10 |
B |
29. |
In the diagram above O is the center of the circle, if ∠PAQ = 75o, what is the value of ∠PBQ? A. 15o B. 75o C. 105o D. 150o E. 210o Detailed Solution< PBQ = 180° - 75° (opp angles of a cyclic quadrilateral)= 105° |
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30. |
Simplify \(\frac{9^{-\frac{1}{2}}}{27^{\frac{2}{3}}}\) A. 1 B. 1/3 C. 1/9 D. 1/18 E. 1/27 Detailed Solution\(\frac{9^{-\frac{1}{2}}}{27^{\frac{2}{3}}}\)=\(\frac{3^{-1}}{3^2}\) = \(\frac{1}{27}\) |
21. |
Calculate the surface area of a hallow cylinder which is closed at one end, if the base radius is 3.5cm and the height 8cm.[take π = 22/7] A. 126.5cm2 B. 165cm2 C. 176cm2 D. 214.5cm2 E. 253.5cm2 Detailed Solutionsince it is an open cylinder; r= 3.5cm = 7/2cmh= 8cm; S.A = 2πrh + πr 2 = πr(2h + r) (16 + 3.5); 11 x 19.5 = 214.5cm2 |
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22. |
Solve the following equation: 6x\(^2\) - 7x - 5 = 0 A. x = 1/2 or x = -21/2 B. x = 1/3 or x = 21/2 C. x = 1 2/3 or x = -1/2 D. x = 12/3 or x = 1/2 E. x = 5/6 or x = -1 Detailed Solution6x\(^2\) - 7x - 5 = 06x\(^2\) - 10x + 3x - 5 = 0 2x(3x - 5) + 1(3x - 5) = 0 (2x + 1)(3x - 5) = 0 x = \(\frac{5}{3}\) or x = \(-\frac{1}{2}\) |
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23. |
What angle represents grown up girls ? Correct to one decimal place A. 37.5o B. 26.7o C. 25.7o D. 20o E. 3.75o Detailed SolutionTotal population = 1400 + 550 + 200 + 150 + 400 = 2700grown up girls = 200 = \(\frac {200}{2700}\) x \(\frac {360}{1}\) =80/3 = 26.7° |
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24. |
What percentage of the population are married? correct to one decimal place A. 14.8% B. 20.4% C. 30.5% D. 35.2% E. 36.5% Detailed SolutionMarried = 550 + 400 = 950Married% = \(\frac {950}{2700}\) x \(\frac {100}{1}\) =35.2% |
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25. |
If A = {a,b,c}, B = {a,b,c,d,e} and C = {a,b,c,d,e,f}. Find (A∪B)∩(A∪C) A. {a,b,c,d} B. {a,b,c,d,e} C. {a,b,c,d,e,f} D. {a,b,c} E. Φ Detailed SolutionA = {a, b, c}; B = {a, b, c, d, e}; C = {a, b, c, d, e, f}(A \(\cup\) B) = {a, b, c, d, e} (A \(\cup\) C) = {a, b, c, d, e, f} (A \(\cup\) B) \(\cap\) (A \(\cup\) C) = {a, b, c, d, e} |
For a class of 30 students, the scores in a Mathematics test out of 10 marks were as follows; |
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26. |
What is the mode of the score A. 3 B. 4 C. 5 D. 6 E. 7 |
E |
27. |
What is the median score? A. 2 B. 7 C. 8 D. 9 E. 10 |
C |
28. |
What is the range of the distribution? A. 2 B. 7 C. 8 D. 9 E. 10 |
B |
29. |
In the diagram above O is the center of the circle, if ∠PAQ = 75o, what is the value of ∠PBQ? A. 15o B. 75o C. 105o D. 150o E. 210o Detailed Solution< PBQ = 180° - 75° (opp angles of a cyclic quadrilateral)= 105° |
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30. |
Simplify \(\frac{9^{-\frac{1}{2}}}{27^{\frac{2}{3}}}\) A. 1 B. 1/3 C. 1/9 D. 1/18 E. 1/27 Detailed Solution\(\frac{9^{-\frac{1}{2}}}{27^{\frac{2}{3}}}\)=\(\frac{3^{-1}}{3^2}\) = \(\frac{1}{27}\) |