Year : 
2015
Title : 
Mathematics (Core)
Exam : 
JAMB Exam

Paper 1 | Objectives

61 - 62 of 62 Questions

# Question Ans
61.

Factorize \( a^2 − b^2 − 4a + 4 \)

A. (a + b)(a − b)

B. (a − 2 + b)(a - 2- b)

C. (a + 1)(a − 2 + b)

D. (a + b) 2

Detailed Solution

The trinomial = \( a^2 − 4a + 4 \\

a^2 − b^2− 4a + 4 = (a^2 − 4a + 4) − b^2 \\

(a^2 − 2a − 2a + 4) − b^2 \\

a(a − 2)− 2(a − 2)] − b^2 \\

(a − 2)2 − b^2 \\

(a − 2 + b)(a − 2 − b )\)
There is an explanation video available below.
62.

Given that tan x = \(\frac{2}{3}\), where 0o d" x d" 90o, Find the value of 2sinx.

A. \(\frac{2\sqrt{13}}{13}\)

B. \(\frac{3\sqrt{13}}{13}\)

C. \(\frac{4\sqrt{13}}{13}\)

D. \(\frac{6\sqrt{13}}{13}\)

Detailed Solution

There is an explanation video available below.
61.

Factorize \( a^2 − b^2 − 4a + 4 \)

A. (a + b)(a − b)

B. (a − 2 + b)(a - 2- b)

C. (a + 1)(a − 2 + b)

D. (a + b) 2

Detailed Solution

The trinomial = \( a^2 − 4a + 4 \\

a^2 − b^2− 4a + 4 = (a^2 − 4a + 4) − b^2 \\

(a^2 − 2a − 2a + 4) − b^2 \\

a(a − 2)− 2(a − 2)] − b^2 \\

(a − 2)2 − b^2 \\

(a − 2 + b)(a − 2 − b )\)
There is an explanation video available below.
62.

Given that tan x = \(\frac{2}{3}\), where 0o d" x d" 90o, Find the value of 2sinx.

A. \(\frac{2\sqrt{13}}{13}\)

B. \(\frac{3\sqrt{13}}{13}\)

C. \(\frac{4\sqrt{13}}{13}\)

D. \(\frac{6\sqrt{13}}{13}\)

Detailed Solution

There is an explanation video available below.