Year :
2015
Title :
Mathematics (Core)
Exam :
JAMB Exam
Paper 1 | Objectives
31 - 40 of 62 Questions
| # | Question | Ans |
|---|---|---|
| 31. |
The volume of a cylinder whose height is 4cm and whose radius 5cm is equal to (π = 3.14) A. 3.13cm2 B. 145cm2 C. 314cm2 D. 214cm2 |
|
| 32. |
The probability of an event A is 1/5. The probability of B is 1/3 . The probability both A and B is 1/15. What is the probability of either event A or B or both A. \( \frac{2}{15} \) B. \( \frac{3}{4} \) C. \( \frac{9}{15} \) D. \( \frac{1}{15} \) |
|
| 33. |
If (159.75)10 = (x)6. Find x A. x6 = 123.346 B. x6 = 424.56 C. x6 = 122.436 D. x6 = 124.456 Detailed Solution(159.75)10 = (y)6\( \begin{array}{c|c} 6 & 159 \\ \hline 6 & 26 \text{ rem 3} \\ 6 & 4 \text{ rem 2} \\ & 0 \text{ rem 4} \\ \end{array}\uparrow \) 15910 = 4236 Then Convert 0.75 to base 6 0.75 x 6 =4.5 i.e 4.5 - 3.00 = 1.5 0.5 x 6 = 3.00 423 + 1.5 =424.5 159.75 = (424.5)6 (159)10 = (424.5)6 There is an explanation video available below. |
|
| 34. |
A man bought a car for N800 and sold it for N520. Find his loss per cent A. 15% B. 25% C. 35% D. 10% |
|
| 35. |
Simplify \(6\frac{1}{12} − 2 ¾ + 1 ½ \) A. \( 3 \frac{5}{6}\) B. \( 4 \frac{5}{6}\) C. \( 2 \frac{1}{6}\) D. \( \frac{1}{3} \) |
|
| 36. |
Find the distance between the points (-2,-3) and (-2,4) A. 3m B. 2.4m C. 3.2m D. 7.0m |
|
| 37. |
Determine the third term of a geometrical progression whose first and second term are 2 and 54 respectively A. 1458 B. 1485 C. 1345 D. 1258 Detailed Solution1st G.P. = a =22nd G.P. = ar\(^{2 −1}\) = 54 2(r) = 54 r = 54/2 = 27 r = 27 3rd term = ar\(^2\) = (2) (27)\(^2\) 2 × 27 × 27 = 1458 There is an explanation video available below. |
|
| 38. |
Given that S and T are sets of real numbers such that S = {x : 0 \(\leq\) x \(\leq\) 5} and T = {x : − 2 < x < 3} Find S \(\cup\) T A. −3 < x < \(\leq\)3 B. −2< x < \(\leq\)5 C. 2< x < \(\geq\) −5 D. −1< x \(\geq\) \(\leq\)2 |
|
| 39. |
If an investor invest N450,000 in a certain organization in order to yield X as a return of N25,000. Find the return on an investment of N700,000 by Y in the same organization. A. N14,950.50K B. N25,150.30K C. N15,000.00K D. N38,888.90K |
|
| 40. |
Evaluate log717 A. 1.35 B. 1.353 C. 1.455 D. 0.455 |
| 31. |
The volume of a cylinder whose height is 4cm and whose radius 5cm is equal to (π = 3.14) A. 3.13cm2 B. 145cm2 C. 314cm2 D. 214cm2 |
|
| 32. |
The probability of an event A is 1/5. The probability of B is 1/3 . The probability both A and B is 1/15. What is the probability of either event A or B or both A. \( \frac{2}{15} \) B. \( \frac{3}{4} \) C. \( \frac{9}{15} \) D. \( \frac{1}{15} \) |
|
| 33. |
If (159.75)10 = (x)6. Find x A. x6 = 123.346 B. x6 = 424.56 C. x6 = 122.436 D. x6 = 124.456 Detailed Solution(159.75)10 = (y)6\( \begin{array}{c|c} 6 & 159 \\ \hline 6 & 26 \text{ rem 3} \\ 6 & 4 \text{ rem 2} \\ & 0 \text{ rem 4} \\ \end{array}\uparrow \) 15910 = 4236 Then Convert 0.75 to base 6 0.75 x 6 =4.5 i.e 4.5 - 3.00 = 1.5 0.5 x 6 = 3.00 423 + 1.5 =424.5 159.75 = (424.5)6 (159)10 = (424.5)6 There is an explanation video available below. |
|
| 34. |
A man bought a car for N800 and sold it for N520. Find his loss per cent A. 15% B. 25% C. 35% D. 10% |
|
| 35. |
Simplify \(6\frac{1}{12} − 2 ¾ + 1 ½ \) A. \( 3 \frac{5}{6}\) B. \( 4 \frac{5}{6}\) C. \( 2 \frac{1}{6}\) D. \( \frac{1}{3} \) |
| 36. |
Find the distance between the points (-2,-3) and (-2,4) A. 3m B. 2.4m C. 3.2m D. 7.0m |
|
| 37. |
Determine the third term of a geometrical progression whose first and second term are 2 and 54 respectively A. 1458 B. 1485 C. 1345 D. 1258 Detailed Solution1st G.P. = a =22nd G.P. = ar\(^{2 −1}\) = 54 2(r) = 54 r = 54/2 = 27 r = 27 3rd term = ar\(^2\) = (2) (27)\(^2\) 2 × 27 × 27 = 1458 There is an explanation video available below. |
|
| 38. |
Given that S and T are sets of real numbers such that S = {x : 0 \(\leq\) x \(\leq\) 5} and T = {x : − 2 < x < 3} Find S \(\cup\) T A. −3 < x < \(\leq\)3 B. −2< x < \(\leq\)5 C. 2< x < \(\geq\) −5 D. −1< x \(\geq\) \(\leq\)2 |
|
| 39. |
If an investor invest N450,000 in a certain organization in order to yield X as a return of N25,000. Find the return on an investment of N700,000 by Y in the same organization. A. N14,950.50K B. N25,150.30K C. N15,000.00K D. N38,888.90K |
|
| 40. |
Evaluate log717 A. 1.35 B. 1.353 C. 1.455 D. 0.455 |