Year : 
2017
Title : 
Chemistry
Exam : 
JAMB Exam

Paper 1 | Objectives

21 - 30 of 49 Questions

# Question Ans
21.

\(^{226}_{88}Ra\) → \(^x_{86}Rn\) + alpha particle

A. 226

B. 220

C. 227

D. 222

Detailed Solution

\(^{226}_{88}Ra\) → \(^x_{86}Rn\) + \(^4_{2}He\)

\(^4_{2}He\) = alpha particle

considering the summation of the mass number

226 = x + 4

x = 226 - 4

x = 222
There is an explanation video available below.
22.

The shape of ammonia molecules is

A. trigonal planar

B. octahedral

C. square planar

D. tetrahedral

Detailed Solution

There is an explanation video available below.
23.

The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is – (Ag = 108 F = 96500(mol-1)

A. 54.0g

B. 27.0g

C. 13.5g

D. 108.0g

Detailed Solution

Recall that

mass deposited = \(\frac{MmIt}{96500n}\)

Mm =108, t = 4830s

I = 10A, n = 1

m = 108 × 10 × (\(\frac{4830}{96500}\)) × 1

m = 54.0g
There is an explanation video available below.
24.

Tin is unaffected by air at ordinary temperature due to its

A. Low melting point

B. Weak electropositive character

C. High boiling point

D. White lustrous appearance

Detailed Solution

There is an explanation video available below.
25.

Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol-1]

A. 0.05

B. 10.80

C. 10.00

D. 0.10

Detailed Solution

There is an explanation video available below.
26.

The reaction of halogens with alkanes in the presence of sunlight is an example of

A. oxidation reaction

B. addition reaction

C. hydrogenation reaction

D. substitution reaction

Detailed Solution

Alkanes undergoes substitution reaction and it is an example of halogenation substitution reaction.

Reaction of halogen with alkane in the presence of sunlight (ultraviolet) is termed halogenation. Halogenation is an example of substitution reaction. In addition, alkanes only undergo substitution reaction but not addition reaction.
There is an explanation video available below.
27.

The enzyme used in the hydrolysis of starch to dextrin and maltose is?

A. lipase

B. amylase

C. invertase

D. zymase

Detailed Solution

Starch is hydrolyzed by dilute acids to yield a mixture of dextrin (a shorter chain intermediate product), disaccharides (mainly maltose) and glucose. Further hydrolysis will eventually give glucose. Hydrolysis of starch to dextrin and maltose can also be brought about by the enzyme amylase present in saliva and in malt.
There is an explanation video available below.
28.

The alkyl group is represented by the general formula

A. CnH2n

B. CnH2n − 2

C. CnH2n + 1

D. CnH2n + 2

Detailed Solution

There is an explanation video available below.
29.

Cu2S(g) + O2(g) → 2Cu + SO2(g)
What is the change in the oxidation number of copper in the reaction?

A. 0 to + 2

B. 0 to + 1

C. + 1 to 0

D. + 2 to + 1

Detailed Solution

In the reactant;

Cu2S

2 Cu - 2(1) = 0

2 Cu = 2

Cu = \(\frac{2}{2}\)

Cu = +1

In the product, Cu

Cu = O

The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively
There is an explanation video available below.
30.

In the diagram above. X is

A. SO3

B. SO2

C. S

D. H2S

Detailed Solution

The setup represents the production of sulfur dioxide. And the cylinder marked X is SO2
There is an explanation video available below.
21.

\(^{226}_{88}Ra\) → \(^x_{86}Rn\) + alpha particle

A. 226

B. 220

C. 227

D. 222

Detailed Solution

\(^{226}_{88}Ra\) → \(^x_{86}Rn\) + \(^4_{2}He\)

\(^4_{2}He\) = alpha particle

considering the summation of the mass number

226 = x + 4

x = 226 - 4

x = 222
There is an explanation video available below.
22.

The shape of ammonia molecules is

A. trigonal planar

B. octahedral

C. square planar

D. tetrahedral

Detailed Solution

There is an explanation video available below.
23.

The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is – (Ag = 108 F = 96500(mol-1)

A. 54.0g

B. 27.0g

C. 13.5g

D. 108.0g

Detailed Solution

Recall that

mass deposited = \(\frac{MmIt}{96500n}\)

Mm =108, t = 4830s

I = 10A, n = 1

m = 108 × 10 × (\(\frac{4830}{96500}\)) × 1

m = 54.0g
There is an explanation video available below.
24.

Tin is unaffected by air at ordinary temperature due to its

A. Low melting point

B. Weak electropositive character

C. High boiling point

D. White lustrous appearance

Detailed Solution

There is an explanation video available below.
25.

Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol-1]

A. 0.05

B. 10.80

C. 10.00

D. 0.10

Detailed Solution

There is an explanation video available below.
26.

The reaction of halogens with alkanes in the presence of sunlight is an example of

A. oxidation reaction

B. addition reaction

C. hydrogenation reaction

D. substitution reaction

Detailed Solution

Alkanes undergoes substitution reaction and it is an example of halogenation substitution reaction.

Reaction of halogen with alkane in the presence of sunlight (ultraviolet) is termed halogenation. Halogenation is an example of substitution reaction. In addition, alkanes only undergo substitution reaction but not addition reaction.
There is an explanation video available below.
27.

The enzyme used in the hydrolysis of starch to dextrin and maltose is?

A. lipase

B. amylase

C. invertase

D. zymase

Detailed Solution

Starch is hydrolyzed by dilute acids to yield a mixture of dextrin (a shorter chain intermediate product), disaccharides (mainly maltose) and glucose. Further hydrolysis will eventually give glucose. Hydrolysis of starch to dextrin and maltose can also be brought about by the enzyme amylase present in saliva and in malt.
There is an explanation video available below.
28.

The alkyl group is represented by the general formula

A. CnH2n

B. CnH2n − 2

C. CnH2n + 1

D. CnH2n + 2

Detailed Solution

There is an explanation video available below.
29.

Cu2S(g) + O2(g) → 2Cu + SO2(g)
What is the change in the oxidation number of copper in the reaction?

A. 0 to + 2

B. 0 to + 1

C. + 1 to 0

D. + 2 to + 1

Detailed Solution

In the reactant;

Cu2S

2 Cu - 2(1) = 0

2 Cu = 2

Cu = \(\frac{2}{2}\)

Cu = +1

In the product, Cu

Cu = O

The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively
There is an explanation video available below.
30.

In the diagram above. X is

A. SO3

B. SO2

C. S

D. H2S

Detailed Solution

The setup represents the production of sulfur dioxide. And the cylinder marked X is SO2
There is an explanation video available below.