Mathematics (Core), 2009, WASSCE/WAEC MAY/JUNE, Exam, Paper 1 | Objectives

Paper Info

Year :

2009

Title :

Mathematics (Core)

Exam :

WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

41 - 46 of 46 Questions

#	Question	Ans
41.	If /XY/ = 50m, how far cast of X is Y? A. 25.5m B. 40.6m C. 40.8m D. 43.3m Show Content Detailed Solution Required distance = x where \(\frac{1}{50m}\) = sin 60 x 50m x 0.866 x = 43.3m	D
42.	In the diagram, angle 20^o is subtended at the centre of the circle, find the value of x A. 30^o B. 50^o C. 80^o D. 100^o Show Content Detailed Solution 2(30 + x) = 360 - 200 60 + 2x = 160 2x = 160 - 60 2x = 100 x = \(\frac{100}{2}\) x = 50	B
43.	The pie chart shows the distribution of 4320 students who graduated from four departments in a university. How many students graduated from the science department? A. 840 B. 864 C. 920 D. 960 Show Content Detailed Solution \(\frac{\text{science}}{\text{graduates}}\) = \(\frac{\theta}{360}\) x 4320 where \(\theta\) + 100 + 80 + 108 = 360 \(\theta\) = 360 - 288 = 360 \(\frac{\text{science}}{\text{graduates}}\) = \(\frac{72}{360} \times 4320\) = 864	B
44.	The pie chart shows the distribution of 4320 students who graduated from four departments in a university. If a student is picked at random from the four departments, what id the probability that he is not from the education department? A. \(\frac{3}{10}\) B. \(\frac{2}{9}\) C. \(\frac{5}{18}\) D. \(\frac{7}{10}\) Show Content Detailed Solution \(\frac{\text{education}}{\text{graduates}} = \frac{108}{360} \times 4320\) = 1296 Pr(Education) = \(\frac{1296}{4320} = \frac{1}{10}\) pr(not education) = 1 - \(\frac{3}{10}\) = \(\frac{10 - 3}{10}\) = \(\frac{7}{10}\)	D
45.	From the diagram which of the following statements are correct? i. XQ is a radius of a circle centre Q. ii. /XQ/ = /QY/. iii. /QX/ = /XY/ A. i only B. inand ii only C. ii and iii only D. i, ii and iii	B
46.	Find the value of x in the diagram A. 50^o B. 60^o C. 70^o D. 80^o Show Content Detailed Solution 30 + x = 100 x = 100 - 30 = 70^o	C

41.	If /XY/ = 50m, how far cast of X is Y? A. 25.5m B. 40.6m C. 40.8m D. 43.3m Show Content Detailed Solution Required distance = x where \(\frac{1}{50m}\) = sin 60 x 50m x 0.866 x = 43.3m	D
42.	In the diagram, angle 20^o is subtended at the centre of the circle, find the value of x A. 30^o B. 50^o C. 80^o D. 100^o Show Content Detailed Solution 2(30 + x) = 360 - 200 60 + 2x = 160 2x = 160 - 60 2x = 100 x = \(\frac{100}{2}\) x = 50	B
43.	The pie chart shows the distribution of 4320 students who graduated from four departments in a university. How many students graduated from the science department? A. 840 B. 864 C. 920 D. 960 Show Content Detailed Solution \(\frac{\text{science}}{\text{graduates}}\) = \(\frac{\theta}{360}\) x 4320 where \(\theta\) + 100 + 80 + 108 = 360 \(\theta\) = 360 - 288 = 360 \(\frac{\text{science}}{\text{graduates}}\) = \(\frac{72}{360} \times 4320\) = 864	B

44.	The pie chart shows the distribution of 4320 students who graduated from four departments in a university. If a student is picked at random from the four departments, what id the probability that he is not from the education department? A. \(\frac{3}{10}\) B. \(\frac{2}{9}\) C. \(\frac{5}{18}\) D. \(\frac{7}{10}\) Show Content Detailed Solution \(\frac{\text{education}}{\text{graduates}} = \frac{108}{360} \times 4320\) = 1296 Pr(Education) = \(\frac{1296}{4320} = \frac{1}{10}\) pr(not education) = 1 - \(\frac{3}{10}\) = \(\frac{10 - 3}{10}\) = \(\frac{7}{10}\)	D
45.	From the diagram which of the following statements are correct? i. XQ is a radius of a circle centre Q. ii. /XQ/ = /QY/. iii. /QX/ = /XY/ A. i only B. inand ii only C. ii and iii only D. i, ii and iii	B
46.	Find the value of x in the diagram A. 50^o B. 60^o C. 70^o D. 80^o Show Content Detailed Solution 30 + x = 100 x = 100 - 30 = 70^o	C