Year :
2014
Title :
Mathematics (Core)
Exam :
JAMB Exam
Paper 1 | Objectives
41 - 47 of 47 Questions
| # | Question | Ans |
|---|---|---|
| 41. |
 From the venn diagram above, the shaded parts represent A. (P\(\cap\)Q)\(\cup\)(P\(\cap\)R) B. (P\(\cup\)Q)\(\cap\)(P\(\cap\)R) C. (P\(\cup\)Q)\(\cup\)(P\(\cup\)R) D. (P\(\cap\)Q)\(\cup\)(P\(\cup\)R) |
|
| 42. |
 In the figure above, KL//NM, LN bisects < KNM. If angles KLN is 54o and angle MKN is 35o, calculate the size of angle KMN. A. 91o B. 89o C. 37o D. 19o |
|
| 43. |
 From the figure above, what is the value of p? A. 135o B. 90o C. 60o D. 45o |
|
| 44. |
 Find the value of x in the figure above A. 20\(\sqrt{3}\)cm B. 10\(\sqrt{3}\)cm C. 5\(\sqrt{3}\)cm D. 4\(\sqrt{3}\)cm |
|
| 45. |
 In the figure above, what is the equation of the line that passes the y-axis at (0,5) and passes the x-axis at (5,0)? A. y = x + 5 B. y = -x + 5 C. y = x - 5 D. y = -x - 5 Detailed Solution(x1, y1) = (0,5)(x2, y2) = (5, 0) Using \(\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}\) \(\frac{y - 5}{0 - 5} = \frac{x - 0}{5 - 0}\) \(\frac{y - 5}{-5} = \frac{x}{5}\) 5(y - 5) = -5x y - 5 = -x x + y = 5 y = -x + 5 There is an explanation video available below. |
|
| 46. |
 The pie chart above shows the monthly distribution of a man's salary on food items. If he spent N8,000 on rice, how much did he spent on yam? A. N42,000 B. N18,000 C. N16,000 D. N12,000 |
|
| 47. |
If the angle of a sector of a circle with radius 10.5 cm is 120°, find the perimeter of the sector. [Take \(\pi = \frac{22}{7}\)] A. 48 cm B. 40 cm C. 43 cm D. 45 cm Detailed SolutionPerimeter of the sector = \(2r + \frac{\theta}{360°} \times 2\pi r\)= \(2(10.5) + \frac{120}{360} \times 2 \times \frac{22}{7} \times 10.5\) = \(21 + 22\) = 43 cm There is an explanation video available below. |
| 41. |
From the venn diagram above, the shaded parts represent A. (P\(\cap\)Q)\(\cup\)(P\(\cap\)R) B. (P\(\cup\)Q)\(\cap\)(P\(\cap\)R) C. (P\(\cup\)Q)\(\cup\)(P\(\cup\)R) D. (P\(\cap\)Q)\(\cup\)(P\(\cup\)R) |
|
| 42. |
In the figure above, KL//NM, LN bisects < KNM. If angles KLN is 54o and angle MKN is 35o, calculate the size of angle KMN. A. 91o B. 89o C. 37o D. 19o |
|
| 43. |
From the figure above, what is the value of p? A. 135o B. 90o C. 60o D. 45o |
|
| 44. |
Find the value of x in the figure above A. 20\(\sqrt{3}\)cm B. 10\(\sqrt{3}\)cm C. 5\(\sqrt{3}\)cm D. 4\(\sqrt{3}\)cm |
| 45. |
In the figure above, what is the equation of the line that passes the y-axis at (0,5) and passes the x-axis at (5,0)? A. y = x + 5 B. y = -x + 5 C. y = x - 5 D. y = -x - 5 Detailed Solution(x1, y1) = (0,5)(x2, y2) = (5, 0) Using \(\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}\) \(\frac{y - 5}{0 - 5} = \frac{x - 0}{5 - 0}\) \(\frac{y - 5}{-5} = \frac{x}{5}\) 5(y - 5) = -5x y - 5 = -x x + y = 5 y = -x + 5 There is an explanation video available below. |
|
| 46. |
The pie chart above shows the monthly distribution of a man's salary on food items. If he spent N8,000 on rice, how much did he spent on yam? A. N42,000 B. N18,000 C. N16,000 D. N12,000 |
|
| 47. |
If the angle of a sector of a circle with radius 10.5 cm is 120°, find the perimeter of the sector. [Take \(\pi = \frac{22}{7}\)] A. 48 cm B. 40 cm C. 43 cm D. 45 cm Detailed SolutionPerimeter of the sector = \(2r + \frac{\theta}{360°} \times 2\pi r\)= \(2(10.5) + \frac{120}{360} \times 2 \times \frac{22}{7} \times 10.5\) = \(21 + 22\) = 43 cm There is an explanation video available below. |