Chemistry, 2008, JAMB Exam, Exam, Paper 1 | Objectives

Paper Info

Year :

2008

Title :

Chemistry

Exam :

JAMB Exam

Paper 1 | Objectives

11 - 20 of 49 Questions

#	Question	Ans
11.	\( _{11} ^{11}Na + _0^1n → _{11}^{24}Na \) The reaction above is an example of A. nuclear fission B. nuclear fusion C. artificial transmutation D. beta decay	C
12.	Air boiled out of water as steam is richer in A. nitrogen and oxygen B. carbon (IV) oxide and oxygen C. noble gases and carbon (IV) oxide D. oxygen and noble gases	B
13.	In the course of purifying water for town supply the water is passed through large settlings tanks, containing sodium aluminate (III) to remove A. large particles B. germs C. fine particles D. odour	A
14.	When a few drops of water is added to a blue anhydrous cobalt (II) chloride, the colour changes to A. white B. pink C. red D. blue	B
15.	The vulcanizer's solution is prepared by dissolving rubber in A. ethanol B. kerosine C. benzene D. petrol	C
16.	117.0g of sodium chloride was dissolved in the solubility in 1.0dm³ of distilled water at 25^oC. Determine the solubility in mol dm^-3 of sodium chloride at that temperature [Na = 23, Cl = 35.5] A. 1.0 B. 2.0 C. 3.0 D. 4.0 Show Content Detailed Solution Relative molecular mass of NaCl = 23 + 35.5 = 55.5 g/mol No. of mole of NaCl = 117/55.5 = 2.1 mol	B
17.	The uncovered raw food that is sold along major roads is likely to contain some amounts of A. Pb B. Cu C. Ag D. Na	A
18.	What is the pH of 0.001 mol dm^-3 solution of sodium hydroxide A. 14 B. 13 C. 12 D. 11 Show Content Detailed Solution [H⁺] [OH^-] = 10^-14 [H⁺] = 10^-14/[OH^-] = 10^-14/(1 * 10^-3) = 10^-11 pH = -Log₁₀[H⁺] = - Log₁₀[10^-11] = - 1 * -11 Log₁₀[10^-11] = 1 = -1 * -11 * 1 = 11	D
19.	The basicity of CH₃COOH is A. 1 B. 2 C. 3 D. 4	A
20.	0.05 mol dm^-3 HCl is neutralized by 25 cm³ NaOH. If the volume of acid used is 32.00cm³, what is the concentration of the base A. 0.016 mol dm^-3 B. 0.032 mol dm^-3 C. 0.039 mol dm^-3 D. 0.064 mol dm^-3 Show Content Detailed Solution HCl + NaOH → NaCl + H₂O CAVA = NA/NB = (0.05 * 32)/(CB * 25) ∴ CB = (0.05 * 32)/25 = 0.064 mol dm^-3	D

11.	\( _{11} ^{11}Na + _0^1n → _{11}^{24}Na \) The reaction above is an example of A. nuclear fission B. nuclear fusion C. artificial transmutation D. beta decay	C
12.	Air boiled out of water as steam is richer in A. nitrogen and oxygen B. carbon (IV) oxide and oxygen C. noble gases and carbon (IV) oxide D. oxygen and noble gases	B
13.	In the course of purifying water for town supply the water is passed through large settlings tanks, containing sodium aluminate (III) to remove A. large particles B. germs C. fine particles D. odour	A
14.	When a few drops of water is added to a blue anhydrous cobalt (II) chloride, the colour changes to A. white B. pink C. red D. blue	B
15.	The vulcanizer's solution is prepared by dissolving rubber in A. ethanol B. kerosine C. benzene D. petrol	C

16.	117.0g of sodium chloride was dissolved in the solubility in 1.0dm³ of distilled water at 25^oC. Determine the solubility in mol dm^-3 of sodium chloride at that temperature [Na = 23, Cl = 35.5] A. 1.0 B. 2.0 C. 3.0 D. 4.0 Show Content Detailed Solution Relative molecular mass of NaCl = 23 + 35.5 = 55.5 g/mol No. of mole of NaCl = 117/55.5 = 2.1 mol	B
17.	The uncovered raw food that is sold along major roads is likely to contain some amounts of A. Pb B. Cu C. Ag D. Na	A
18.	What is the pH of 0.001 mol dm^-3 solution of sodium hydroxide A. 14 B. 13 C. 12 D. 11 Show Content Detailed Solution [H⁺] [OH^-] = 10^-14 [H⁺] = 10^-14/[OH^-] = 10^-14/(1 * 10^-3) = 10^-11 pH = -Log₁₀[H⁺] = - Log₁₀[10^-11] = - 1 * -11 Log₁₀[10^-11] = 1 = -1 * -11 * 1 = 11	D
19.	The basicity of CH₃COOH is A. 1 B. 2 C. 3 D. 4	A
20.	0.05 mol dm^-3 HCl is neutralized by 25 cm³ NaOH. If the volume of acid used is 32.00cm³, what is the concentration of the base A. 0.016 mol dm^-3 B. 0.032 mol dm^-3 C. 0.039 mol dm^-3 D. 0.064 mol dm^-3 Show Content Detailed Solution HCl + NaOH → NaCl + H₂O CAVA = NA/NB = (0.05 * 32)/(CB * 25) ∴ CB = (0.05 * 32)/25 = 0.064 mol dm^-3	D