Mathematics (Core), 2003, WASSCE/WAEC MAY/JUNE, Exam, Paper 1 | Objectives

Paper Info

Year :

2003

Title :

Mathematics (Core)

Exam :

WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

41 - 46 of 46 Questions

#	Question	Ans
41.	In constructing an angle, Olu draws line OX. With centre O and a convenient radius, he draws an arc intersecting OX at P. With centre P and the same radius, he draws an arc intersecting the first arc at Q and finally joins OQ. What is the size of angle POQ so constructed? A. 90^o B. 75^o C. 60^o D. 45^o	C
42.	In the diagram /PS/ = 9 cm, /OR/ = 5cm, \(P\hat{S}R = 63^o\) and \(S\hat{P}Q = P\hat{Q}R = 90^o\). Find, correct to the nearest whole number, the area of the trapezium, A. 55cm² B. 25cm² C. 22cm² D. 13cm² Show Content Detailed Solution Considering the triangle in the diagram \(tan\theta = \frac{opp}{hyp}\\ Tan 63^{\circ} = \frac{h}{4}\\ h = 4 tan 63^{\circ}\\ Area of trapezium = \frac{1}{2}h(a+b)\\ \left(\frac{1}{2} \times 4 tan 63^{\circ}[5+9]\right)\\ =28\times 1.963 = 54.96 = 55cm^2\)	A
43.	A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h A. \(\frac{2}{3}\pi h^2\) B. \(\frac{1}{12}\pi h^3\) C. \(\frac{4}{3}\pi h^2\) D. \(\frac{4}{3}\pi h^3\) Show Content Detailed Solution Volume of a cone = \(\frac{\pi r^2 h}{3}\) r = 2h. V = \(\frac{\pi \times (2h)^2 \times h}{3}\) = \(\frac{4}{3} \pi h^3\)	D
44.	A man made a loss of 15% by selling an article for N595. Find the cost price of the article A. N600.00 B. N684.25 C. N700.00 D. N892.50 Show Content Detailed Solution 15% loss = N595 \(\implies\) (100 - 15)% of CP = N595 85% of CP = N595 CP = \(\frac{595 \times 100}{85}\) = N700.00	C
45.	The bearing of P from Q is x, where 270^o < x < 360^o. Find the bearing of Q from P A. (x - 90)^o B. (x-270)^o C. (x - 135)^o D. (x - 180)^o Show Content Detailed Solution Bearing of Q and P \(180^{\circ} – (360^{\circ}-x)\\ 180^{\circ}-360^{\circ}+x\\ -180^{\circ}+x\\ x-180^{\circ}\)	D
46.	Which of the following is not a measure of dispersion? A. Range B. Mean deviation C. Mean D. Standard deviation	C

41.	In constructing an angle, Olu draws line OX. With centre O and a convenient radius, he draws an arc intersecting OX at P. With centre P and the same radius, he draws an arc intersecting the first arc at Q and finally joins OQ. What is the size of angle POQ so constructed? A. 90^o B. 75^o C. 60^o D. 45^o	C
42.	In the diagram /PS/ = 9 cm, /OR/ = 5cm, \(P\hat{S}R = 63^o\) and \(S\hat{P}Q = P\hat{Q}R = 90^o\). Find, correct to the nearest whole number, the area of the trapezium, A. 55cm² B. 25cm² C. 22cm² D. 13cm² Show Content Detailed Solution Considering the triangle in the diagram \(tan\theta = \frac{opp}{hyp}\\ Tan 63^{\circ} = \frac{h}{4}\\ h = 4 tan 63^{\circ}\\ Area of trapezium = \frac{1}{2}h(a+b)\\ \left(\frac{1}{2} \times 4 tan 63^{\circ}[5+9]\right)\\ =28\times 1.963 = 54.96 = 55cm^2\)	A
43.	A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h A. \(\frac{2}{3}\pi h^2\) B. \(\frac{1}{12}\pi h^3\) C. \(\frac{4}{3}\pi h^2\) D. \(\frac{4}{3}\pi h^3\) Show Content Detailed Solution Volume of a cone = \(\frac{\pi r^2 h}{3}\) r = 2h. V = \(\frac{\pi \times (2h)^2 \times h}{3}\) = \(\frac{4}{3} \pi h^3\)	D

44.	A man made a loss of 15% by selling an article for N595. Find the cost price of the article A. N600.00 B. N684.25 C. N700.00 D. N892.50 Show Content Detailed Solution 15% loss = N595 \(\implies\) (100 - 15)% of CP = N595 85% of CP = N595 CP = \(\frac{595 \times 100}{85}\) = N700.00	C
45.	The bearing of P from Q is x, where 270^o < x < 360^o. Find the bearing of Q from P A. (x - 90)^o B. (x-270)^o C. (x - 135)^o D. (x - 180)^o Show Content Detailed Solution Bearing of Q and P \(180^{\circ} – (360^{\circ}-x)\\ 180^{\circ}-360^{\circ}+x\\ -180^{\circ}+x\\ x-180^{\circ}\)	D
46.	Which of the following is not a measure of dispersion? A. Range B. Mean deviation C. Mean D. Standard deviation	C