Year :
2016
Title :
Chemistry
Exam :
JAMB Exam
Paper 1 | Objectives
21 - 30 of 50 Questions
| # | Question | Ans |
|---|---|---|
| 21. |
Which of the following compounds is used as a gaseous fuel? A. CH3 -CH2 -CHO2 -COOH B. CH3 -C = CH C. CH3 -CH2 -CH2 -CH3 D. CH2 -CH2 -CH3 |
|
| 22. |
The products formed when primary Alkanols are oxidized using acidified potassium tetraoxomanganate (VII) are what? A. CH3CH2CHO and H2O B. CH3CHO and CO2 C. CH3CH2COOH and H2 D. CH3COOH and CO2 |
|
| 23. |
Alkanols have the general molecular formula A. CnH2n-2 B. CnH2n+1CHO C. CnH2n-2OH D. CnH2n+1OH |
|
| 24. |
Which of the following is not an alkali? A. Ca(OH)2 B. NH3 C. NaOH D. Al(OH)3 Detailed SolutionAl(OH)3 is not generally an alkali but is amphoteric; acting as a base and an acid when the need arises.There is an explanation video available below. |
|
| 25. |
Which of the following statements is correct about the periodic table? A. Elements in the same group have the same number of electron shells B. The non-metallic properties of the elements tend to decrease across each period C. Elements in the same period have the same number of valence electrons D. The valence electrons of the elements increase progressively across the period |
|
| 26. |
The metal whose ore can be concentrated by passing it through a magnetic separator is A. Zn B. Sn C. Cu D. Ca |
|
| 27. |
An example of an acidic oxide is A. NO B. CO C. SO2 D. CuO |
|
| 28. |
What volume of 0.5M H2SO4 will exactly neutralize 20cm3 of 0.1M NaOH Solution? A. 2.0cm 3 B. 5.0cm 3 C. 6.8cm 3 D. 8.3cm 3 Detailed SolutionThe balanced equation is given as:\(H_{2}SO_{4} + 2NaOH \to Na_{2}SO_{4} + 2H_{2}O\) Molarity of \(NaOH = 0.1M\) Volume of \(NaOH = 20cm^{3}\) Molarity of \(H_{2}SO_{4} = 0.5M\) mol NaOH = \(0.1 \times 20cm^{3} = 2molNaOH\) ⇒ \(2mol NaOH \times \frac{1mol H_{2}SO_{4}}{2mol NaOH} = 1 mol H_{2}SO_{4}\) \(volume of H_{2}SO_{4} = \frac{mole of H_{2}SO_{4}}{molarity of H_{2}SO_{4}}\) = \(\frac{1 mole}{0.5 M} = 2cm^{3} H_{2}SO_{4}\) There is an explanation video available below. |
|
| 29. |
Diamond cannot be used A. In making bicycle chains B. As abrasives C. In cutting glass and metals D. As dies for drawing wires |
|
| 30. |
Ethanol is soluble in water due to the presence of a A. Carbonyl group B. Hydroxyl group C. Phenyl group D. Methyl group |
| 21. |
Which of the following compounds is used as a gaseous fuel? A. CH3 -CH2 -CHO2 -COOH B. CH3 -C = CH C. CH3 -CH2 -CH2 -CH3 D. CH2 -CH2 -CH3 |
|
| 22. |
The products formed when primary Alkanols are oxidized using acidified potassium tetraoxomanganate (VII) are what? A. CH3CH2CHO and H2O B. CH3CHO and CO2 C. CH3CH2COOH and H2 D. CH3COOH and CO2 |
|
| 23. |
Alkanols have the general molecular formula A. CnH2n-2 B. CnH2n+1CHO C. CnH2n-2OH D. CnH2n+1OH |
|
| 24. |
Which of the following is not an alkali? A. Ca(OH)2 B. NH3 C. NaOH D. Al(OH)3 Detailed SolutionAl(OH)3 is not generally an alkali but is amphoteric; acting as a base and an acid when the need arises.There is an explanation video available below. |
|
| 25. |
Which of the following statements is correct about the periodic table? A. Elements in the same group have the same number of electron shells B. The non-metallic properties of the elements tend to decrease across each period C. Elements in the same period have the same number of valence electrons D. The valence electrons of the elements increase progressively across the period |
| 26. |
The metal whose ore can be concentrated by passing it through a magnetic separator is A. Zn B. Sn C. Cu D. Ca |
|
| 27. |
An example of an acidic oxide is A. NO B. CO C. SO2 D. CuO |
|
| 28. |
What volume of 0.5M H2SO4 will exactly neutralize 20cm3 of 0.1M NaOH Solution? A. 2.0cm 3 B. 5.0cm 3 C. 6.8cm 3 D. 8.3cm 3 Detailed SolutionThe balanced equation is given as:\(H_{2}SO_{4} + 2NaOH \to Na_{2}SO_{4} + 2H_{2}O\) Molarity of \(NaOH = 0.1M\) Volume of \(NaOH = 20cm^{3}\) Molarity of \(H_{2}SO_{4} = 0.5M\) mol NaOH = \(0.1 \times 20cm^{3} = 2molNaOH\) ⇒ \(2mol NaOH \times \frac{1mol H_{2}SO_{4}}{2mol NaOH} = 1 mol H_{2}SO_{4}\) \(volume of H_{2}SO_{4} = \frac{mole of H_{2}SO_{4}}{molarity of H_{2}SO_{4}}\) = \(\frac{1 mole}{0.5 M} = 2cm^{3} H_{2}SO_{4}\) There is an explanation video available below. |
|
| 29. |
Diamond cannot be used A. In making bicycle chains B. As abrasives C. In cutting glass and metals D. As dies for drawing wires |
|
| 30. |
Ethanol is soluble in water due to the presence of a A. Carbonyl group B. Hydroxyl group C. Phenyl group D. Methyl group |