Year : 
2010
Title : 
Mathematics (Core)
Exam : 
JAMB Exam

Paper 1 | Objectives

11 - 20 of 49 Questions

# Question Ans
11.

From the cyclic quadrilateral TUVW above, find the value of x

A. 26o

B. 24o

C. 20o

D. 23o

Detailed Solution

TUVW is a cyclic quad
3χ + 20 + 88 = 180 (opp ∠ s of a cyclic quad are supplementary)
3χ + 108 = 180
3χ = 180 - 108
3χ = 72
χ = 72/3
χ = 24o
There is an explanation video available below.
12.

If two smaller sides of a right angled triangle are 4cm and 5cm, find its area

A. 10 cm2

B. 6 cm2

C. 24 cm2

D. 8 cm2

Detailed Solution

Area of a triangle = 1/2 base x height
= 1/2 x 4 x 5
= 10 cm2
There is an explanation video available below.
13.

An arc subtends an angle of 50o at the center of circle of radius 6cm. Calculate the area of the sector formed

A. 100/7

B. 80/7

C. 110/7

D. 90/7

Detailed Solution


= 50/360 x 22/7 x 36/1
= 110/7
There is an explanation video available below.
14.

What is the locus of point that is equidistant from points P(1,3) and Q(3,5)?

A. y = -χ + 6

B. y = -χ - 6

C. y = χ + 6

D. y = χ - 6

Detailed Solution

Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1
Gradient bisector = -1
Equation of perpendicular bisector
y - y1 = m(χ - χ1
y - 4 = -χ + 2
y = -χ + 6
There is an explanation video available below.
15.

If the area of ΔPQR above is 12√3 cm2, find the value of q?

A. 6 cm

B. 7 cm

C. 8 cm

D. 5 cm

Detailed Solution

Area of a triangle = 1/2 ab Sinθ
12√3 = 1/2 x 8 x q sin 60
12√3 = 4 x q x √3/2
12√3 = 2q√3

q = 6
There is an explanation video available below.
16.

If y = (2x + 1)3 find dy/dx

A. 3(2x+1)2

B. 6(2x+1)

C. 3(2x+1)

D. 6(2x+1)2

Detailed Solution

y = (2x + 1)3
dy/dx = 3(2x + 1)3-1 x 2
= 3(2x + 1)2 x 2
= 6(2x + 1)2
There is an explanation video available below.
17.

Find ∫(sin x + 2)dx

A. cos x + x2 + K

B. cos x 2x + K

C. -cos x + x2 + K

D. -cos x + 2x + K

Detailed Solution

∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K
There is an explanation video available below.
18.

Table:

from the table above, if the pass mark is 5, how many students failed the test?

A. 6

B. 2

C. 7

D. 9

Detailed Solution

There is an explanation video available below.
19.

Table:

The table above show the marks obtained in a given test.
How many student took the test?

A. 16

B. 13

C. 20

D. 15

Detailed Solution

∑f = 2 + 2 + 8 + 4 + 4
= 20
There is an explanation video available below.
20.

Table:

The table above show the marks obtained in a given test.
Find the mean mark

A. 3.1

B. 3.0

C. 3.2

D. 3.3

Detailed Solution



\(Mean = \frac{\sum fx}{\sum f}\)
= \(\frac{66}{20}\)
= 3.3

There is an explanation video available below.
11.

From the cyclic quadrilateral TUVW above, find the value of x

A. 26o

B. 24o

C. 20o

D. 23o

Detailed Solution

TUVW is a cyclic quad
3χ + 20 + 88 = 180 (opp ∠ s of a cyclic quad are supplementary)
3χ + 108 = 180
3χ = 180 - 108
3χ = 72
χ = 72/3
χ = 24o
There is an explanation video available below.
12.

If two smaller sides of a right angled triangle are 4cm and 5cm, find its area

A. 10 cm2

B. 6 cm2

C. 24 cm2

D. 8 cm2

Detailed Solution

Area of a triangle = 1/2 base x height
= 1/2 x 4 x 5
= 10 cm2
There is an explanation video available below.
13.

An arc subtends an angle of 50o at the center of circle of radius 6cm. Calculate the area of the sector formed

A. 100/7

B. 80/7

C. 110/7

D. 90/7

Detailed Solution


= 50/360 x 22/7 x 36/1
= 110/7
There is an explanation video available below.
14.

What is the locus of point that is equidistant from points P(1,3) and Q(3,5)?

A. y = -χ + 6

B. y = -χ - 6

C. y = χ + 6

D. y = χ - 6

Detailed Solution

Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1
Gradient bisector = -1
Equation of perpendicular bisector
y - y1 = m(χ - χ1
y - 4 = -χ + 2
y = -χ + 6
There is an explanation video available below.
15.

If the area of ΔPQR above is 12√3 cm2, find the value of q?

A. 6 cm

B. 7 cm

C. 8 cm

D. 5 cm

Detailed Solution

Area of a triangle = 1/2 ab Sinθ
12√3 = 1/2 x 8 x q sin 60
12√3 = 4 x q x √3/2
12√3 = 2q√3

q = 6
There is an explanation video available below.
16.

If y = (2x + 1)3 find dy/dx

A. 3(2x+1)2

B. 6(2x+1)

C. 3(2x+1)

D. 6(2x+1)2

Detailed Solution

y = (2x + 1)3
dy/dx = 3(2x + 1)3-1 x 2
= 3(2x + 1)2 x 2
= 6(2x + 1)2
There is an explanation video available below.
17.

Find ∫(sin x + 2)dx

A. cos x + x2 + K

B. cos x 2x + K

C. -cos x + x2 + K

D. -cos x + 2x + K

Detailed Solution

∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K
There is an explanation video available below.
18.

Table:

from the table above, if the pass mark is 5, how many students failed the test?

A. 6

B. 2

C. 7

D. 9

Detailed Solution

There is an explanation video available below.
19.

Table:

The table above show the marks obtained in a given test.
How many student took the test?

A. 16

B. 13

C. 20

D. 15

Detailed Solution

∑f = 2 + 2 + 8 + 4 + 4
= 20
There is an explanation video available below.
20.

Table:

The table above show the marks obtained in a given test.
Find the mean mark

A. 3.1

B. 3.0

C. 3.2

D. 3.3

Detailed Solution



\(Mean = \frac{\sum fx}{\sum f}\)
= \(\frac{66}{20}\)
= 3.3

There is an explanation video available below.