Year : 
2013
Title : 
Chemistry
Exam : 
JAMB Exam

Paper 1 | Objectives

41 - 44 of 44 Questions

# Question Ans
41.

How many unpaired electron are in the p-orbitals of a fluorine atom?

A. 3

B. \( 0 \)

C. 1

D. 2

Detailed Solution

There is an explanation video available below.
42.

The radioactive emission with the least ionization power is

A. \( \alpha - particles \)

B. X-rays

C. \( \gamma -rays \)

D. \( \beta - rays \)

Detailed Solution

There is an explanation video available below.
43.

Zn(s) + CuSO4(aq) \( \to \) ZnSO4(aq) + Cu(s)

In the reaction above, the oxidizing agent is

A. CuSO4(aq)

B. ZnSO4(aq)

C. Cu(s)

D. Zn(s)

Detailed Solution

There is an explanation video available below.
44.

2SO2(g) + O2(g) \( \iff \)2SO3(g)

\( \bigtriangleup H = -395.7kJmol^{-1} \)

In the reaction above, the concentration of 2SO3(g) can be in creased by

A. decreasing the pressure

B. decreasing the temperature

C. the addition of catalyst

D. increasing the temperature

Detailed Solution

There is an explanation video available below.
41.

How many unpaired electron are in the p-orbitals of a fluorine atom?

A. 3

B. \( 0 \)

C. 1

D. 2

Detailed Solution

There is an explanation video available below.
42.

The radioactive emission with the least ionization power is

A. \( \alpha - particles \)

B. X-rays

C. \( \gamma -rays \)

D. \( \beta - rays \)

Detailed Solution

There is an explanation video available below.
43.

Zn(s) + CuSO4(aq) \( \to \) ZnSO4(aq) + Cu(s)

In the reaction above, the oxidizing agent is

A. CuSO4(aq)

B. ZnSO4(aq)

C. Cu(s)

D. Zn(s)

Detailed Solution

There is an explanation video available below.
44.

2SO2(g) + O2(g) \( \iff \)2SO3(g)

\( \bigtriangleup H = -395.7kJmol^{-1} \)

In the reaction above, the concentration of 2SO3(g) can be in creased by

A. decreasing the pressure

B. decreasing the temperature

C. the addition of catalyst

D. increasing the temperature

Detailed Solution

There is an explanation video available below.