51 - 60 of 80 Questions
# | Question | Ans |
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51. |
What volume of 0.100M sodium trioxonitrate (V) solution contains 5g of solute. A. 1.7 litres B. 0.420 litres C. 0.588 litres D. 2.35 litres |
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52. |
The two ions responsible for hardness in water are A. Ca\(^{2+}\) and / or Mg\(^{2+}\) B. K\(^+\) and / or Mg\(^{2+}\) C. Ca\(^{2+}\) and / or Li\(^+\) D. Ca\(^{2+}\) and / or Na\(^+\) |
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53. |
Which of the following could not be alkane? A. C\(_4\)H\(_{10}\) B. C\(_5\)H\(_{12}\) C. C\(_7\)H\(_{14}\) D. C\(_8\)H\(_{18}\) |
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54. |
The electronic configuration of element Z is 1s\(^2\) 2s\(^2\) 2p\(^6\) 3s\(^2\) 3p\(^1\). What is the formula of the compound formed between Z and tetraoxosulphate (VI) ion. A. Z\(_3\)(SO\(_4\))\(_2\) B. ZSO\(_4\) C. Z\(_2\) SO\(_4\) D. Z\(_2\)(SO\(_4\))\(_3\) Detailed SolutionZ = 1s\(^2\) 2s\(^2\) 2p\(^6\) 3s\(^2\) 3p\(^1\)\(\therefore\) We have Z\(^{3+}\) and SO\(_4 ^{2-}\) The reaction : Z\(^{3+}\) + SO\(_4 ^{2-}\) \(\to\) Z\(_2\)(SO\(_4\))\(_3\). There is an explanation video available below. |
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55. |
The hybridization in the compound \(CH_3 - CH_2 - C \equiv H\) is A. sp\(^3\) and sp B. sp C. sp\(^2\) D. sp\(^3\) and sp\(^2\) Detailed SolutionThe hybridization in a and b is sp\(^3\) hybridization while in c and d is sp hybridization. There is an explanation video available below. |
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56. |
The following are isoelectronic ions except A. Na\(^+\) B. Mg\(^{2+}\) C. Si\(^{2+}\) D. O\(^{2+}\) Detailed SolutionTwo or more ions are said to be isoelectronic if they have the same electronic structure and the same number of valence electrons.Na\(^+\) = 10 electrons = 2, 8 Mg\(^{2+}\) = 10 electrons = 2,8 O\(^{2-}\) = 10 electrons = 2,8 Si\(^{2+}\) = 12 electrons = 2,8,2 \(\implies\) Si\(^{2+}\) is not isoelectronic with the rest. There is an explanation video available below. |
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57. |
Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons \) 2C + D\(_{(g)}\) (\(\Delta\)H = +ve)What will be the effect of decrease in temperature on the reaction? A. Rate of backward reaction will increase B. The equilibrium constant will shift C. Rates of forward and backward reactions are not affected D. Rate of forward reaction will increase Detailed SolutionThe given reaction is endothermic, hence, a decrease in temperature will favor the exothermic side which is the backward reaction.There is an explanation video available below. |
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58. |
A cell shorthand notation can be written as A / A\(^+\) // B\(^{2+}\) /B. The double slash in the notation represents the A. electrolyte B. electrodes C. salt bridge D. solid - liquid interface |
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59. |
The shapes of water, ammonia, carbon (iv) oxide and methane are respectively A. linear, tetrahedral, angular and pyramidal B. angular, pyramidal, linear and tetrahedral C. pyramidal, linear, tetrahedral and angular D. tetrahedral, angular, pyramidal and linear |
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60. |
Which quantum divides shells into orbitals? A. Spin B. Principal C. Azimuthal D. Magnetic Detailed SolutionThe azimuthal quantum number determines an atom's orbital angular momentum and the shape of the orbital. The principal quantum number determines its number of shells. Magnetic quantum number determines how many orbitals there are as well as their orientation within a subshell.There is an explanation video available below. |
51. |
What volume of 0.100M sodium trioxonitrate (V) solution contains 5g of solute. A. 1.7 litres B. 0.420 litres C. 0.588 litres D. 2.35 litres |
|
52. |
The two ions responsible for hardness in water are A. Ca\(^{2+}\) and / or Mg\(^{2+}\) B. K\(^+\) and / or Mg\(^{2+}\) C. Ca\(^{2+}\) and / or Li\(^+\) D. Ca\(^{2+}\) and / or Na\(^+\) |
|
53. |
Which of the following could not be alkane? A. C\(_4\)H\(_{10}\) B. C\(_5\)H\(_{12}\) C. C\(_7\)H\(_{14}\) D. C\(_8\)H\(_{18}\) |
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54. |
The electronic configuration of element Z is 1s\(^2\) 2s\(^2\) 2p\(^6\) 3s\(^2\) 3p\(^1\). What is the formula of the compound formed between Z and tetraoxosulphate (VI) ion. A. Z\(_3\)(SO\(_4\))\(_2\) B. ZSO\(_4\) C. Z\(_2\) SO\(_4\) D. Z\(_2\)(SO\(_4\))\(_3\) Detailed SolutionZ = 1s\(^2\) 2s\(^2\) 2p\(^6\) 3s\(^2\) 3p\(^1\)\(\therefore\) We have Z\(^{3+}\) and SO\(_4 ^{2-}\) The reaction : Z\(^{3+}\) + SO\(_4 ^{2-}\) \(\to\) Z\(_2\)(SO\(_4\))\(_3\). There is an explanation video available below. |
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55. |
The hybridization in the compound \(CH_3 - CH_2 - C \equiv H\) is A. sp\(^3\) and sp B. sp C. sp\(^2\) D. sp\(^3\) and sp\(^2\) Detailed SolutionThe hybridization in a and b is sp\(^3\) hybridization while in c and d is sp hybridization. There is an explanation video available below. |
56. |
The following are isoelectronic ions except A. Na\(^+\) B. Mg\(^{2+}\) C. Si\(^{2+}\) D. O\(^{2+}\) Detailed SolutionTwo or more ions are said to be isoelectronic if they have the same electronic structure and the same number of valence electrons.Na\(^+\) = 10 electrons = 2, 8 Mg\(^{2+}\) = 10 electrons = 2,8 O\(^{2-}\) = 10 electrons = 2,8 Si\(^{2+}\) = 12 electrons = 2,8,2 \(\implies\) Si\(^{2+}\) is not isoelectronic with the rest. There is an explanation video available below. |
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57. |
Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons \) 2C + D\(_{(g)}\) (\(\Delta\)H = +ve)What will be the effect of decrease in temperature on the reaction? A. Rate of backward reaction will increase B. The equilibrium constant will shift C. Rates of forward and backward reactions are not affected D. Rate of forward reaction will increase Detailed SolutionThe given reaction is endothermic, hence, a decrease in temperature will favor the exothermic side which is the backward reaction.There is an explanation video available below. |
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58. |
A cell shorthand notation can be written as A / A\(^+\) // B\(^{2+}\) /B. The double slash in the notation represents the A. electrolyte B. electrodes C. salt bridge D. solid - liquid interface |
|
59. |
The shapes of water, ammonia, carbon (iv) oxide and methane are respectively A. linear, tetrahedral, angular and pyramidal B. angular, pyramidal, linear and tetrahedral C. pyramidal, linear, tetrahedral and angular D. tetrahedral, angular, pyramidal and linear |
|
60. |
Which quantum divides shells into orbitals? A. Spin B. Principal C. Azimuthal D. Magnetic Detailed SolutionThe azimuthal quantum number determines an atom's orbital angular momentum and the shape of the orbital. The principal quantum number determines its number of shells. Magnetic quantum number determines how many orbitals there are as well as their orientation within a subshell.There is an explanation video available below. |