Mathematics (Core), 2004, JAMB Exam, Exam, Paper 1 | Objectives

Paper Info

Year :

2004

Title :

Mathematics (Core)

Exam :

JAMB Exam

Paper 1 | Objectives

41 - 45 of 45 Questions

#	Question	Ans
41.	A farmer planted 5000 grains of maize and harvested 5000 cobs, each bearing 500 grains. What is the ratio of the number of grains sowed to the number harvested? A. 1 : 250 000 B. 1 : 25 000 C. 1 : 500 D. 1 : 5 000 Show Content Detailed Solution 5000 : 5000 * 500 5000 : 2500000 5 : 2500 1 : 500	C
42.	The shadow of a pole 5√3m high is 5m. Find the angle of elevation of the sun. A. 45^o B. 75^o C. 30^o D. 60^o Show Content Detailed Solution Tan θ = ^5√3/₅ Tan θ = √3 θ = 60^o	D
43.	The shaded area in the diagram above is represented by A. {(x,y) : y - 3x < -6} B. {(x,y) : y + 3x < 6} C. {(x,y) : y + 3x < -6} D. {(x,y) : y - 3x < 6} Show Content Detailed Solution Coordinates of the line are (x₁ y₁)(0,2) respectively and (x₂ y₂)(2,0) respectively Gradient (m) of the line = (y₂ - y₁) / (x₂ - x₁) = (0-6) / (2-0) = ^-6/₂ = -3 Equation of the line y-y₁ = m(x-x₁) y - 6 = -3(x - 0) y - 6 = -3x y + 3x	B
44.	PQRSTV is a regular polygon of side 7 cm inscribed in a circle. Find the circumference of the circle PQRSTV. A. 56 cm B. 22 cm C. 42 cm D. 44 cm Show Content Detailed Solution	D
45.	The graph above shows the cumulative frequency curve of the distribution of marks in a class test. What percentage of the students scored more than 20 marks? A. 68% B. 28% C. 17% D. 8% Show Content Detailed Solution \(\begin{array}{c\|c} \text{class-marks(x)} & \text{(freq. (f)} & \text{cum. freq.}\\\hline 9 & &3.....3\\14 & & 6....3 + 6 = 9\\ 19 & & 9.....9 + 9 = 18\\ 24 & & 3.....18 + 3 = 21\\ 29 & & 2.....21 + 2 = 23\\ 34 & & 2.....23 + 2 = 25\\ & & 25\end{array}\) % of students scoring more than 20 marks = \(\frac{7}{25}\) x 100% = 28%	B

41.	A farmer planted 5000 grains of maize and harvested 5000 cobs, each bearing 500 grains. What is the ratio of the number of grains sowed to the number harvested? A. 1 : 250 000 B. 1 : 25 000 C. 1 : 500 D. 1 : 5 000 Show Content Detailed Solution 5000 : 5000 * 500 5000 : 2500000 5 : 2500 1 : 500	C
42.	The shadow of a pole 5√3m high is 5m. Find the angle of elevation of the sun. A. 45^o B. 75^o C. 30^o D. 60^o Show Content Detailed Solution Tan θ = ^5√3/₅ Tan θ = √3 θ = 60^o	D
43.	The shaded area in the diagram above is represented by A. {(x,y) : y - 3x < -6} B. {(x,y) : y + 3x < 6} C. {(x,y) : y + 3x < -6} D. {(x,y) : y - 3x < 6} Show Content Detailed Solution Coordinates of the line are (x₁ y₁)(0,2) respectively and (x₂ y₂)(2,0) respectively Gradient (m) of the line = (y₂ - y₁) / (x₂ - x₁) = (0-6) / (2-0) = ^-6/₂ = -3 Equation of the line y-y₁ = m(x-x₁) y - 6 = -3(x - 0) y - 6 = -3x y + 3x	B

44.	PQRSTV is a regular polygon of side 7 cm inscribed in a circle. Find the circumference of the circle PQRSTV. A. 56 cm B. 22 cm C. 42 cm D. 44 cm Show Content Detailed Solution	D
45.	The graph above shows the cumulative frequency curve of the distribution of marks in a class test. What percentage of the students scored more than 20 marks? A. 68% B. 28% C. 17% D. 8% Show Content Detailed Solution \(\begin{array}{c\|c} \text{class-marks(x)} & \text{(freq. (f)} & \text{cum. freq.}\\\hline 9 & &3.....3\\14 & & 6....3 + 6 = 9\\ 19 & & 9.....9 + 9 = 18\\ 24 & & 3.....18 + 3 = 21\\ 29 & & 2.....21 + 2 = 23\\ 34 & & 2.....23 + 2 = 25\\ & & 25\end{array}\) % of students scoring more than 20 marks = \(\frac{7}{25}\) x 100% = 28%	B