Mathematics (Core), 1995, JAMB Exam, Exam, Paper 1 | Objectives

Paper Info

Year :

1995

Title :

Mathematics (Core)

Exam :

JAMB Exam

Paper 1 | Objectives

41 - 46 of 46 Questions

#	Question	Ans
41.	Use the graph of the curve y = f(x)to solve the inequality f(x) \(\leq\) 0 A. -1 \(\geq\) x \(\geq\) 1, x \(\geq\) 2 B. x \(\leq\) -1, 1 \(\geq\) x \(\geq\) 2 C. x \(\geq\) -1, 1 \(\geq\) x \(\geq\) 2 D. x \(\geq\) 2, -1 \(\geq\) x \(\geq\) 1 Show Content Detailed Solution -1 \(\geq\) x \(\geq\) 1, 1 < x \(\geq\) 2 Combining solutions = x \(\leq\) 1; 1 \(\geq\) x \(\geq\) 2	B
42.	Determine the value of x in the figure A. 134^o B. 81^o C. 53^o D. 46^o Show Content Detailed Solution Within the triangle, 180° - (81° + 53°) = 46° In a cyclic quadrilateral, the sum of two opposite angles = 180° \(\therefore\) x = 180° - 46° = 134°	A
43.	PT is a tangent to the circle TYZX. YT = YX and < PTX = 50^o. Calculate < TZY A. 50^o B. 65^o C. 85^o D. 130^o Show Content Detailed Solution XTY = 50^o = TXY = \(\frac{130^o}{2}\) = 65^o	B
44.	In the diagram, the base diameter is 14cm while the height is 12cm. Calculate the total surface area if the cylinder has both a base and a top.[\(\pi \frac{22}{7}\)] A. 836cm² B. 308cm² C. 528cm² D. 154cm² Show Content Detailed Solution Area(S) = 2\(\pi r^2 + 2 \pi rh = 2\pi r(h + r)\) D = 14cm, 2r = D r = \(\frac{D}{2}\) = 7cm S = 2 x \(\frac{22}{7} \times [7 + 12] = 44 \times 19\) = 836cm²	A
45.	In the diagram, find PQ if the area of triangle PQR is 35cm\(^2\) A. 7cm B. 10cm C. 14cm D. 17cm Show Content Detailed Solution PQ x 10 sin 30 = 35 PQ = \(\frac{35}{10 \sin 30}\) = 7cm	A
46.	The mean and the range of the set of numbers 1, 20, 1.00, 0.90, 1.40, 0.80, 1.20 and 1.10 are me and r A. 1.11 B. 1.65 C. 1.85 D. 2.45 Show Content Detailed Solution m = 1.05, r = 0.6 m + r = 1.05 + 0.5 = 1.65	B

41.	Use the graph of the curve y = f(x)to solve the inequality f(x) \(\leq\) 0 A. -1 \(\geq\) x \(\geq\) 1, x \(\geq\) 2 B. x \(\leq\) -1, 1 \(\geq\) x \(\geq\) 2 C. x \(\geq\) -1, 1 \(\geq\) x \(\geq\) 2 D. x \(\geq\) 2, -1 \(\geq\) x \(\geq\) 1 Show Content Detailed Solution -1 \(\geq\) x \(\geq\) 1, 1 < x \(\geq\) 2 Combining solutions = x \(\leq\) 1; 1 \(\geq\) x \(\geq\) 2	B
42.	Determine the value of x in the figure A. 134^o B. 81^o C. 53^o D. 46^o Show Content Detailed Solution Within the triangle, 180° - (81° + 53°) = 46° In a cyclic quadrilateral, the sum of two opposite angles = 180° \(\therefore\) x = 180° - 46° = 134°	A
43.	PT is a tangent to the circle TYZX. YT = YX and < PTX = 50^o. Calculate < TZY A. 50^o B. 65^o C. 85^o D. 130^o Show Content Detailed Solution XTY = 50^o = TXY = \(\frac{130^o}{2}\) = 65^o	B

44.	In the diagram, the base diameter is 14cm while the height is 12cm. Calculate the total surface area if the cylinder has both a base and a top.[\(\pi \frac{22}{7}\)] A. 836cm² B. 308cm² C. 528cm² D. 154cm² Show Content Detailed Solution Area(S) = 2\(\pi r^2 + 2 \pi rh = 2\pi r(h + r)\) D = 14cm, 2r = D r = \(\frac{D}{2}\) = 7cm S = 2 x \(\frac{22}{7} \times [7 + 12] = 44 \times 19\) = 836cm²	A
45.	In the diagram, find PQ if the area of triangle PQR is 35cm\(^2\) A. 7cm B. 10cm C. 14cm D. 17cm Show Content Detailed Solution PQ x 10 sin 30 = 35 PQ = \(\frac{35}{10 \sin 30}\) = 7cm	A
46.	The mean and the range of the set of numbers 1, 20, 1.00, 0.90, 1.40, 0.80, 1.20 and 1.10 are me and r A. 1.11 B. 1.65 C. 1.85 D. 2.45 Show Content Detailed Solution m = 1.05, r = 0.6 m + r = 1.05 + 0.5 = 1.65	B