Mathematics (Core), 2012, WASSCE/WAEC MAY/JUNE, Exam, Paper 1 | Objectives

Paper Info

Year :

2012

Title :

Mathematics (Core)

Exam :

WASSCE/WAEC MAY/JUNE

Paper 1 | Objectives

31 - 40 of 49 Questions

#	Question	Ans
31.	Factorise completely: 32x²y - 48x³y³ A. 16x²y(2 - 3xy²) B. 8xy(4x - 6x²y²) C. 8x²y(4 - 6xy²) D. 16xy(2x - 3x²y²)	A
32.	If x and y are variables and k is a constant, which of the following describes an inverse relationship between x and y? A. y = kx B. y = \(\frac{k}{x}\) C. y = k\(\sqrt{x}\) D. y = x + k	B
33.	If x and y are variables and k is a constant, which of the following describes an inverse relationship between x and y? A. y = kx B. y = \(\frac{k}{x}\) C. y = k\(\sqrt{x}\) D. y = x + k	B
34.	In the diagram, \|QR\| = 10m, \|SR\| = 8m < QPS = 30^o, < QRP = 90^o and \|PS\| = x, Find x A. 1.32m B. 6.32m C. 9.32m D. 17.32 Show Content Detailed Solution In right angled \(\bigtriangleup\)QPR tan 30^o = \(\frac{10}{x + 8}\) (x + 8) tan 30 = 10 x + 8 = \(\frac{10}{0.5773}\) x +8 = 17.3 x = 17.3 - 8 x = 9.32	C
35.	In the diagram, O is a circle centre of the circle PQRS and < PSR = 86^o. If < PQR = x^o, find x A. 108^o B. 172^o C. 130^o D. 50^o Show Content Detailed Solution x^o = 86 x 2(angle at centre = 2 x angle at circumference) = 172^o	B
36.	The diagram is a circle centre O. If < SPR = 2m and < SQR = n, express m in terms of n A. m = \(\frac{n}{2}\) B. m = 2n C. m = n - 2 D. m = n + 2 Show Content Detailed Solution If < SPR = 2m then < SQR = 2m but < AQR was n n = 2m m = \(\frac{n}{2}\)	A
37.	In the diagram, MQ//RS, < TUV = 70^o and < RLV = 30^o. Find the value of x A. 150^o B. 110^o C. 100^o D. 95^o Show Content Detailed Solution L + 30^o - 180^o(Sum of < s on straight line) L = 180^o - 30^o = 150^o L = q = 150^o(opposite < s are equal) y = b = 30^o(alt. < s) b + c = 180^o(sum of < s on str. line) 30^o + c 180 c = 180 - 30 c = 150^o b = a = 30^o (opp < s are equal) c = d = 150^o (opp < s are equal)	C
38.	Is the diagram, MN, PQ and RS are three intersecting straight lines. Which of the following statements is/are true? i. t = y ii. x + y + z + m = 180^o ii. x + m + n = 180^o iv. x + n = m + z A. i and iv B. ii C. iii D. iv Show Content Detailed Solution m + y + x = 180^o(sum of < s on straight line) y = n(vertically opp. angle) m + n + x = 180^o	C
39.	The position of three ships P,Q and R at sea are illustrated in the diagram. The arrows indicated the North direction. The bearing of Q from P is 050^o and < PQR = 72^o. Calculate the bearing of R and Q A. 155^o B. 80^o C. 158^o D. 91^o Show Content Detailed Solution < NPQ = < PQB = 50^o(alt. < s) < PQB = 50^o < PQR = < PQR < PQB + < QBR = 72^o < QBR = < PQR - < PQB = 72^o - 50^o = 22^o < NQR = 180 - < QBR = 180^o - 22 = 158^o, the bearing of R from Q = 158^o	C
40.	The bar chart shows the frequency distribution of marks scored by students in a class test. How many students are in the class? A. 10 B. 24 C. 25 D. 30 Show Content Detailed Solution 6 + 8 + 6 + 5 = 25	C

31.	Factorise completely: 32x²y - 48x³y³ A. 16x²y(2 - 3xy²) B. 8xy(4x - 6x²y²) C. 8x²y(4 - 6xy²) D. 16xy(2x - 3x²y²)	A
32.	If x and y are variables and k is a constant, which of the following describes an inverse relationship between x and y? A. y = kx B. y = \(\frac{k}{x}\) C. y = k\(\sqrt{x}\) D. y = x + k	B
33.	If x and y are variables and k is a constant, which of the following describes an inverse relationship between x and y? A. y = kx B. y = \(\frac{k}{x}\) C. y = k\(\sqrt{x}\) D. y = x + k	B
34.	In the diagram, \|QR\| = 10m, \|SR\| = 8m < QPS = 30^o, < QRP = 90^o and \|PS\| = x, Find x A. 1.32m B. 6.32m C. 9.32m D. 17.32 Show Content Detailed Solution In right angled \(\bigtriangleup\)QPR tan 30^o = \(\frac{10}{x + 8}\) (x + 8) tan 30 = 10 x + 8 = \(\frac{10}{0.5773}\) x +8 = 17.3 x = 17.3 - 8 x = 9.32	C
35.	In the diagram, O is a circle centre of the circle PQRS and < PSR = 86^o. If < PQR = x^o, find x A. 108^o B. 172^o C. 130^o D. 50^o Show Content Detailed Solution x^o = 86 x 2(angle at centre = 2 x angle at circumference) = 172^o	B

36.	The diagram is a circle centre O. If < SPR = 2m and < SQR = n, express m in terms of n A. m = \(\frac{n}{2}\) B. m = 2n C. m = n - 2 D. m = n + 2 Show Content Detailed Solution If < SPR = 2m then < SQR = 2m but < AQR was n n = 2m m = \(\frac{n}{2}\)	A
37.	In the diagram, MQ//RS, < TUV = 70^o and < RLV = 30^o. Find the value of x A. 150^o B. 110^o C. 100^o D. 95^o Show Content Detailed Solution L + 30^o - 180^o(Sum of < s on straight line) L = 180^o - 30^o = 150^o L = q = 150^o(opposite < s are equal) y = b = 30^o(alt. < s) b + c = 180^o(sum of < s on str. line) 30^o + c 180 c = 180 - 30 c = 150^o b = a = 30^o (opp < s are equal) c = d = 150^o (opp < s are equal)	C
38.	Is the diagram, MN, PQ and RS are three intersecting straight lines. Which of the following statements is/are true? i. t = y ii. x + y + z + m = 180^o ii. x + m + n = 180^o iv. x + n = m + z A. i and iv B. ii C. iii D. iv Show Content Detailed Solution m + y + x = 180^o(sum of < s on straight line) y = n(vertically opp. angle) m + n + x = 180^o	C
39.	The position of three ships P,Q and R at sea are illustrated in the diagram. The arrows indicated the North direction. The bearing of Q from P is 050^o and < PQR = 72^o. Calculate the bearing of R and Q A. 155^o B. 80^o C. 158^o D. 91^o Show Content Detailed Solution < NPQ = < PQB = 50^o(alt. < s) < PQB = 50^o < PQR = < PQR < PQB + < QBR = 72^o < QBR = < PQR - < PQB = 72^o - 50^o = 22^o < NQR = 180 - < QBR = 180^o - 22 = 158^o, the bearing of R from Q = 158^o	C
40.	The bar chart shows the frequency distribution of marks scored by students in a class test. How many students are in the class? A. 10 B. 24 C. 25 D. 30 Show Content Detailed Solution 6 + 8 + 6 + 5 = 25	C